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Trigonometric limits practice problems

Limits built on sin(u)/u → 1 and (1 − cos u)/u → 0. 69 problems with worked solutions; in 67 of them every equation is proved by a computer algebra system.

20 worked problems

Try each one before opening the solution. Every line is labeled with what checked it; 20 of these also have a second solution, written separately and checked the same way. How we verify

Problem 1.155

medium Video
Evaluate \( \displaystyle \lim_{x \to - \frac{1}{2}} \frac{\sin^{2}{\left(2 x + 1 \right)}}{\left(2 x + 1\right)^{2}} \).
  1. \[ \lim_{x \to - \frac{1}{2}^+}\left(\frac{\sin^{2}{\left(2 x + 1 \right)}}{\left(2 x + 1\right)^{2}}\right) \]
    limit algebraStart with the original limit. Apply the power rule for quotients.✓ Proved
  2. \[ = \lim_{u \to 0^+}\left(\frac{\sin^{2}{\left(u \right)}}{u^{2}}\right) \]
    substitution algebraSubstitute u = 2*x + 1, which implies u -> 0 as x -> -1/2. Distribute the square to the numerator and denominator.✓ Proved
  3. \[ = \lim_{u \to 0^+}\left(\frac{\frac{d}{d u} \sin^{2}{\left(u \right)}}{\frac{d}{d u} u^{2}}\right) \]
    lhopitalApply L'Hopital's rule because the limit is an indeterminate form 0/0.✓ Proved
  4. \[ = \lim_{u \to 0^+}\left(\frac{\sin{\left(u \right)} \cos{\left(u \right)}}{u}\right) \]
    simplify simplify algebraCompute the derivatives. Cancel the common factor of 2. Split the expression into a product.✓ Proved
  5. \[ = \lim_{u \to 0^+}\left(\frac{\sin{\left(u \right)}}{u}\right) \lim_{u \to 0^+} \cos{\left(u \right)} \]
    limit-lawApply the product rule for limits.✓ Proved
  6. \[ = 1 \]
    limit simplify simplifyEvaluate the first limit component. Evaluate the second limit component. Final result.✓ Proved
Answer \( 1 \)
The graph of f(x) = sin(2x + 1)²/(2x + 1)². Two points slide along the curve toward x = -1/2, one from each side; their heights close in on 1.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to - \frac{1}{2}^+}\left(\frac{\sin^{2}{\left(2 x + 1 \right)}}{\left(2 x + 1\right)^{2}}\right) \]
    limit rewriteRewrite the fraction as a square of sin over its argument.✓ Proved
  2. \[ = \left(\lim_{x \to - \frac{1}{2}^+}\left(\frac{\sin{\left(2 x + 1 \right)}}{2 x + 1}\right)\right)^{2} \]
    limit-lawApply the limit law to the inner fraction.✓ Proved
  3. \[ = 1 \]
    limit simplifySince sin(u)/u -> 1 as u -> 0. The limit evaluates to 1.✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.498

medium Video
Evaluate \( \displaystyle \lim_{x \to \frac{1}{2}} \frac{1 - \cos{\left(2 x - 1 \right)}}{\left(2 x - 1\right)^{2}} \).
  1. \[ \lim_{x \to \frac{1}{2}^+}\left(\frac{1 - \cos{\left(2 x - 1 \right)}}{\left(2 x - 1\right)^{2}}\right) \]
    limit algebra algebraStart with the original limit. Rewrite the argument of the cosine. Factor out 2 from the denominator.✓ Proved
  2. \[ = \lim_{x \to \frac{1}{2}^+}\left(\frac{\frac{d}{d x} \left(1 - \cos{\left(2 x - 1 \right)}\right)}{\frac{d}{d x} \left(2 x - 1\right)^{2}}\right) \]
    lhopitalApply L'Hopital's rule.✓ Proved
  3. \[ = \lim_{x \to \frac{1}{2}^+}\left(\frac{2 \sin{\left(2 x - 1 \right)}}{8 x - 4}\right) \]
    simplify simplifyCompute the derivatives. Simplify the denominator.✓ Proved
  4. \[ = \lim_{x \to \frac{1}{2}^+}\left(\frac{\sin{\left(2 x - 1 \right)}}{4 x - 2}\right) \]
    simplifyCancel the common factor of 2.✓ Proved
  5. \[ = \lim_{u \to 0^+}\left(\frac{\sin{\left(2 u \right)}}{4 u}\right) \]
    substitution algebra simplifyLet u = x - 1/2, so x = u + 1/2. Substitute x = u + 1/2 into the expression. Simplify the denominator.✓ Proved
  6. \[ = \lim_{u \to 0^+} \frac{1}{2} \]
    trig-limitUse the fundamental trigonometric limit sin(z)/z -> 1 as z -> 0.✓ Proved
  7. \[ = \frac{1}{2} \]
    limitEvaluate the limit.✓ Proved
Answer \( \frac{1}{2} \)
The graph of f(x) = (1 - cos(2x - 1))/(2x - 1)². Two points slide along the curve toward x = 1/2, one from each side; their heights close in on 1/2.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to \frac{1}{2}^+}\left(\frac{1 - \cos{\left(2 x - 1 \right)}}{\left(2 x - 1\right)^{2}}\right) \]
    limit✓ Proved
  2. \[ = \lim_{x \to \frac{1}{2}^+}\left(\frac{2 \sin^{2}{\left(x - \frac{1}{2} \right)}}{\left(2 x - 1\right)^{2}}\right) \]
    rewrite simplify factoruse sin^2 identity pull out 2 and square✓ Proved
  3. \[ = \lim_{x \to \frac{1}{2}^+}\left(\frac{\sin^{2}{\left(x - \frac{1}{2} \right)}}{2 \left(x - \frac{1}{2}\right)^{2}}\right) \]
    rewrite simplifyrewrite denominator✓ Proved
  4. \[ = \frac{\lim_{x \to \frac{1}{2}^+}\left(\frac{\sin^{2}{\left(x - \frac{1}{2} \right)}}{\left(x - \frac{1}{2}\right)^{2}}\right)}{2} \]
    limit-lawpull constants out✓ Proved
  5. \[ = \frac{1}{2} \]
    limit limitvalue of inner limit is 1 final value✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.145

