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L'Hôpital's rule practice problems

Indeterminate forms 0/0 and ∞/∞, settled by differentiating top and bottom. 76 problems with worked solutions; in 72 of them every equation is proved by a computer algebra system.

20 worked problems

Try each one before opening the solution. Every line is labeled with what checked it; 20 of these also have a second solution, written separately and checked the same way. How we verify

Problem 1.797

hard Video
Evaluate \( \displaystyle \lim_{x \to \frac{1}{3}} \frac{3 x - \sin{\left(3 x - 1 \right)} - 1}{\left(3 x - 1\right)^{3}} \).
  1. \[ \lim_{x \to \frac{1}{3}^+}\left(\frac{3 x - \sin{\left(3 x - 1 \right)} - 1}{\left(3 x - 1\right)^{3}}\right) \]
    limit algebraEvaluate the limit of the given function at x = 1/3. Group the terms in the numerator.✓ Proved
  2. \[ = \lim_{x \to \frac{1}{3}^+}\left(\frac{\frac{d}{d x} \left(3 x - \sin{\left(3 x - 1 \right)} - 1\right)}{\frac{d}{d x} \left(3 x - 1\right)^{3}}\right) \]
    lhopitalApply L'Hôpital's rule since the limit is an indeterminate form 0/0.✓ Proved
  3. \[ = \lim_{x \to \frac{1}{3}^+}\left(\frac{3 - 3 \cos{\left(3 x - 1 \right)}}{9 \left(3 x - 1\right)^{2}}\right) \]
    simplify simplify algebraCompute the derivatives in the numerator and denominator. Simplify the denominator. Factor out 3 from the numerator.✓ Proved
  4. \[ = \lim_{x \to \frac{1}{3}^+}\left(\frac{1 - \cos{\left(3 x - 1 \right)}}{3 \left(3 x - 1\right)^{2}}\right) \]
    simplify rewriteSimplify the fraction. Rewrite the expression to isolate the term (x - 1/3).✓ Proved
  5. \[ = \lim_{u \to 0^+}\left(\frac{1 - \cos{\left(3 u \right)}}{27 u^{2}}\right) \]
    substitution simplifySubstitute u = x - 1/3, which implies u approaches 0 as x approaches 1/3. Simplify the denominator (3 * (3*u)**2 = 27*u**2).✓ Proved
  6. \[ = \lim_{u \to 0^+}\left(\frac{\frac{d}{d u} \left(1 - \cos{\left(3 u \right)}\right)}{\frac{d}{d u} 27 u^{2}}\right) \]
    lhopitalApply L'Hôpital's rule again.✓ Proved
  7. \[ = \lim_{u \to 0^+}\left(\frac{\sin{\left(3 u \right)}}{18 u}\right) \]
    simplify algebraCompute the derivatives. Simplify the coefficients.✓ Proved
  8. \[ = \lim_{u \to 0^+} \frac{1}{6} \]
    trig-limitUse the standard limit sin(kz)/z = k as z approaches 0.✓ Proved
  9. \[ = \frac{1}{6} \]
    limitFinal evaluation of the limit.✓ Proved
Answer \( \frac{1}{6} \)
The graph of f(x) = (3x - sin(3x - 1) - 1)/(3x - 1)³. Two points slide along the curve toward x = 1/3, one from each side; their heights close in on 1/6.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to \frac{1}{3}^+}\left(\frac{3 x - \sin{\left(3 x - 1 \right)} - 1}{\left(3 x - 1\right)^{3}}\right) \]
    limit✓ Proved
  2. \[ = \lim_{x \to \frac{1}{3}^+} \frac{1}{6} \]
    rewrite algebra simplify simplifyUse sin(y) ≈ y - y³/6 near y=0 Distribute the minus sign Combine like terms in the numerator Cancel (3*x-1)**3✓ Proved
  3. \[ = \frac{1}{6} \]
    limitThe limit equals the constant 1/6✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.773

hard Video
Evaluate \( \displaystyle \lim_{x \to - \frac{1}{3}} \frac{3 x - \sin{\left(3 x + 1 \right)} + 1}{\left(3 x + 1\right)^{3}} \).
  1. \[ \lim_{x \to - \frac{1}{3}^+}\left(\frac{3 x - \sin{\left(3 x + 1 \right)} + 1}{\left(3 x + 1\right)^{3}}\right) \]
    limitIdentify the limit to evaluate.✓ Proved
  2. \[ = \lim_{x \to - \frac{1}{3}^+}\left(\frac{\frac{d}{d x} \left(3 x - \sin{\left(3 x + 1 \right)} + 1\right)}{\frac{d}{d x} \left(3 x + 1\right)^{3}}\right) \]
    lhopitalThe limit is an indeterminate form 0/0, so apply L'Hopital's rule.✓ Proved
  3. \[ = \lim_{x \to - \frac{1}{3}^+}\left(\frac{3 - 3 \cos{\left(3 x + 1 \right)}}{9 \left(3 x + 1\right)^{2}}\right) \]
    simplify simplifyCompute the derivatives of the numerator and denominator. Simplify the expression in the denominator.✓ Proved
  4. \[ = \lim_{x \to - \frac{1}{3}^+}\left(\frac{1 - \cos{\left(3 x + 1 \right)}}{3 \left(3 x + 1\right)^{2}}\right) \]
    algebraDivide the numerator and denominator by 3.✓ Proved
  5. \[ = \lim_{x \to - \frac{1}{3}^+}\left(\frac{2 \sin^{2}{\left(\frac{3 x}{2} + \frac{1}{2} \right)}}{3 \left(3 x + 1\right)^{2}}\right) \]
    rewrite substitutionUse the trigonometric identity 1 - cos(2theta) = 2*sin(theta)^2. Let u = 3*x + 1, so u approaches 0 as x approaches -1/3.✓ Proved
  6. \[ = \lim_{u \to 0^+}\left(\frac{2 \sin^{2}{\left(\frac{u}{2} \right)}}{3 u^{2}}\right) \]
    substitutionSubstitute u with 3*x + 1.✓ Proved
  7. \[ = \lim_{u \to 0^+} \frac{1}{6} \]
    trig-limit simplify simplifyUse the small angle approximation sin(theta) ~ theta for the limit. Expand the squared term. Cancel the u**2 terms and simplify the constant.✓ Proved
  8. \[ = \frac{1}{6} \]
    limitThe limit evaluates to the constant value.✓ Proved
Answer \( \frac{1}{6} \)
The graph of f(x) = (3x - sin(3x + 1) + 1)/(3x + 1)³. Two points slide along the curve toward x = -1/3, one from each side; their heights close in on 1/6.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to - \frac{1}{3}^+}\left(\frac{3 x - \sin{\left(3 x + 1 \right)} + 1}{\left(3 x + 1\right)^{3}}\right) \]
    limit algebra✓ Proved
  2. \[ = \lim_{x \to - \frac{1}{3}^+}\left(\frac{\frac{d}{d x} \left(3 x - \sin{\left(3 x + 1 \right)} + 1\right)}{\frac{d}{d x} \left(3 x + 1\right)^{3}}\right) \]
    lhopital✓ Proved
  3. \[ = \lim_{x \to - \frac{1}{3}^+}\left(\frac{3 - 3 \cos{\left(3 x + 1 \right)}}{9 \left(3 x + 1\right)^{2}}\right) \]
    simplify✓ Proved
  4. \[ = \lim_{x \to - \frac{1}{3}^+}\left(\frac{\frac{d}{d x} \left(3 - 3 \cos{\left(3 x + 1 \right)}\right)}{\frac{d}{d x} 9 \left(3 x + 1\right)^{2}}\right) \]
    lhopital✓ Proved
  5. \[ = \lim_{x \to - \frac{1}{3}^+}\left(\frac{9 \sin{\left(3 x + 1 \right)}}{162 x + 54}\right) \]
    simplify✓ Proved
  6. \[ = \lim_{x \to - \frac{1}{3}^+}\left(\frac{\frac{d}{d x} 9 \sin{\left(3 x + 1 \right)}}{\frac{d}{d x} \left(162 x + 54\right)}\right) \]
    lhopital✓ Proved
  7. \[ = \lim_{x \to - \frac{1}{3}^+}\left(\frac{\cos{\left(3 x + 1 \right)}}{6}\right) \]
    simplify limit✓ Proved
  8. \[ = \frac{1}{6} \]
    limit✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.822