medium Video
Evaluate \( \displaystyle \lim_{x \to - \frac{1}{2}} \frac{\sin{\left(8 x + 4 \right)}}{3 \left(2 x + 1\right)} \).
  1. \[ \lim_{x \to - \frac{1}{2}^+}\left(\frac{\sin{\left(8 x + 4 \right)}}{6 x + 3}\right) \]
    limit algebraSet up the limit. Rewrite the numerator using factoring.✓ Proved
  2. \[ = \lim_{x \to - \frac{1}{2}^+}\left(\frac{\frac{d}{d x} \sin{\left(8 x + 4 \right)}}{\frac{d}{d x} \left(6 x + 3\right)}\right) \]
    lhopitalApply L'Hôpital's Rule because we have a 0/0 indeterminate form.✓ Proved
  3. \[ = \lim_{x \to - \frac{1}{2}^+}\left(\frac{4 \cos{\left(8 x + 4 \right)}}{3}\right) \]
    lhopital simplifyCompute the derivatives of the numerator and denominator. Simplify the constant fraction.✓ Proved
  4. \[ = \frac{4}{3} \]
    limit simplify simplify simplifyEvaluate the limit by substituting x = -1/2. Simplify the argument of the cosine function. Evaluate the cosine of zero. Final value.✓ Proved
Answer \( \frac{4}{3} \)
The graph of f(x) = sin(8x + 4)/(6x + 3). Two points slide along the curve toward x = -1/2, one from each side; their heights close in on 4/3.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to - \frac{1}{2}^+}\left(\frac{\sin{\left(8 x + 4 \right)}}{6 x + 3}\right) \]
    limit✓ Proved
  2. \[ = \lim_{x \to - \frac{1}{2}^+}\left(\frac{\frac{d}{d x} \sin{\left(8 x + 4 \right)}}{\frac{d}{d x} \left(6 x + 3\right)}\right) \]
    lhopitalApply l'Hôpital's rule✓ Proved
  3. \[ = \lim_{x \to - \frac{1}{2}^+}\left(\frac{4 \cos{\left(8 x + 4 \right)}}{3}\right) \]
    simplify simplifyCompute the derivatives Reduce the fraction✓ Proved
  4. \[ = \frac{4}{3} \]
    limitEvaluate the limit✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.422

medium Video
Evaluate \( \displaystyle \lim_{x \to \frac{1}{3}} \frac{\sin^{2}{\left(3 x - 1 \right)}}{\left(3 x - 1\right)^{2}} \).
  1. \[ \lim_{x \to \frac{1}{3}^+}\left(\frac{\sin^{2}{\left(3 x - 1 \right)}}{\left(3 x - 1\right)^{2}}\right) \]
    limit algebra algebraStart with the original limit. Rewrite the square of the fraction. Group the terms to reveal the structure.✓ Proved
  2. \[ = \lim_{x \to \frac{1}{3}^+}\left(\frac{\sin^{2}{\left(3 x - 1 \right)}}{9 \left(x - \frac{1}{3}\right)^{2}}\right) \]
    algebraFactor out the constant 3 from the denominator.✓ Proved
  3. \[ = \lim_{u \to 0^+}\left(\frac{\sin^{2}{\left(3 u \right)}}{9 u^{2}}\right) \]
    substitution simplifyLet u = x - 1/3, so u approaches 0. Simplify the expression inside the limit.✓ Proved
  4. \[ = \lim_{u \to 0^+} 1 \]
    trig-limit simplifyUse the fundamental trigonometric limit sin(u)/u -> 1. Evaluate the constant expression.✓ Proved
  5. \[ = 1 \]
    limitThe limit evaluates to 1.✓ Proved
Answer \( 1 \)
The graph of f(x) = sin(3x - 1)²/(3x - 1)². Two points slide along the curve toward x = 1/3, one from each side; their heights close in on 1.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to \frac{1}{3}^+}\left(\frac{\sin^{2}{\left(3 x - 1 \right)}}{\left(3 x - 1\right)^{2}}\right) \]
    limit factorRewrite the fraction as a square of sin(u)/u.✓ Proved
  2. \[ = \left(\lim_{x \to \frac{1}{3}^+}\left(\frac{\sin{\left(3 x - 1 \right)}}{3 x - 1}\right)\right)^{2} \]
    limit-lawApply the limit law to separate the square.✓ Proved
  3. \[ = 1 \]
    limit simplifySince sin(u)/u → 1 as u → 0, and 3*x-1 → 0 at x=1/3.✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.425

medium Video
Evaluate \( \displaystyle \lim_{x \to - \frac{1}{3}} \frac{\sin{\left(9 x + 3 \right)}}{3 x + 1} \).
  1. \[ \lim_{x \to - \frac{1}{3}^+}\left(\frac{\sin{\left(9 x + 3 \right)}}{3 x + 1}\right) \]
    limit factorEvaluate the limit of the function as x approaches -1/3. Factor the argument of the sine function.✓ Proved
  2. \[ = \lim_{x \to - \frac{1}{3}^+}\left(\frac{\frac{d}{d x} \sin{\left(9 x + 3 \right)}}{\frac{d}{d x} \left(3 x + 1\right)}\right) \]
    lhopitalApply L'Hopital's Rule because the limit is an indeterminate form 0/0.✓ Proved
  3. \[ = \lim_{x \to - \frac{1}{3}^+}\left(3 \cos{\left(9 x + 3 \right)}\right) \]
    simplify simplifyCompute the derivatives of the numerator and denominator. Simplify the expression by canceling the common factor of 3.✓ Proved
  4. \[ = \lim_{x \to - \frac{1}{3}^+} 3 \]
    substitutionSubstitute x = -1/3 into the expression.✓ Proved
  5. \[ = 3 \]
    limit simplify simplifyEvaluate the limit. Evaluate the cosine of 0. Final result.✓ Proved
Answer \( 3 \)
The graph of f(x) = sin(9x + 3)/(3x + 1). Two points slide along the curve toward x = -1/3, one from each side; their heights close in on 3.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to - \frac{1}{3}^+}\left(\frac{\sin{\left(9 x + 3 \right)}}{3 x + 1}\right) \]
    limit✓ Proved
  2. \[ = \lim_{x \to - \frac{1}{3}^+}\left(\frac{\frac{d}{d x} \sin{\left(9 x + 3 \right)}}{\frac{d}{d x} \left(3 x + 1\right)}\right) \]
    lhopital✓ Proved
  3. \[ = \lim_{x \to - \frac{1}{3}^+}\left(3 \cos{\left(9 x + 3 \right)}\right) \]
    simplify limit-law✓ Proved
  4. \[ = 3 \]
    limit✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.466

medium Video
Evaluate \( \displaystyle \lim_{x \to \frac{1}{3}} \frac{\sin{\left(15 x - 5 \right)}}{\sin{\left(6 x - 2 \right)}} \).
  1. \[ \lim_{x \to \frac{1}{3}^+}\left(\frac{\sin{\left(15 x - 5 \right)}}{\sin{\left(6 x - 2 \right)}}\right) \]
    limitIdentify the limit and the indeterminate form.✓ Proved
  2. \[ = \lim_{x \to \frac{1}{3}^+}\left(\frac{\frac{d}{d x} \sin{\left(15 x - 5 \right)}}{\frac{d}{d x} \sin{\left(6 x - 2 \right)}}\right) \]
    lhopitalApply L'Hopital's Rule because the limit is of the form 0/0.✓ Proved
  3. \[ = \lim_{x \to \frac{1}{3}^+}\left(\frac{5 \cos{\left(15 x - 5 \right)}}{2 \cos{\left(6 x - 2 \right)}}\right) \]
    simplifyCompute the derivatives.✓ Proved
  4. \[ = \lim_{x \to \frac{1}{3}^+} \frac{5}{2} \]
    limitEvaluate the limit by substituting x = 1/3.✓ Proved
  5. \[ = \frac{5}{2} \]
    algebra simplify simplify simplify simplifySimplify the arguments of the trigonometric functions. Evaluate the arithmetic inside the cosine functions. Substitute the value of cos(0). Simplify the fraction. Final simplified value.✓ Proved
Answer \( \frac{5}{2} \)
The graph of f(x) = sin(15x - 5)/sin(6x - 2). Two points slide along the curve toward x = 1/3, one from each side; their heights close in on 5/2.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to \frac{1}{3}^+}\left(\frac{\sin{\left(15 x - 5 \right)}}{\sin{\left(6 x - 2 \right)}}\right) \]
    limitOriginal limit✓ Proved
  2. \[ = \lim_{x \to \frac{1}{3}^+}\left(\frac{\frac{d}{d x} \sin{\left(15 x - 5 \right)}}{\frac{d}{d x} \sin{\left(6 x - 2 \right)}}\right) \]
    lhopitalApply l'Hôpital's rule✓ Proved
  3. \[ = \lim_{x \to \frac{1}{3}^+}\left(\frac{5 \cos{\left(15 x - 5 \right)}}{2 \cos{\left(6 x - 2 \right)}}\right) \]
    simplifyCompute derivatives✓ Proved
  4. \[ = \frac{5}{2} \]
    limit-law limitEvaluate at x = 1/3 Final value✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.26

medium Video
Evaluate \( \displaystyle \lim_{x \to 0} \frac{1 - \cos{\left(3 x \right)}}{9 x^{2}} \).
  1. \[ \lim_{x \to 0^+}\left(\frac{1 - \cos{\left(3 x \right)}}{9 x^{2}}\right) \]
    limitStart with the limit of the original function.✓ Proved
  2. \[ = \lim_{x \to 0^+}\left(\frac{\frac{d}{d x} \left(1 - \cos{\left(3 x \right)}\right)}{\frac{d}{d x} 9 x^{2}}\right) \]
    lhopitalApply L'Hôpital's rule because the limit is an indeterminate form 0/0.✓ Proved
  3. \[ = \lim_{x \to 0^+}\left(\frac{\sin{\left(3 x \right)}}{6 x}\right) \]
    simplify algebra rewriteDifferentiate the numerator and denominator. Simplify the fraction by dividing the constants. Rewrite the expression to use the standard trigonometric limit.✓ Proved
  4. \[ = \frac{\lim_{x \to 0^+}\left(\frac{\sin{\left(3 x \right)}}{3 x}\right)}{2} \]
    limit-lawApply the limit-law for the product of two functions.✓ Proved
  5. \[ = \frac{1}{2} \]
    trig-limit simplifyUse the standard limit result sin(u)/u -> 1 as u -> 0. Final evaluation.✓ Proved
Answer \( \frac{1}{2} \)
The graph of f(x) = (1 - cos(3x))/(9x²). Two points slide along the curve toward x = 0, one from each side; their heights close in on 1/2.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to 0^+}\left(\frac{1 - \cos{\left(3 x \right)}}{9 x^{2}}\right) \]
    limit✓ Proved
  2. \[ = \lim_{x \to 0^+}\left(\frac{2 \sin^{2}{\left(\frac{3 x}{2} \right)}}{9 x^{2}}\right) \]
    rewrite factor✓ Proved
  3. \[ = \frac{\lim_{x \to 0^+}\left(\frac{4 \sin^{2}{\left(\frac{3 x}{2} \right)}}{9 x^{2}}\right)}{2} \]
    limit-law✓ Proved
  4. \[ = \frac{1}{2} \]
    limit simplify✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.99

medium Video
Evaluate \( \displaystyle \lim_{x \to - \frac{1}{3}} \frac{3 x + 1}{\sin{\left(3 x + 1 \right)}} \).
  1. \[ \lim_{x \to - \frac{1}{3}^+}\left(\frac{3 x + 1}{\sin{\left(3 x + 1 \right)}}\right) \]
    limitStart with the limit of the given function.✓ Proved
  2. \[ = \lim_{x \to - \frac{1}{3}^+} \text{NaN} \]
    limitIdentify the indeterminate form 0/0.✓ Checked independently
  3. \[ = \lim_{x \to - \frac{1}{3}^+}\left(\frac{\frac{d}{d x} \left(3 x + 1\right)}{\frac{d}{d x} \sin{\left(3 x + 1 \right)}}\right) \]
    lhopitalApply L'Hopital's Rule because the limit is of the form 0/0.✓ Checked independently
  4. \[ = \lim_{x \to - \frac{1}{3}^+} \frac{1}{\cos{\left(3 x + 1 \right)}} \]
    simplify simplifyCompute the derivatives of the numerator and denominator. Cancel the common factor of 3.✓ Proved
  5. \[ = \lim_{x \to - \frac{1}{3}^+} 1 \]
    substitution simplifyEvaluate the expression at the point x = -1/3. Evaluate the cosine term.✓ Proved
  6. \[ = 1 \]
    simplifyFinal result.✓ Proved
Answer \( 1 \)
The graph of f(x) = (3x + 1)/sin(3x + 1). Two points slide along the curve toward x = -1/3, one from each side; their heights close in on 1.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to - \frac{1}{3}^+}\left(\frac{3 x + 1}{\sin{\left(3 x + 1 \right)}}\right) \]
    limit factorFactor 3 from the numerator.✓ Proved
  2. \[ = 3 \lim_{x \to - \frac{1}{3}^+}\left(\frac{x + \frac{1}{3}}{\sin{\left(3 x + 1 \right)}}\right) \]
    limit-law rewritePull out the constant factor 3. Rewrite the sine argument as 3*(x+1/3).✓ Proved
  3. \[ = 3 \lim_{t \to 0^+}\left(\frac{t}{\sin{\left(3 t \right)}}\right) \]
    substitutionLet t = x + 1/3, so t -> 0.✓ Proved
  4. \[ = 3 \lim_{t \to 0^+} \frac{1}{3} \]
    limit-lawUse sin(3*t) ~ 3*t near 0.✓ Proved
  5. \[ = 1 \]
    limit limitEvaluate the remaining constant limit. Final value of the limit.✓ Proved