hard Video
Evaluate \( \displaystyle \lim_{x \to - \frac{1}{2}} \frac{- 2 x + e^{2 x + 1} - 2}{\left(2 x + 1\right)^{2}} \).
  1. \[ \lim_{x \to - \frac{1}{2}^+}\left(\frac{- 2 x + e^{2 x + 1} - 2}{\left(2 x + 1\right)^{2}}\right) \]
    limitEvaluate the limit of the given function.✓ Proved
  2. \[ = \lim_{x \to - \frac{1}{2}^+}\left(\frac{- 2 x + e^{2 x + 1} - 2}{4 \left(x + \frac{1}{2}\right)^{2}}\right) \]
    algebraRewrite the denominator by expanding (2x + 1)**2.✓ Proved
  3. \[ = \lim_{x \to - \frac{1}{2}^+}\left(\frac{\frac{d}{d x} \left(- 2 x + e^{2 x + 1} - 2\right)}{\frac{d}{d x} 4 \left(x + \frac{1}{2}\right)^{2}}\right) \]
    lhopitalApply L'Hopital's rule since the limit is of the form 0/0.✓ Proved
  4. \[ = \lim_{x \to - \frac{1}{2}^+}\left(\frac{2 e^{2 x + 1} - 2}{8 x + 4}\right) \]
    simplify substitutionCalculate the derivatives of the numerator and denominator. Let u = x + 1/2, so x = u - 1/2.✓ Proved
  5. \[ = \lim_{u \to 0^+}\left(\frac{2 e^{2 u} - 2}{8 u}\right) \]
    substitution factorRewrite the limit in terms of u. Factor out the constant 2 from the numerator.✓ Proved
  6. \[ = \lim_{u \to 0^+}\left(\frac{e^{2 u} - 1}{4 u}\right) \]
    simplifySimplify the fraction.✓ Proved
  7. \[ = \lim_{u \to 0^+}\left(\frac{\frac{d}{d u} \left(e^{2 u} - 1\right)}{\frac{d}{d u} 4 u}\right) \]
    lhopitalApply L'Hopital's rule again to the expression in terms of u.✓ Proved
  8. \[ = \lim_{u \to 0^+}\left(\frac{e^{2 u}}{2}\right) \]
    simplify simplifyCalculate the derivatives. Simplify the resulting fraction.✓ Proved
  9. \[ = \frac{1}{2} \]
    limitEvaluate the limit as u approaches 0.✓ Proved
Answer \( \frac{1}{2} \)
The graph of f(x) = (-2x + e^(2x + 1) - 2)/(2x + 1)². Two points slide along the curve toward x = -1/2, one from each side; their heights close in on 1/2.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to - \frac{1}{2}^+}\left(\frac{- 2 x + e^{2 x + 1} - 2}{\left(2 x + 1\right)^{2}}\right) \]
    limit✓ Proved
  2. \[ = \lim_{x \to - \frac{1}{2}^+}\left(\frac{\frac{d}{d x} \left(- 2 x + e^{2 x + 1} - 2\right)}{\frac{d}{d x} \left(2 x + 1\right)^{2}}\right) \]
    lhopital✓ Proved
  3. \[ = \lim_{x \to - \frac{1}{2}^+}\left(\frac{2 e^{2 x + 1} - 2}{8 x + 4}\right) \]
    simplify✓ Proved
  4. \[ = \lim_{x \to - \frac{1}{2}^+}\left(\frac{\frac{d}{d x} \left(2 e^{2 x + 1} - 2\right)}{\frac{d}{d x} \left(8 x + 4\right)}\right) \]
    lhopital✓ Proved
  5. \[ = \lim_{x \to - \frac{1}{2}^+}\left(\frac{e^{2 x + 1}}{2}\right) \]
    simplify simplify✓ Proved
  6. \[ = \frac{1}{2} \]
    limit✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.525