✓ Nihil obstat Lines: 7 proved, 2 checked by independent solution. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.171

medium Video
Evaluate \( \displaystyle \lim_{x \to 0} \frac{\sin^{2}{\left(3 x \right)}}{9 x^{2}} \).
  1. \[ \lim_{x \to 0^+}\left(\frac{\sin^{2}{\left(3 x \right)}}{9 x^{2}}\right) \]
    limit algebraStart with the original limit. Rewrite the expression as a square.✓ Proved
  2. \[ = \left(\lim_{x \to 0^+}\left(\frac{\sin{\left(3 x \right)}}{3 x}\right)\right)^{2} \]
    limit-lawApply the power rule for limits.✓ Proved
  3. \[ = \left(\lim_{x \to 0^+}\left(\frac{\frac{d}{d x} \sin{\left(3 x \right)}}{\frac{d}{d x} 3 x}\right)\right)^{2} \]
    lhopitalApply L'Hopital's rule to the inner limit.✓ Proved
  4. \[ = \left(\lim_{x \to 0^+} \cos{\left(3 x \right)}\right)^{2} \]
    simplify simplifyCompute the derivatives. Simplify the fraction inside the limit.✓ Proved
  5. \[ = 1 \]
    limit simplifyEvaluate the limit of the cosine function. Final result.✓ Proved
Answer \( 1 \)
The graph of f(x) = sin(3x)²/(9x²). Two points slide along the curve toward x = 0, one from each side; their heights close in on 1.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to 0^+}\left(\frac{\sin^{2}{\left(3 x \right)}}{9 x^{2}}\right) \]
    limit rewrite rewritefactor out 9*x**2 expand the square✓ Proved
  2. \[ = \left(\lim_{x \to 0^+}\left(\frac{\sin{\left(3 x \right)}}{3 x}\right)\right)^{2} \]
    limit-lawproduct of limits✓ Proved
  3. \[ = \lim_{x \to 0^+}\left(\frac{\sin{\left(3 x \right)}}{3 x}\right) \]
    limitsimplify one factor✓ Proved
  4. \[ = 1 \]
    limit algebra simplifyknown limit sin(u)/u → 1 multiply the two limits evaluate the product✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.413

medium Video
Evaluate \( \displaystyle \lim_{x \to -1} \frac{\sin{\left(5 x + 5 \right)}}{\sin{\left(2 x + 2 \right)}} \).
  1. \[ \lim_{x \to -1^+}\left(\frac{\sin{\left(5 x + 5 \right)}}{\sin{\left(2 x + 2 \right)}}\right) \]
    limit factorEvaluate the limit of the given function. Factor the arguments of the sine functions.✓ Proved
  2. \[ = \lim_{x \to -1^+}\left(\frac{\frac{d}{d x} \sin{\left(5 x + 5 \right)}}{\frac{d}{d x} \sin{\left(2 x + 2 \right)}}\right) \]
    lhopitalThe limit is an indeterminate form 0/0, so apply L'Hopital's rule.✓ Proved
  3. \[ = \lim_{x \to -1^+}\left(\frac{5 \cos{\left(5 x + 5 \right)}}{2 \cos{\left(2 x + 2 \right)}}\right) \]
    simplifyCompute the derivatives of the numerator and denominator.✓ Proved
  4. \[ = \lim_{x \to -1^+} \frac{5}{2} \]
    substitution simplify simplifySubstitute the value x = -1 into the expression. Evaluate the cosine terms. Simplify the numerical fraction.✓ Proved
  5. \[ = \frac{5}{2} \]
    limitThe limit is evaluated.✓ Proved
Answer \( \frac{5}{2} \)
The graph of f(x) = sin(5x + 5)/sin(2x + 2). Two points slide along the curve toward x = -1, one from each side; their heights close in on 5/2.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to -1^+}\left(\frac{\sin{\left(5 x + 5 \right)}}{\sin{\left(2 x + 2 \right)}}\right) \]
    limit rewriteFactor out (x+1) from the arguments of the sines.✓ Proved
  2. \[ = \lim_{u \to 0^+}\left(\frac{\sin{\left(5 u \right)}}{\sin{\left(2 u \right)}}\right) \]
    substitutionLet u = x + 1, so u -> 0 as x -> -1.✓ Proved
  3. \[ = \lim_{u \to 0^+}\left(\frac{\sin{\left(5 u \right)}}{2 \sin{\left(u \right)}}\right) \]
    limit-lawRewrite sin(2*u) as 2*sin(u).✓ Proved
  4. \[ = \frac{\lim_{u \to 0^+}\left(\frac{\sin{\left(5 u \right)}}{\sin{\left(u \right)}}\right)}{2} \]
    limit-lawSeparate the constant factor 1/2.✓ Proved
  5. \[ = \frac{5}{2} \]
    limitAs u -> 0, sin(5*u)/sin(u) -> 5.✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.502

medium Video
Evaluate \( \displaystyle \lim_{x \to \frac{1}{3}} \frac{1 - \cos{\left(3 x - 1 \right)}}{3 x - 1} \).
  1. \[ \lim_{x \to \frac{1}{3}^+}\left(\frac{1 - \cos{\left(3 x - 1 \right)}}{3 x - 1}\right) \]
    limitStart with the limit of the given function.✓ Proved
  2. \[ = \lim_{x \to \frac{1}{3}^+}\left(\frac{\frac{d}{d x} \left(1 - \cos{\left(3 x - 1 \right)}\right)}{\frac{d}{d x} \left(3 x - 1\right)}\right) \]
    lhopitalApply L'Hopital's rule because it is an indeterminate form 0/0.✓ Proved
  3. \[ = \lim_{x \to \frac{1}{3}^+} \sin{\left(3 x - 1 \right)} \]
    simplify simplifyDifferentiate the numerator and denominator. Simplify the fraction.✓ Proved
  4. \[ = 0 \]
    substitution algebra simplify limitSubstitute the value x = 1/3 into the expression. Simplify the expression inside the sine function. Evaluate the expression inside the sine. The final value of the limit is 0.✓ Proved
Answer \( 0 \)
The graph of f(x) = (1 - cos(3x - 1))/(3x - 1). Two points slide along the curve toward x = 1/3, one from each side; their heights close in on 0.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to \frac{1}{3}^+}\left(\frac{1 - \cos{\left(3 x - 1 \right)}}{3 x - 1}\right) \]
    limitOriginal limit✓ Proved
  2. \[ = \lim_{x \to \frac{1}{3}^+}\left(\frac{2 \sin^{2}{\left(\frac{3 x}{2} - \frac{1}{2} \right)}}{3 x - 1}\right) \]
    rewriteUse identity 1-cos t = 2 sin^2(t/2)✓ Proved
  3. \[ = \lim_{u \to 0^+}\left(\frac{2 \sin^{2}{\left(\frac{u}{2} \right)}}{u}\right) \]
    substitution rewrite simplify simplifyLet u=3x-1 Factor (u/2) out of sin term (u/2)**2/u = u/4 Combine constants✓ Proved
  4. \[ = \lim_{u \to 0^+}\left(\frac{4 \sin^{2}{\left(\frac{u}{2} \right)}}{u^{2}}\right) \lim_{u \to 0^+}\left(\frac{u}{2}\right) \]
    limit-lawProduct of limits✓ Proved
  5. \[ = 0 \]
    limit limitEvaluate each factor Final value✓ Proved