medium Video
Evaluate \( \displaystyle \lim_{x \to \frac{1}{3}} \frac{- 3 x + e^{3 x - 1}}{\left(3 x - 1\right)^{2}} \).
  1. \[ \lim_{x \to \frac{1}{3}^+}\left(\frac{- 3 x + e^{3 x - 1}}{\left(3 x - 1\right)^{2}}\right) \]
    limit algebraDefine the limit from the right. Rearrange the numerator.✓ Proved
  2. \[ = \lim_{x \to \frac{1}{3}^+}\left(\frac{\frac{d}{d x} \left(- 3 x + e^{3 x - 1}\right)}{\frac{d}{d x} \left(3 x - 1\right)^{2}}\right) \]
    lhopitalApply L'Hopital's rule since the limit is 0/0.✓ Proved
  3. \[ = \lim_{x \to \frac{1}{3}^+}\left(\frac{3 e^{3 x - 1} - 3}{18 x - 6}\right) \]
    simplify algebra factorCompute the derivatives. Simplify the denominator. Factor out 3 from the numerator.✓ Proved
  4. \[ = \lim_{x \to \frac{1}{3}^+}\left(\frac{e^{3 x - 1} - 1}{6 x - 2}\right) \]
    algebraSimplify the fraction.✓ Proved
  5. \[ = \lim_{x \to \frac{1}{3}^+}\left(\frac{\frac{d}{d x} \left(e^{3 x - 1} - 1\right)}{\frac{d}{d x} \left(6 x - 2\right)}\right) \]
    lhopitalApply L'Hopital's rule again.✓ Proved
  6. \[ = \lim_{x \to \frac{1}{3}^+}\left(\frac{e^{3 x - 1}}{2}\right) \]
    simplify algebra algebraCompute the derivatives. Simplify the fraction. Reduce the fraction.✓ Proved
  7. \[ = \frac{1}{2} \]
    limit algebra simplifyEvaluate the limit by substitution. Simplify the exponent. Final evaluation.✓ Proved
Answer \( \frac{1}{2} \)
The graph of f(x) = (-3x + e^(3x - 1))/(3x - 1)². Two points slide along the curve toward x = 1/3, one from each side; their heights close in on 1/2.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to \frac{1}{3}^+}\left(\frac{- 3 x + e^{3 x - 1}}{\left(3 x - 1\right)^{2}}\right) \]
    limit✓ Proved
  2. \[ = \lim_{x \to \frac{1}{3}^+}\left(\frac{3 e^{3 x - 1} - 3}{18 x - 6}\right) \]
    lhopitalApply l'Hôpital's rule once✓ Proved
  3. \[ = \lim_{x \to \frac{1}{3}^+}\left(\frac{e^{3 x - 1}}{2}\right) \]
    lhopital simplifyApply l'Hôpital's rule again Simplify the constant factor✓ Proved
  4. \[ = \frac{1}{2} \]
    limitEvaluate the remaining limit✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.461

medium Video
Evaluate \( \displaystyle \lim_{x \to \infty} \left(2 x + 1\right)^{2} e^{- 2 x - 1} \).
  1. \[ \lim_{x \to \infty}\left(\left(2 x + 1\right)^{2} e^{- 2 x - 1}\right) \]
    limit rewriteStart with the original limit. Rewrite the negative exponent as a fraction.✓ Proved
  2. \[ = \lim_{x \to \infty}\left(\left(4 x^{2} + 4 x + 1\right) e^{- 2 x - 1}\right) \]
    algebraExpand the squared binomial.✓ Proved
  3. \[ = \lim_{x \to \infty}\left(\frac{\frac{d}{d x} \left(4 x^{2} + 4 x + 1\right)}{\frac{d}{d x} e^{2 x + 1}}\right) \]
    lhopitalApply L'Hopital's rule because it is an indeterminate form of type infinity/infinity.✓ Proved
  4. \[ = \lim_{x \to \infty}\left(\frac{\left(8 x + 4\right) e^{- 2 x - 1}}{2}\right) \]
    simplifyCompute the derivatives.✓ Proved
  5. \[ = \lim_{x \to \infty}\left(\left(4 x + 2\right) e^{- 2 x - 1}\right) \]
    simplifyDivide the numerator and denominator by 2.✓ Proved
  6. \[ = \lim_{x \to \infty}\left(\frac{\left(4 x + 2\right) e^{- 2 x}}{e}\right) \]
    algebraSplit the exponential term.✓ Proved
  7. \[ = \frac{\lim_{x \to \infty}\left(\left(4 x + 2\right) e^{- 2 x}\right)}{e} \]
    limit-lawApply the limit law for products.✓ Proved
  8. \[ = \frac{\lim_{x \to \infty}\left(\frac{\frac{d}{d x} \left(4 x + 2\right)}{\frac{d}{d x} e^{2 x}}\right)}{e} \]
    lhopitalApply L'Hopital's rule again.✓ Proved
  9. \[ = \frac{\lim_{x \to \infty}\left(2 e^{- 2 x}\right)}{e} \]
    simplify simplifyCompute the derivatives. Simplify the fraction.✓ Proved
  10. \[ = 0 \]
    limit simplifyEvaluate the remaining limit. Final result.✓ Proved
Answer \( 0 \)
The graph of f(x) = (2x + 1)²·e^(-2x - 1). A point runs right along the curve; its height settles toward 0.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to \infty}\left(\left(2 x + 1\right)^{2} e^{- 2 x - 1}\right) \]
    limit✓ Proved
  2. \[ = \lim_{x \to \infty}\left(\frac{\left(2 x + 1\right)^{2} e^{- 2 x}}{e}\right) \]
    rewriteSeparate the constant factor exp(-1)✓ Proved
  3. \[ = \frac{\lim_{x \to \infty}\left(\left(2 x + 1\right)^{2} e^{- 2 x}\right)}{e} \]
    factorFactor out the constant exp(-1)✓ Proved
  4. \[ = 0 \]
    limit simplifyThe product (2*x+1)**2*exp(-2*x) tends to 0 as x→∞ Multiply by exp(-1) gives 0✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.74

medium Video
Evaluate \( \displaystyle \lim_{x \to 0} \frac{- 3 x + e^{3 x} - 1}{9 x^{2}} \).
  1. \[ \lim_{x \to 0^+}\left(\frac{- 3 x + e^{3 x} - 1}{9 x^{2}}\right) \]
    limit algebraIdentify the limit to be evaluated. Rearrange the terms in the numerator.✓ Proved
  2. \[ = \lim_{x \to 0^+}\left(\frac{\frac{d}{d x} \left(- 3 x + e^{3 x} - 1\right)}{\frac{d}{d x} 9 x^{2}}\right) \]
    lhopitalApply L'Hépital's rule because the limit is an indeterminate form 0/0.✓ Proved
  3. \[ = \lim_{x \to 0^+}\left(\frac{3 e^{3 x} - 3}{18 x}\right) \]
    simplify factorCompute the derivatives. Factor out the constant 3 from the numerator.✓ Proved
  4. \[ = \lim_{x \to 0^+}\left(\frac{e^{3 x} - 1}{6 x}\right) \]
    simplifySimplify the fraction by dividing 3/18.✓ Proved
  5. \[ = \lim_{x \to 0^+}\left(\frac{\frac{d}{d x} \left(e^{3 x} - 1\right)}{\frac{d}{d x} 6 x}\right) \]
    lhopitalApply L'Hépital's rule again as it is still 0/0.✓ Proved
  6. \[ = \lim_{x \to 0^+}\left(\frac{e^{3 x}}{2}\right) \]
    simplify simplifyCompute the derivatives. Simplify the fraction 3/6 to 1/2.✓ Proved
  7. \[ = \frac{1}{2} \]
    limit simplifyEvaluate the limit by substituting x = 0. Final result.✓ Proved
Answer \( \frac{1}{2} \)
The graph of f(x) = (-3x + e^(3x) - 1)/(9x²). Two points slide along the curve toward x = 0, one from each side; their heights close in on 1/2.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to 0^+}\left(\frac{- 3 x + e^{3 x} - 1}{9 x^{2}}\right) \]
    limit✓ Proved
  2. \[ = \lim_{x \to 0^+} \frac{1}{2} \]
    rewrite simplifyUse the Taylor expansion exp(3*x)=1+3*x+9/2*x**2+… Cancel the common factor 9*x**2✓ Proved
  3. \[ = \frac{1}{2} \]
    limitThe limit of a constant is the constant itself✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.51

medium Video
Evaluate \( \displaystyle \lim_{x \to 0} \frac{2 x - \sin{\left(2 x \right)}}{8 x^{3}} \).
  1. \[ \lim_{x \to 0^+}\left(\frac{2 x - \sin{\left(2 x \right)}}{8 x^{3}}\right) \]
    limitStart with the original limit.✓ Proved
  2. \[ = \lim_{x \to 0^+}\left(\frac{\frac{d}{d x} \left(2 x - \sin{\left(2 x \right)}\right)}{\frac{d}{d x} 8 x^{3}}\right) \]
    lhopitalApply L'Hopital's rule because the limit is an indeterminate form 0/0.✓ Proved
  3. \[ = \lim_{x \to 0^+}\left(\frac{2 - 2 \cos{\left(2 x \right)}}{24 x^{2}}\right) \]
    simplify factorCompute the derivatives. Factor out the constant 2.✓ Proved
  4. \[ = \lim_{x \to 0^+}\left(\frac{1 - \cos{\left(2 x \right)}}{12 x^{2}}\right) \]
    simplifySimplify the fraction.✓ Proved
  5. \[ = \lim_{x \to 0^+}\left(\frac{2 x^{2} + O\left(x^{4}\right)}{12 x^{2}}\right) \]
    rewriteUse the Taylor series expansion for cos(2x).✓ Proved
  6. \[ = \lim_{x \to 0^+} \frac{1}{6} \]
    simplify algebra cancelKeep the leading term of the expansion. Expand the squared term. Cancel the x**2 terms.✓ Proved
  7. \[ = \frac{1}{6} \]
    simplifyFinal evaluation.✓ Proved
Answer \( \frac{1}{6} \)
The graph of f(x) = (2x - sin(2x))/(8x³). Two points slide along the curve toward x = 0, one from each side; their heights close in on 1/6.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to 0^+}\left(\frac{2 x - \sin{\left(2 x \right)}}{8 x^{3}}\right) \]
    limit✓ Proved
  2. \[ = \lim_{x \to 0^+} \frac{1}{6} \]
    rewrite simplify cancelreplace sin(2*x) by its series 2*x - 8*x**3/6 subtract the 2*x terms cancel 8*x**3 in numerator and denominator✓ Proved
  3. \[ = \frac{1}{6} \]
    limitevaluate the constant limit✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.110

medium Video
Evaluate \( \displaystyle \lim_{x \to \infty} 4 x^{2} e^{- 2 x} \).
  1. \[ \lim_{x \to \infty}\left(4 x^{2} e^{- 2 x}\right) \]
    limit rewriteEvaluate the limit of the function as x approaches infinity. Rewrite the negative exponent as a fraction.✓ Proved
  2. \[ = \lim_{x \to \infty}\left(\frac{\frac{d}{d x} 4 x^{2}}{\frac{d}{d x} e^{2 x}}\right) \]
    lhopitalApply L'Hopital's rule because the limit is an indeterminate form of type infinity/infinity.✓ Proved
  3. \[ = \lim_{x \to \infty}\left(4 x e^{- 2 x}\right) \]
    simplify simplifyCompute the derivatives in the numerator and denominator. Simplify the fraction by canceling the common factor of 2.✓ Proved
  4. \[ = \lim_{x \to \infty}\left(\frac{\frac{d}{d x} 4 x}{\frac{d}{d x} e^{2 x}}\right) \]
    lhopitalApply L'Hopital's rule again.✓ Proved
  5. \[ = \lim_{x \to \infty}\left(2 e^{- 2 x}\right) \]
    simplify simplify rewriteCompute the derivatives in the numerator and denominator. Simplify the fraction. Rewrite the expression using a positive exponent.✓ Proved
  6. \[ = 0 \]
    limitThe limit of exp(-2x) as x approaches infinity is 0.✓ Proved
Answer \( 0 \)
The graph of f(x) = 4x²·e^(-2x). A point runs right along the curve; its height settles toward 0.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to \infty}\left(4 x^{2} e^{- 2 x}\right) \]
    limit rewriteRewrite exp(-2*x) as 1/exp(2*x).✓ Proved
  2. \[ = \lim_{x \to \infty}\left(4 x e^{- 2 x}\right) \]
    lhopitalApply l'Hôpital's rule once.✓ Proved
  3. \[ = \lim_{x \to \infty}\left(2 e^{- 2 x}\right) \]
    lhopitalApply l'Hôpital's rule again.✓ Proved
  4. \[ = 0 \]
    limitAs x→∞, exp(2*x) dominates, so the limit is 0.✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.360