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Problem 1.239

medium Video
Evaluate \( \displaystyle \lim_{x \to - \frac{1}{3}} \frac{\tan{\left(3 x + 1 \right)}}{3 x + 1} \).
  1. \[ \lim_{x \to - \frac{1}{3}^+}\left(\frac{\tan{\left(3 x + 1 \right)}}{3 x + 1}\right) \]
    limit algebra simplifySet up the limit. Rewrite the denominator to isolate the term approaching zero. The expression is already in a form suitable for substitution.✓ Proved
  2. \[ = \lim_{u \to 0^+}\left(\frac{\tan{\left(u \right)}}{u}\right) \]
    substitutionLet u = 3*x + 1. As x approaches -1/3, u approaches 0.✓ Proved
  3. \[ = \lim_{u \to 0^+}\left(\frac{\frac{d}{d u} \tan{\left(u \right)}}{\frac{d}{d u} u}\right) \]
    lhopitalApply L'Hôpital's rule because the limit is of the form 0/0.✓ Proved
  4. \[ = \lim_{u \to 0^+} \sec^{2}{\left(u \right)} \]
    simplifyCompute the derivatives of the numerator and denominator.✓ Proved
  5. \[ = 1 \]
    limitEvaluate the limit as u approaches 0.✓ Proved
Answer \( 1 \)
The graph of f(x) = tan(3x + 1)/(3x + 1). Two points slide along the curve toward x = -1/3, one from each side; their heights close in on 1.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to - \frac{1}{3}^+}\left(\frac{\tan{\left(3 x + 1 \right)}}{3 x + 1}\right) \]
    limit factorRewrite the denominator as 3*(x+1/3).✓ Proved
  2. \[ = \lim_{u \to 0^+}\left(\frac{\tan{\left(u \right)}}{u}\right) \]
    substitutionLet u = 3*x + 1; then x -> -1/3 gives u -> 0.✓ Proved
  3. \[ = 1 \]
    limit-lawThe standard limit lim_{u->0} tan(u)/u = 1.✓ Proved

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Problem 1.251

medium Video
Evaluate \( \displaystyle \lim_{x \to 1} \frac{\sin{\left(4 x - 4 \right)}}{3 \left(x - 1\right)} \).
  1. \[ \lim_{x \to 1^+}\left(\frac{\sin{\left(4 x - 4 \right)}}{3 x - 3}\right) \]
    limit algebraIdentify the limit to be evaluated. Factor out 4 from the argument of the sine function.✓ Proved
  2. \[ = \frac{\lim_{x \to 1^+}\left(\frac{\sin{\left(4 x - 4 \right)}}{x - 1}\right)}{3} \]
    limit-lawApply the constant multiple rule for limits.✓ Proved
  3. \[ = \lim_{x \to 1^+}\left(\frac{\frac{d}{d x} \sin{\left(4 x - 4 \right)}}{\frac{d}{d x} \left(3 x - 3\right)}\right) \]
    lhopitalThe limit is in the indeterminate form 0/0, so apply L'Hopital's rule.✓ Proved
  4. \[ = \lim_{x \to 1^+}\left(\frac{4 \cos{\left(4 x - 4 \right)}}{3}\right) \]
    simplifyCompute the derivatives of the numerator and denominator.✓ Proved
  5. \[ = \frac{4}{3} \]
    limit simplifyEvaluate the limit by substituting x = 1. Simplify the final numerical value.✓ Proved
Answer \( \frac{4}{3} \)
The graph of f(x) = sin(4x - 4)/(3x - 3). Two points slide along the curve toward x = 1, one from each side; their heights close in on 4/3.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to 1^+}\left(\frac{\sin{\left(4 x - 4 \right)}}{3 x - 3}\right) \]
    limit rewriteRewrite 4*x-4 as 4*(x-1).✓ Proved
  2. \[ = \lim_{x \to 1^+}\left(\frac{4 \sin{\left(4 x - 4 \right)}}{3 \left(4 x - 4\right)}\right) \]
    factorFactor out 4 from the denominator.✓ Proved
  3. \[ = \frac{4 \lim_{x \to 1^+}\left(\frac{\sin{\left(4 x - 4 \right)}}{4 x - 4}\right)}{3} \]
    limit-lawSeparate constant factor.✓ Proved
  4. \[ = \frac{4}{3} \]
    limit simplifyUse lim_{u->0} sin(u)/u = 1 with u = 4*(x-1). Final value of the limit.✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.316