medium Video
Evaluate \( \displaystyle \lim_{x \to \infty} \left(3 x - 1\right)^{2} e^{1 - 3 x} \).
  1. \[ \lim_{x \to \infty}\left(\left(3 x - 1\right)^{2} e^{1 - 3 x}\right) \]
    limit rewriteEvaluate the limit of the function as x approaches infinity. Rewrite the exponential term using a negative exponent.✓ Proved
  2. \[ = \lim_{x \to \infty}\left(\left(9 x^{2} - 6 x + 1\right) e^{1 - 3 x}\right) \]
    algebraExpand the squared binomial.✓ Proved
  3. \[ = \lim_{x \to \infty}\left(\frac{\frac{d}{d x} \left(9 x^{2} - 6 x + 1\right)}{\frac{d}{d x} e^{3 x - 1}}\right) \]
    lhopitalApply L'Hopital's Rule because the limit is in the form infinity/infinity.✓ Proved
  4. \[ = \lim_{x \to \infty}\left(\frac{\left(18 x - 6\right) e^{1 - 3 x}}{3}\right) \]
    simplifyCompute the derivatives of the numerator and denominator.✓ Proved
  5. \[ = \lim_{x \to \infty}\left(\frac{\frac{d}{d x} \left(18 x - 6\right)}{\frac{d}{d x} 3 e^{3 x - 1}}\right) \]
    lhopitalApply L'Hopital's Rule again.✓ Proved
  6. \[ = \lim_{x \to \infty}\left(2 e^{1 - 3 x}\right) \]
    simplify simplifyCompute the derivatives of the numerator and denominator. Simplify the fraction.✓ Proved
  7. \[ = \lim_{x \to \infty} 0 \]
    infinityAs x approaches infinity, the exponent approaches infinity.✓ Proved
  8. \[ = 0 \]
    limitThe limit of 2/exp(infinity) is 0.✓ Proved
Answer \( 0 \)
The graph of f(x) = (3x - 1)²·e^(1 - 3x). A point runs right along the curve; its height settles toward 0.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to \infty}\left(\left(3 x - 1\right)^{2} e^{1 - 3 x}\right) \]
    limit✓ Proved
  2. \[ = \lim_{x \to \infty}\left(e \left(3 x - 1\right)^{2} e^{- 3 x}\right) \]
    rewrite factorSplit the exponential using exp(a+b)=exp(a)*exp(b). Factor out the constant exp(1).✓ Proved
  3. \[ = \lim_{x \to \infty}\left(\left(3 x - 1\right)^{2} e^{- 3 x}\right) \]
    limitSince exp(1) is a constant, it can be omitted from the limit.✓ Proved
  4. \[ = 0 \]
    limitThe exponential term exp(-3*x) decays faster than any polynomial, so the product tends to 0.✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.114

medium Video
Evaluate \( \displaystyle \lim_{x \to \infty} \left(x + 1\right)^{2} e^{- x - 1} \).
  1. \[ \lim_{x \to \infty}\left(\left(x + 1\right)^{2} e^{- x - 1}\right) \]
    limit rewriteEvaluate the limit of the function as x approaches infinity. Rewrite the negative exponent using the property exp(-a) = 1/exp(a).✓ Proved
  2. \[ = \lim_{x \to \infty}\left(\left(x^{2} + 2 x + 1\right) e^{- x - 1}\right) \]
    algebraExpand the numerator.✓ Proved
  3. \[ = \lim_{x \to \infty}\left(\frac{\frac{d}{d x} \left(x^{2} + 2 x + 1\right)}{\frac{d}{d x} e^{x + 1}}\right) \]
    lhopitalApply L'Hopital's Rule because the limit is an indeterminate form of type infinity/infinity.✓ Proved
  4. \[ = \lim_{x \to \infty}\left(\left(2 x + 2\right) e^{- x - 1}\right) \]
    simplifyCompute the derivatives of the numerator and denominator.✓ Proved
  5. \[ = \lim_{x \to \infty}\left(\frac{\frac{d}{d x} \left(2 x + 2\right)}{\frac{d}{d x} e^{x + 1}}\right) \]
    lhopitalApply L'Hopital's Rule again.✓ Proved
  6. \[ = \lim_{x \to \infty}\left(2 e^{- x - 1}\right) \]
    simplifyCompute the derivatives of the numerator and denominator.✓ Proved
  7. \[ = \lim_{x \to \infty} 0 \]
    infinityAs x approaches infinity, exp(x + 1) approaches infinity.✓ Proved
  8. \[ = 0 \]
    limitThe limit is 0.✓ Proved
Answer \( 0 \)
The graph of f(x) = (x + 1)²·e^(-x - 1). A point runs right along the curve; its height settles toward 0.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to \infty}\left(\left(x + 1\right)^{2} e^{- x - 1}\right) \]
    limit✓ Proved
  2. \[ = \lim_{x \to \infty}\left(\frac{\left(x + 1\right)^{2} e^{- x}}{e}\right) \]
    rewrite rewriteSplit the exponential: exp(-x-1)=exp(-x)*exp(-1). Rewrite exp(-x) as 1/exp(x).✓ Proved
  3. \[ = \frac{\lim_{x \to \infty}\left(\left(x + 1\right)^{2} e^{- x}\right)}{e} \]
    limit-lawTake the constant exp(-1) outside the limit.✓ Proved
  4. \[ = \lim_{x \to \infty}\left(\left(2 x + 2\right) e^{- x}\right) \]
    lhopitalApply l'Hôpital to (x+1)**2/exp(x).✓ Proved
  5. \[ = \lim_{x \to \infty}\left(2 e^{- x}\right) \]
    lhopitalApply l'Hôpital again to 2*(x+1)/exp(x).✓ Proved
  6. \[ = 0 \]
    limitAs x→∞, 2/exp(x)→0.✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.357

medium Video
Evaluate \( \displaystyle \lim_{x \to -1} \frac{x - \sin{\left(x + 1 \right)} + 1}{\left(x + 1\right)^{3}} \).
  1. \[ \lim_{x \to -1^+}\left(\frac{x - \sin{\left(x + 1 \right)} + 1}{\left(x + 1\right)^{3}}\right) \]
    limitEvaluate the limit of the function at x = -1.✓ Proved
  2. \[ = \lim_{x \to -1^+}\left(\frac{\frac{d}{d x} \left(x - \sin{\left(x + 1 \right)} + 1\right)}{\frac{d}{d x} \left(x + 1\right)^{3}}\right) \]
    lhopitalApply L'Hopital's Rule because the limit is an indeterminate form 0/0.✓ Proved
  3. \[ = \lim_{x \to -1^+}\left(\frac{1 - \cos{\left(x + 1 \right)}}{3 \left(x + 1\right)^{2}}\right) \]
    simplifyCompute the derivatives in the numerator and denominator.✓ Proved
  4. \[ = \lim_{u \to 0^+}\left(\frac{1 - \cos{\left(u \right)}}{3 u^{2}}\right) \]
    substitutionUse the substitution u = x + 1, which implies u approaches 0 as x approaches -1.✓ Proved
  5. \[ = \lim_{u \to 0^+}\left(\frac{\frac{d}{d u} \left(1 - \cos{\left(u \right)}\right)}{\frac{d}{d u} 3 u^{2}}\right) \]
    lhopitalApply L'Hopital's Rule to the new limit.✓ Proved
  6. \[ = \lim_{u \to 0^+}\left(\frac{\sin{\left(u \right)}}{6 u}\right) \]
    simplifyCompute the derivatives.✓ Proved
  7. \[ = \lim_{u \to 0^+}\left(\frac{\frac{d}{d u} \sin{\left(u \right)}}{\frac{d}{d u} 6 u}\right) \]
    lhopitalApply L'Hopital's Rule again.✓ Proved
  8. \[ = \lim_{u \to 0^+}\left(\frac{\cos{\left(u \right)}}{6}\right) \]
    simplifyCompute the derivatives.✓ Proved
  9. \[ = \frac{1}{6} \]
    limitEvaluate the final limit.✓ Proved
Answer \( \frac{1}{6} \)
The graph of f(x) = (x - sin(x + 1) + 1)/(x + 1)³. Two points slide along the curve toward x = -1, one from each side; their heights close in on 1/6.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to -1^+}\left(\frac{x - \sin{\left(x + 1 \right)} + 1}{\left(x + 1\right)^{3}}\right) \]
    limit algebraStart with the original limit Rewrite numerator✓ Proved
  2. \[ = \lim_{t \to 0^+}\left(\frac{t - \sin{\left(t \right)}}{t^{3}}\right) \]
    substitutionLet t = x + 1✓ Proved
  3. \[ = \lim_{t \to 0^+}\left(\frac{\frac{d}{d t} \left(t - \sin{\left(t \right)}\right)}{\frac{d}{d t} t^{3}}\right) \]
    lhopitalApply l'Hôpital once✓ Proved
  4. \[ = \lim_{t \to 0^+}\left(\frac{1 - \cos{\left(t \right)}}{3 t^{2}}\right) \]
    simplifyCompute derivatives✓ Proved
  5. \[ = \lim_{t \to 0^+}\left(\frac{\frac{d}{d t} \left(1 - \cos{\left(t \right)}\right)}{\frac{d}{d t} 3 t^{2}}\right) \]
    lhopitalApply l'Hôpital again✓ Proved
  6. \[ = \lim_{t \to 0^+}\left(\frac{\sin{\left(t \right)}}{6 t}\right) \]
    simplifyCompute derivatives✓ Proved
  7. \[ = \lim_{t \to 0^+}\left(\frac{\frac{d}{d t} \sin{\left(t \right)}}{\frac{d}{d t} 6 t}\right) \]
    lhopitalApply l'Hôpital third time✓ Proved
  8. \[ = \lim_{t \to 0^+}\left(\frac{\cos{\left(t \right)}}{6}\right) \]
    simplifyCompute derivatives✓ Proved
  9. \[ = \frac{1}{6} \]
    limitFinal value of the limit✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.424

medium Video
Evaluate \( \displaystyle \lim_{x \to \infty} \left(x - 1\right)^{2} e^{1 - x} \).
  1. \[ \lim_{x \to \infty}\left(\left(x - 1\right)^{2} e^{1 - x}\right) \]
    limit rewriteStart with the original limit. Rewrite the exponential term using negative exponents.✓ Proved
  2. \[ = \lim_{x \to \infty}\left(\left(x^{2} - 2 x + 1\right) e^{1 - x}\right) \]
    algebraExpand the squared binomial.✓ Proved
  3. \[ = \lim_{x \to \infty}\left(\frac{\frac{d}{d x} \left(x^{2} - 2 x + 1\right)}{\frac{d}{d x} e^{x - 1}}\right) \]
    lhopitalApply L'Hopital's rule since the limit is of the form infinity/infinity.✓ Proved
  4. \[ = \lim_{x \to \infty}\left(\left(2 x - 2\right) e^{1 - x}\right) \]
    simplifyCompute the derivatives.✓ Proved
  5. \[ = \lim_{x \to \infty}\left(\frac{\frac{d}{d x} \left(2 x - 2\right)}{\frac{d}{d x} e^{x - 1}}\right) \]
    lhopitalApply L'Hopital's rule again.✓ Proved
  6. \[ = \lim_{x \to \infty}\left(2 e^{1 - x}\right) \]
    simplifyCompute the derivatives.✓ Proved
  7. \[ = \lim_{x \to \infty} 0 \]
    infinityEvaluate the limit as x approaches infinity.✓ Proved
  8. \[ = 0 \]
    limitThe final value of the limit.✓ Proved
Answer \( 0 \)
The graph of f(x) = (x - 1)²·e^(1 - x). A point runs right along the curve; its height settles toward 0.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to \infty}\left(\left(x - 1\right)^{2} e^{1 - x}\right) \]
    limit✓ Proved
  2. \[ = \lim_{x \to \infty}\left(e \left(x - 1\right)^{2} e^{- x}\right) \]
    rewriteRewrite exp(1 - x) as exp(1)*exp(-x).✓ Proved
  3. \[ = e \lim_{x \to \infty}\left(\left(x - 1\right)^{2} e^{- x}\right) \]
    factor rewriteFactor out the constant exp(1). Rewrite exp(-x) as 1/exp(x).✓ Proved
  4. \[ = e \lim_{x \to \infty}\left(\left(2 x - 2\right) e^{- x}\right) \]
    lhopitalApply l'Hôpital's rule once: derivative of numerator 2*(x-1), derivative of denominator exp(x).✓ Proved
  5. \[ = e \lim_{x \to \infty}\left(2 e^{- x}\right) \]
    lhopitalApply l'Hôpital's rule again: derivative of numerator 2, derivative of denominator exp(x).✓ Proved
  6. \[ = 0 \]
    limit simplifyAs x→∞, exp(x)→∞, so 2/exp(x)→0. Multiply by exp(1) gives 0.✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.232

medium Video
Evaluate \( \displaystyle \lim_{x \to 0} \frac{e^{4 x} - 1}{\sin{\left(2 x \right)}} \).
  1. \[ \lim_{x \to 0^+}\left(\frac{e^{4 x} - 1}{\sin{\left(2 x \right)}}\right) \]
    limitStart with the limit of the given function.✓ Proved
  2. \[ = \lim_{x \to 0^+}\left(\frac{\frac{d}{d x} \left(e^{4 x} - 1\right)}{\frac{d}{d x} \sin{\left(2 x \right)}}\right) \]
    lhopitalApply L'Hôpital's rule because the limit is an indeterminate form 0/0.✓ Proved
  3. \[ = \lim_{x \to 0^+}\left(\frac{2 e^{4 x}}{\cos{\left(2 x \right)}}\right) \]
    simplify simplify limitCompute the derivatives in the numerator and denominator. Simplify the fraction by canceling the common factor of 2. The expression is now continuous at x = 0.✓ Proved
  4. \[ = 2 \]
    substitution simplify simplifySubstitute x = 0 into the expression. Evaluate the exponential and trigonometric functions at 0. Final result.✓ Proved
Answer \( 2 \)
The graph of f(x) = (e^(4x) - 1)/sin(2x). Two points slide along the curve toward x = 0, one from each side; their heights close in on 2.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to 0^+}\left(\frac{e^{4 x} - 1}{\sin{\left(2 x \right)}}\right) \]
    limit✓ Proved
  2. \[ = \lim_{x \to 0^+}\left(\frac{\frac{d}{d x} \left(e^{4 x} - 1\right)}{\frac{d}{d x} \sin{\left(2 x \right)}}\right) \]
    lhopitalApply l'Hôpital's rule✓ Proved
  3. \[ = \lim_{x \to 0^+}\left(\frac{2 e^{4 x}}{\cos{\left(2 x \right)}}\right) \]
    simplifyCompute the derivatives✓ Proved
  4. \[ = 2 \]
    limitEvaluate the limit by substitution✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.254