medium Video
Evaluate \( \displaystyle \lim_{x \to - \frac{1}{2}} \frac{\sin{\left(10 x + 5 \right)}}{\sin{\left(4 x + 2 \right)}} \).
  1. \[ \lim_{x \to - \frac{1}{2}^+}\left(\frac{\sin{\left(10 x + 5 \right)}}{\sin{\left(4 x + 2 \right)}}\right) \]
    limit factorSet up the limit. Factor the arguments of the sine functions.✓ Proved
  2. \[ = \lim_{u \to 0^+}\left(\frac{\sin{\left(5 u \right)}}{\sin{\left(2 u \right)}}\right) \]
    substitutionLet u = 2*x + 1, so u approaches 0 as x approaches -1/2.✓ Proved
  3. \[ = \lim_{u \to 0^+}\left(\frac{\frac{d}{d u} \sin{\left(5 u \right)}}{\frac{d}{d u} \sin{\left(2 u \right)}}\right) \]
    lhopitalApply L'Hôpital's rule since the limit is an indeterminate form 0/0.✓ Proved
  4. \[ = \lim_{u \to 0^+}\left(\frac{5 \cos{\left(5 u \right)}}{2 \cos{\left(2 u \right)}}\right) \]
    simplifyCompute the derivatives.✓ Proved
  5. \[ = \frac{5}{2} \]
    limit simplifyEvaluate the limit by substituting u = 0. Simplify the final value.✓ Proved
Answer \( \frac{5}{2} \)
The graph of f(x) = sin(10x + 5)/sin(4x + 2). Two points slide along the curve toward x = -1/2, one from each side; their heights close in on 5/2.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to - \frac{1}{2}^+}\left(\frac{\sin{\left(10 x + 5 \right)}}{\sin{\left(4 x + 2 \right)}}\right) \]
    limit✓ Proved
  2. \[ = \lim_{x \to - \frac{1}{2}^+}\left(\frac{\frac{d}{d x} \sin{\left(10 x + 5 \right)}}{\frac{d}{d x} \sin{\left(4 x + 2 \right)}}\right) \]
    lhopital✓ Proved
  3. \[ = \lim_{x \to - \frac{1}{2}^+}\left(\frac{5 \cos{\left(10 x + 5 \right)}}{2 \cos{\left(4 x + 2 \right)}}\right) \]
    limit✓ Proved
  4. \[ = \frac{5}{2} \]
    simplify limit✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.556

medium Video
Evaluate \( \displaystyle \lim_{x \to -1} \frac{1 - \cos{\left(x + 1 \right)}}{\left(x + 1\right)^{2}} \).
  1. \[ \lim_{x \to -1^+}\left(\frac{1 - \cos{\left(x + 1 \right)}}{\left(x + 1\right)^{2}}\right) \]
    limitStart with the original limit.✓ Proved
  2. \[ = \lim_{u \to 0^+}\left(\frac{1 - \cos{\left(u \right)}}{u^{2}}\right) \]
    substitutionSubstitute u = x + 1, which implies u approaches 0 as x approaches -1.✓ Proved
  3. \[ = \lim_{u \to 0^+}\left(\frac{\frac{d}{d u} \left(1 - \cos{\left(u \right)}\right)}{\frac{d}{d u} u^{2}}\right) \]
    lhopitalApply L'Hôpital's rule since the limit is in the indeterminate form 0/0.✓ Proved
  4. \[ = \lim_{u \to 0^+}\left(\frac{\sin{\left(u \right)}}{2 u}\right) \]
    simplify algebraCompute the derivatives of the numerator and denominator. Factor out the constant 1/2.✓ Proved
  5. \[ = \lim_{u \to 0^+} \frac{1}{2} \]
    trig-limitUse the fundamental trigonometric limit sin(u)/u -> 1 as u approaches 0.✓ Proved
  6. \[ = \frac{1}{2} \]
    limitEvaluate the final limit.✓ Proved
Answer \( \frac{1}{2} \)
The graph of f(x) = (1 - cos(x + 1))/(x + 1)². Two points slide along the curve toward x = -1, one from each side; their heights close in on 1/2.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to -1^+}\left(\frac{1 - \cos{\left(x + 1 \right)}}{\left(x + 1\right)^{2}}\right) \]
    limit✓ Proved
  2. \[ = \lim_{x \to -1^+}\left(\frac{2 \sin^{2}{\left(\frac{x}{2} + \frac{1}{2} \right)}}{\left(x + 1\right)^{2}}\right) \]
    algebra algebraUse 1 - cos(u) = 2*sin(u/2)**2 Rewrite the square as a ratio squared✓ Proved
  3. \[ = \lim_{u \to 0^+}\left(\frac{2 \sin^{2}{\left(\frac{u}{2} \right)}}{u^{2}}\right) \]
    substitution algebra algebraLet u = x + 1 Factor u/2 out of the denominator Simplify the constant factor✓ Proved
  4. \[ = \lim_{u \to 0^+} \frac{1}{2} \]
    limitUse lim_{u->0} sin(u/2)/(u/2) = 1✓ Proved
  5. \[ = \frac{1}{2} \]
    limit✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.46

medium Video
Evaluate \( \displaystyle \lim_{x \to \frac{1}{2}} \frac{\sin{\left(8 x - 4 \right)}}{3 \left(2 x - 1\right)} \).
  1. \[ \lim_{x \to \frac{1}{2}^+}\left(\frac{\sin{\left(8 x - 4 \right)}}{6 x - 3}\right) \]
    limit algebraIdentify the limit to be evaluated. Factor out 4 from the argument of the sine function.✓ Proved
  2. \[ = \lim_{x \to \frac{1}{2}^+}\left(\frac{\frac{d}{d x} \sin{\left(8 x - 4 \right)}}{\frac{d}{d x} \left(6 x - 3\right)}\right) \]
    lhopitalThe limit is an indeterminate form 0/0, so apply L'Hopital's rule.✓ Proved
  3. \[ = \lim_{x \to \frac{1}{2}^+}\left(\frac{4 \cos{\left(8 x - 4 \right)}}{3}\right) \]
    simplifyCompute the derivatives of the numerator and denominator.✓ Proved
  4. \[ = \frac{4}{3} \]
    limit simplifyEvaluate the limit by substituting x = 1/2. Simplify the final numerical expression.✓ Proved
Answer \( \frac{4}{3} \)
The graph of f(x) = sin(8x - 4)/(6x - 3). Two points slide along the curve toward x = 1/2, one from each side; their heights close in on 4/3.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to \frac{1}{2}^+}\left(\frac{\sin{\left(8 x - 4 \right)}}{6 x - 3}\right) \]
    limit rewrite factorRewrite the sine argument. Factor 3*(2*x-1) as 6*(x-1/2).✓ Proved
  2. \[ = \lim_{x \to \frac{1}{2}^+}\left(\frac{4 \sin{\left(8 x - 4 \right)}}{3 \left(8 x - 4\right)}\right) \]
    rewriteIntroduce 8*(x-1/2) to use the sin(u)/u limit.✓ Proved
  3. \[ = \frac{4 \lim_{x \to \frac{1}{2}^+}\left(\frac{\sin{\left(8 x - 4 \right)}}{8 x - 4}\right)}{3} \]
    limit-lawSeparate constant factor.✓ Proved
  4. \[ = \frac{4}{3} \]
    limit simplifyLimit of sin(u)/u as u→0 is 1. Simplify the constant.✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.77