medium Video
Evaluate \( \displaystyle \lim_{x \to \infty} \left(2 x - 1\right) e^{1 - 2 x} \).
  1. \[ \lim_{x \to \infty}\left(\left(2 x - 1\right) e^{1 - 2 x}\right) \]
    limitStart with the original limit expression.✓ Proved
  2. \[ = \lim_{x \to \infty}\left(e \left(2 x - 1\right) e^{- 2 x}\right) \]
    rewrite algebraRewrite the exponential term using properties of exponents. Rearrange the terms for clarity.✓ Proved
  3. \[ = \lim_{x \to \infty}\left(\frac{\frac{d}{d x} e \left(2 x - 1\right)}{\frac{d}{d x} e^{2 x}}\right) \]
    lhopitalApply L'Hopital's rule because the limit is of the form infinity/infinity.✓ Proved
  4. \[ = \lim_{x \to \infty}\left(e e^{- 2 x}\right) \]
    simplify simplifyCompute the derivatives of the numerator and denominator. Cancel the common factor of 2.✓ Proved
  5. \[ = \lim_{x \to \infty} e^{1 - 2 x} \]
    algebraCombine the exponential terms.✓ Proved
  6. \[ = 0 \]
    limitAs x approaches infinity, the exponential term approaches zero.✓ Proved
Answer \( 0 \)
The graph of f(x) = (2x - 1)·e^(1 - 2x). A point runs right along the curve; its height settles toward 0.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to \infty}\left(\left(2 x - 1\right) e^{1 - 2 x}\right) \]
    limit✓ Proved
  2. \[ = \lim_{x \to \infty}\left(e \left(2 x - 1\right) e^{- 2 x}\right) \]
    factorSeparate the constant exp(1) from the exponential.✓ Proved
  3. \[ = e \lim_{x \to \infty}\left(\left(2 x - 1\right) e^{- 2 x}\right) \]
    limit-lawPull out the constant factor from the limit.✓ Proved
  4. \[ = e \lim_{x \to \infty}\left(2 x e^{- 2 x} - e^{- 2 x}\right) \]
    algebraDistribute the exponential over the sum.✓ Proved
  5. \[ = e \left(\lim_{x \to \infty}\left(2 x e^{- 2 x}\right) - \lim_{x \to \infty} e^{- 2 x}\right) \]
    limit-lawSplit the limit of a difference.✓ Proved
  6. \[ = e \lim_{x \to \infty}\left(2 x e^{- 2 x}\right) \]
    limit limit-lawexp(-2*x) -> 0 as x -> oo. Simplify the expression.✓ Proved
  7. \[ = 2 e \lim_{x \to \infty}\left(x e^{- 2 x}\right) \]
    factor limit-lawTake the constant 2 out of the limit. Reorder constants.✓ Proved
  8. \[ = 0 \]
    limit limitx*exp(-2*x) -> 0 as x -> oo. Final value of the limit.✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.313

medium Video
Evaluate \( \displaystyle \lim_{x \to \frac{1}{2}} \frac{e^{4 x - 2} - 1}{\sin{\left(2 x - 1 \right)}} \).
  1. \[ \lim_{x \to \frac{1}{2}^+}\left(\frac{e^{4 x - 2} - 1}{\sin{\left(2 x - 1 \right)}}\right) \]
    limitStart with the original limit.✓ Proved
  2. \[ = \lim_{x \to \frac{1}{2}^+}\left(\frac{\frac{d}{d x} \left(e^{4 x - 2} - 1\right)}{\frac{d}{d x} \sin{\left(2 x - 1 \right)}}\right) \]
    lhopitalApply L'Hopital's rule because the limit is of the form 0/0.✓ Proved
  3. \[ = \lim_{x \to \frac{1}{2}^+}\left(\frac{2 e^{4 x - 2}}{\cos{\left(2 x - 1 \right)}}\right) \]
    simplify simplifyCompute the derivatives. Simplify the fraction by dividing by 2.✓ Proved
  4. \[ = \lim_{x \to \frac{1}{2}^+} 2 \]
    limit simplify simplifyEvaluate the limit by substituting x = 1/2. Simplify the exponents and trigonometric arguments. Evaluate the exponential and cosine functions.✓ Proved
  5. \[ = 2 \]
    simplifyFinal result.✓ Proved
Answer \( 2 \)
The graph of f(x) = (e^(4x - 2) - 1)/sin(2x - 1). Two points slide along the curve toward x = 1/2, one from each side; their heights close in on 2.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to \frac{1}{2}^+}\left(\frac{e^{4 x - 2} - 1}{\sin{\left(2 x - 1 \right)}}\right) \]
    limit rewriteRewrite using (x-1/2) to prepare for l'Hôpital.✓ Proved
  2. \[ = \lim_{x \to \frac{1}{2}^+}\left(\frac{\frac{d}{d x} \left(e^{4 x - 2} - 1\right)}{\frac{d}{d x} \sin{\left(2 x - 1 \right)}}\right) \]
    lhopital✓ Proved
  3. \[ = \lim_{x \to \frac{1}{2}^+}\left(\frac{2 e^{4 x - 2}}{\cos{\left(2 x - 1 \right)}}\right) \]
    simplify simplify✓ Proved
  4. \[ = 2 \]
    limit limit✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.330