medium Video
Evaluate \( \displaystyle \lim_{x \to 0} \frac{\sin{\left(10 x \right)}}{\sin{\left(4 x \right)}} \).
  1. \[ \lim_{x \to 0^+}\left(\frac{\sin{\left(10 x \right)}}{\sin{\left(4 x \right)}}\right) \]
    limitIdentify the limit to be evaluated.✓ Proved
  2. \[ = \lim_{x \to 0^+}\left(\frac{\frac{d}{d x} \sin{\left(10 x \right)}}{\frac{d}{d x} \sin{\left(4 x \right)}}\right) \]
    lhopitalThe limit is an indeterminate form 0/0, so apply L'Hôpital's rule.✓ Proved
  3. \[ = \lim_{x \to 0^+}\left(\frac{5 \cos{\left(10 x \right)}}{2 \cos{\left(4 x \right)}}\right) \]
    simplifyCompute the derivatives of the numerator and denominator.✓ Proved
  4. \[ = \frac{5}{2} \]
    limit simplifyEvaluate the limit by substituting x = 0. Simplify the resulting fraction.✓ Proved
  5. \[ = 2.5 \]
    simplifyFinal numerical value.✓ Proved
Answer \( \frac{5}{2} \)
The graph of f(x) = sin(10x)/sin(4x). Two points slide along the curve toward x = 0, one from each side; their heights close in on 5/2.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to 0^+}\left(\frac{\sin{\left(10 x \right)}}{\sin{\left(4 x \right)}}\right) \]
    limit algebraRewrite using sin(z)/z limits✓ Proved
  2. \[ = \lim_{x \to 0^+}\left(\frac{\sin{\left(10 x \right)}}{10 x}\right) \lim_{x \to 0^+} \frac{5}{2} \lim_{x \to 0^+}\left(\frac{4 x}{\sin{\left(4 x \right)}}\right) \]
    limit-lawSeparate into product of limits✓ Proved
  3. \[ = \frac{5}{2} \]
    limitEvaluate each limit: 1 * 10/4 * 1 = 5/2✓ Proved

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Problem 1.103

medium Video
Evaluate \( \displaystyle \lim_{x \to 1} \frac{1 - \cos{\left(x - 1 \right)}}{x - 1} \).
  1. \[ \lim_{x \to 1^+}\left(\frac{1 - \cos{\left(x - 1 \right)}}{x - 1}\right) \]
    limitStart with the limit of the original function.✓ Proved
  2. \[ = \lim_{x \to 1^+}\left(\frac{\frac{d}{d x} \left(1 - \cos{\left(x - 1 \right)}\right)}{\frac{d}{d x} \left(x - 1\right)}\right) \]
    lhopitalApply L'Hopital's rule since the limit is an indeterminate form 0/0.✓ Proved
  3. \[ = \lim_{x \to 1^+} \sin{\left(x - 1 \right)} \]
    simplify simplifyCompute the derivatives of the numerator and denominator. Simplify the expression.✓ Proved
  4. \[ = 0 \]
    limit simplifyEvaluate the limit by substituting x = 1. Final result.✓ Proved
Answer \( 0 \)
The graph of f(x) = (1 - cos(x - 1))/(x - 1). Two points slide along the curve toward x = 1, one from each side; their heights close in on 0.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to 1^+}\left(\frac{1 - \cos{\left(x - 1 \right)}}{x - 1}\right) \]
    limit✓ Proved
  2. \[ = \lim_{x \to 1^+}\left(\frac{\frac{d}{d x} \left(1 - \cos{\left(x - 1 \right)}\right)}{\frac{d}{d x} \left(x - 1\right)}\right) \]
    lhopitalApply l'Hôpital's rule✓ Proved
  3. \[ = \lim_{x \to 1^+} \sin{\left(x - 1 \right)} \]
    simplifyCompute derivatives✓ Proved
  4. \[ = 0 \]
    limitEvaluate sin(0)✓ Proved

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Problem 1.141

medium Video
Evaluate \( \displaystyle \lim_{x \to \frac{1}{3}} \frac{\tan{\left(3 x - 1 \right)}}{3 x - 1} \).
  1. \[ \lim_{x \to \frac{1}{3}^+}\left(\frac{\tan{\left(3 x - 1 \right)}}{3 x - 1}\right) \]
    limitIdentify the limit to be evaluated.✓ Proved
  2. \[ = \lim_{u \to 0^+}\left(\frac{\tan{\left(u \right)}}{u}\right) \]
    substitutionLet u = 3*x - 1, so as x approaches 1/3, u approaches 0.✓ Proved
  3. \[ = \lim_{u \to 0^+}\left(\frac{\frac{d}{d u} \tan{\left(u \right)}}{\frac{d}{d u} u}\right) \]
    lhopitalApply L'Hopital's Rule since the limit is in the form 0/0.✓ Proved
  4. \[ = \lim_{u \to 0^+} \sec^{2}{\left(u \right)} \]
    simplifyCompute the derivatives of the numerator and denominator.✓ Proved
  5. \[ = 1 \]
    limit simplifyEvaluate the limit by plugging in u = 0. Simplify the final numerical value.✓ Proved
Answer \( 1 \)
The graph of f(x) = tan(3x - 1)/(3x - 1). Two points slide along the curve toward x = 1/3, one from each side; their heights close in on 1.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to \frac{1}{3}^+}\left(\frac{\tan{\left(3 x - 1 \right)}}{3 x - 1}\right) \]
    limit✓ Proved
  2. \[ = \lim_{u \to 0^+}\left(\frac{\tan{\left(u \right)}}{u}\right) \]
    substitutionLet u = 3*x - 1, so u -> 0 as x -> 1/3.✓ Proved
  3. \[ = 1 \]
    limit-lawThe standard limit lim_{u->0} tan(u)/u = 1.✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.165

medium Video
Evaluate \( \displaystyle \lim_{x \to -1} \frac{\sin{\left(4 x + 4 \right)}}{3 \left(x + 1\right)} \).
  1. \[ \lim_{x \to -1^+}\left(\frac{\sin{\left(4 x + 4 \right)}}{3 x + 3}\right) \]
    limit factorIdentify the limit to evaluate. Factor the argument of the sine function.✓ Proved
  2. \[ = \lim_{x \to -1^+}\left(\frac{\frac{d}{d x} \sin{\left(4 x + 4 \right)}}{\frac{d}{d x} \left(3 x + 3\right)}\right) \]
    lhopitalThe limit is an indeterminate form 0/0, so apply L'Hopital's rule.✓ Proved
  3. \[ = \lim_{x \to -1^+}\left(\frac{4 \cos{\left(4 x + 4 \right)}}{3}\right) \]
    simplifyCompute the derivatives of the numerator and denominator.✓ Proved
  4. \[ = \frac{4}{3} \]
    limit simplifyEvaluate the limit by substituting x = -1. Simplify the final numerical value.✓ Proved
Answer \( \frac{4}{3} \)
The graph of f(x) = sin(4x + 4)/(3x + 3). Two points slide along the curve toward x = -1, one from each side; their heights close in on 4/3.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to -1^+}\left(\frac{\sin{\left(4 x + 4 \right)}}{3 x + 3}\right) \]
    limit rewriteInitial limit Rewrite the argument of sin✓ Proved
  2. \[ = \lim_{x \to -1^+}\left(\frac{4 \sin{\left(4 x + 4 \right)}}{3 \left(4 x + 4\right)}\right) \]
    limit-lawFactor out 4/3 using limit law✓ Proved
  3. \[ = \frac{4 \lim_{x \to -1^+}\left(\frac{\sin{\left(4 x + 4 \right)}}{4 x + 4}\right)}{3} \]
    limitSeparate the constant 4/3✓ Proved
  4. \[ = \frac{4}{3} \]
    limit limitLimit of sin(u)/u as u→0 is 1 Final value of the limit✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

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Evaluate \( \displaystyle \lim_{x \to - \frac{1}{2}} \frac{2 x + 1}{\sin{\left(2 x + 1 \right)}} \).
Problem 1.123medium Video✓ Nihil obstat
Evaluate \( \displaystyle \lim_{x \to \frac{1}{2}} \frac{\sin^{2}{\left(2 x - 1 \right)}}{\left(2 x - 1\right)^{2}} \).
Problem 1.150medium VideoNot checked
Evaluate \( \displaystyle \lim_{x \to - \frac{1}{2}} \frac{\tan{\left(2 x + 1 \right)}}{2 x + 1} \).
Problem 1.156medium Video✓ Nihil obstat
Evaluate \( \displaystyle \lim_{x \to -1} \frac{\sin^{2}{\left(x + 1 \right)}}{\left(x + 1\right)^{2}} \).
Problem 1.229medium Video✓ Nihil obstat
Evaluate \( \displaystyle \lim_{x \to - \frac{1}{2}} \frac{\sin{\left(6 x + 3 \right)}}{2 x + 1} \).
Problem 1.234medium Video✓ Nihil obstat
Evaluate \( \displaystyle \lim_{x \to - \frac{1}{3}} \frac{\sin^{2}{\left(3 x + 1 \right)}}{\left(3 x + 1\right)^{2}} \).
Problem 1.248medium Video✓ Nihil obstat
Evaluate \( \displaystyle \lim_{x \to 0} \frac{1 - \cos{\left(2 x \right)}}{2 x} \).
Problem 1.250medium Video✓ Nihil obstat
Evaluate \( \displaystyle \lim_{x \to 1} \frac{\sin{\left(5 x - 5 \right)}}{\sin{\left(2 x - 2 \right)}} \).
Problem 1.253medium Video✓ Nihil obstat
Evaluate \( \displaystyle \lim_{x \to 1} \frac{\sin^{2}{\left(x - 1 \right)}}{\left(x - 1\right)^{2}} \).
Problem 1.258medium Video✓ Nihil obstat
Evaluate \( \displaystyle \lim_{x \to -1} \frac{\sin{\left(3 x + 3 \right)}}{x + 1} \).
Problem 1.307medium Video✓ Nihil obstat
Evaluate \( \displaystyle \lim_{x \to \frac{1}{3}} \frac{\sin{\left(12 x - 4 \right)}}{3 \left(3 x - 1\right)} \).
Problem 1.315medium Video✓ Nihil obstat
Evaluate \( \displaystyle \lim_{x \to - \frac{1}{3}} \frac{\sin{\left(15 x + 5 \right)}}{\sin{\left(6 x + 2 \right)}} \).
Problem 1.320medium Video✓ Nihil obstat
Evaluate \( \displaystyle \lim_{x \to 0} \frac{1 - \cos{\left(3 x \right)}}{3 x} \).
Problem 1.322medium Video✓ Nihil obstat
Evaluate \( \displaystyle \lim_{x \to \frac{1}{2}} \frac{\sin{\left(10 x - 5 \right)}}{\sin{\left(4 x - 2 \right)}} \).
Problem 1.331medium Video✓ Nihil obstat
Evaluate \( \displaystyle \lim_{x \to -1} \frac{1 - \cos{\left(x + 1 \right)}}{x + 1} \).
Problem 1.355medium Video✓ Nihil obstat
Evaluate \( \displaystyle \lim_{x \to \frac{1}{2}} \frac{\tan{\left(2 x - 1 \right)}}{2 x - 1} \).
Problem 1.356medium Video✓ Nihil obstat
Evaluate \( \displaystyle \lim_{x \to \frac{1}{2}} \frac{1 - \cos{\left(2 x - 1 \right)}}{2 x - 1} \).
Problem 1.373medium Video✓ Nihil obstat
Evaluate \( \displaystyle \lim_{x \to \frac{1}{3}} \frac{\sin{\left(9 x - 3 \right)}}{3 x - 1} \).
Problem 1.377medium Video✓ Every equation proved
Evaluate \( \displaystyle \lim_{x \to 0} \frac{1 - \cos{\left(2 x \right)}}{4 x^{2}} \).
Problem 1.378medium Video✓ Nihil obstat
Evaluate \( \displaystyle \lim_{x \to \frac{1}{3}} \frac{3 x - 1}{\sin{\left(3 x - 1 \right)}} \).
Problem 1.411medium Video✓ Nihil obstat
Evaluate \( \displaystyle \lim_{x \to 1} \frac{1 - \cos{\left(x - 1 \right)}}{\left(x - 1\right)^{2}} \).
Problem 1.419medium Video✓ Nihil obstat
Evaluate \( \displaystyle \lim_{x \to 1} \frac{\sin{\left(3 x - 3 \right)}}{x - 1} \).
Problem 1.426medium Video✓ Nihil obstat
Evaluate \( \displaystyle \lim_{x \to - \frac{1}{2}} \frac{1 - \cos{\left(2 x + 1 \right)}}{2 x + 1} \).
Problem 1.457medium Video✓ Nihil obstat
Evaluate \( \displaystyle \lim_{x \to \frac{1}{2}} \frac{\sin{\left(6 x - 3 \right)}}{2 x - 1} \).
Problem 1.524medium Video✓ Nihil obstat
Evaluate \( \displaystyle \lim_{x \to \frac{1}{2}} \frac{2 x - 1}{\sin{\left(2 x - 1 \right)}} \).
Problem 1.637medium Video✓ Every equation proved
Evaluate \( \displaystyle \lim_{x \to - \frac{1}{3}} \frac{1 - \cos{\left(3 x + 1 \right)}}{3 x + 1} \).
Problem 1.810medium VideoNot checked