medium Video
Evaluate \( \displaystyle \lim_{x \to 1} \frac{e^{2 x - 2} - 1}{\sin{\left(x - 1 \right)}} \).
  1. \[ \lim_{x \to 1^+}\left(\frac{e^{2 x - 2} - 1}{\sin{\left(x - 1 \right)}}\right) \]
    limit algebraEvaluate the limit of the function as x approaches 1. Rewrite the exponent to reveal the common term (x - 1).✓ Proved
  2. \[ = \lim_{x \to 1^+}\left(\frac{\frac{d}{d x} \left(e^{2 x - 2} - 1\right)}{\frac{d}{d x} \sin{\left(x - 1 \right)}}\right) \]
    lhopitalApply L'Hopital's rule since the limit results in an indeterminate form 0/0.✓ Proved
  3. \[ = \lim_{x \to 1^+}\left(\frac{2 e^{2 x - 2}}{\cos{\left(x - 1 \right)}}\right) \]
    simplifyCompute the derivatives of the numerator and denominator.✓ Proved
  4. \[ = 2 \]
    limit algebra simplify simplifyEvaluate the limit by substituting x = 1. Simplify the arguments of the exponential and trigonometric functions. Evaluate the exponential and trigonometric values. Final result.✓ Proved
Answer \( 2 \)
The graph of f(x) = (e^(2x - 2) - 1)/sin(x - 1). Two points slide along the curve toward x = 1, one from each side; their heights close in on 2.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to 1^+}\left(\frac{e^{2 x - 2} - 1}{\sin{\left(x - 1 \right)}}\right) \]
    limit rewrite factorRewrite the exponent as 2*(x-1). Factor out 2*(x-1) from the numerator.✓ Proved
  2. \[ = \lim_{x \to 1^+}\left(\frac{e^{2 x - 2} - 1}{2 x - 2}\right) \lim_{x \to 1^+}\left(\frac{2 x - 2}{\sin{\left(x - 1 \right)}}\right) \]
    limit-lawSplit the product of limits.✓ Proved
  3. \[ = \lim_{x \to 1^+}\left(\frac{2 x - 2}{\sin{\left(x - 1 \right)}}\right) \]
    limitThe first limit equals 1 because (exp(u)-1)/u -> 1 as u->0.✓ Proved
  4. \[ = 2 \]
    limit limitThe second limit equals 2 because (x-1)/sin(x-1) -> 1. Final value of the limit.✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.376

medium Video
Evaluate \( \displaystyle \lim_{x \to -1} \frac{- x + e^{x + 1} - 2}{\left(x + 1\right)^{2}} \).
  1. \[ \lim_{x \to -1^+}\left(\frac{- x + e^{x + 1} - 2}{\left(x + 1\right)^{2}}\right) \]
    limit algebraStart with the limit of the given function. Rewrite the numerator to group terms with (x + 1).✓ Proved
  2. \[ = \lim_{x \to -1^+}\left(\frac{\frac{d}{d x} \left(- x + e^{x + 1} - 2\right)}{\frac{d}{d x} \left(x + 1\right)^{2}}\right) \]
    lhopitalApply L'Hopital's rule since the limit is in the form 0/0.✓ Proved
  3. \[ = \lim_{x \to -1^+}\left(\frac{e^{x + 1} - 1}{2 x + 2}\right) \]
    simplifyCompute the derivatives in the numerator and denominator.✓ Proved
  4. \[ = \lim_{x \to -1^+}\left(\frac{\frac{d}{d x} \left(e^{x + 1} - 1\right)}{\frac{d}{d x} \left(2 x + 2\right)}\right) \]
    lhopitalApply L'Hopital's rule again since the limit is in the form 0/0.✓ Proved
  5. \[ = \lim_{x \to -1^+}\left(\frac{e^{x + 1}}{2}\right) \]
    simplifyCompute the derivatives.✓ Proved
  6. \[ = \frac{1}{2} \]
    limit simplifyEvaluate the limit by substituting x = -1. Simplify the final value.✓ Proved
Answer \( \frac{1}{2} \)
The graph of f(x) = (-x + e^(x + 1) - 2)/(x + 1)². Two points slide along the curve toward x = -1, one from each side; their heights close in on 1/2.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to -1^+}\left(\frac{- x + e^{x + 1} - 2}{\left(x + 1\right)^{2}}\right) \]
    limit✓ Proved
  2. \[ = \lim_{x \to -1^+}\left(\frac{e^{x + 1} - 1}{2 x + 2}\right) \]
    lhopital simplifyRewrite numerator✓ Proved
  3. \[ = \lim_{x \to -1^+}\left(\frac{e^{x + 1}}{2}\right) \]
    lhopital✓ Proved
  4. \[ = \frac{1}{2} \]
    limit limit✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.462

medium Video
Evaluate \( \displaystyle \lim_{x \to \frac{1}{3}} \frac{\cos{\left(3 x - 1 \right)} - 1}{e^{3 x - 1} - 1} \).
  1. \[ \lim_{x \to \frac{1}{3}^+}\left(\frac{\cos{\left(3 x - 1 \right)} - 1}{e^{3 x - 1} - 1}\right) \]
    limitStarting with the original limit.✓ Proved
  2. \[ = \lim_{x \to \frac{1}{3}^+}\left(\frac{\frac{d}{d x} \left(\cos{\left(3 x - 1 \right)} - 1\right)}{\frac{d}{d x} \left(e^{3 x - 1} - 1\right)}\right) \]
    lhopitalApply L'Hopital's rule because the limit is an indeterminate form 0/0.✓ Proved
  3. \[ = \lim_{x \to \frac{1}{3}^+}\left(- e^{1 - 3 x} \sin{\left(3 x - 1 \right)}\right) \]
    simplify simplifyCompute the derivatives. Cancel the common factor of 3.✓ Proved
  4. \[ = 0 \]
    limit algebra simplify simplifyEvaluate the limit by substituting x = 1/3. Simplify the expression inside the sine and exponential functions. Evaluate the trigonometric and exponential functions. Final result.✓ Proved
Answer \( 0 \)
The graph of f(x) = (cos(3x - 1) - 1)/(e^(3x - 1) - 1). Two points slide along the curve toward x = 1/3, one from each side; their heights close in on 0.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to \frac{1}{3}^+}\left(\frac{\cos{\left(3 x - 1 \right)} - 1}{e^{3 x - 1} - 1}\right) \]
    limit✓ Proved
  2. \[ = \lim_{u \to 0^+}\left(\frac{\cos{\left(u \right)} - 1}{e^{u} - 1}\right) \]
    substitutionLet u = 3*x - 1, so u -> 0 as x -> 1/3.✓ Proved
  3. \[ = \lim_{u \to 0^+}\left(\frac{\frac{d}{d u} \left(\cos{\left(u \right)} - 1\right)}{\frac{d}{d u} \left(e^{u} - 1\right)}\right) \]
    lhopitalApply l'Hôpital's rule because the limit is 0/0.✓ Proved
  4. \[ = \lim_{u \to 0^+}\left(- e^{- u} \sin{\left(u \right)}\right) \]
    simplifyCompute the derivatives.✓ Proved
  5. \[ = 0 \]
    limitAs u -> 0, -sin(u) -> 0 and exp(u) -> 1, so the limit is 0.✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.12

medium Video
Evaluate \( \displaystyle \lim_{x \to 0} \frac{e^{2 x} - 1}{\sin{\left(x \right)}} \).
  1. \[ \lim_{x \to 0^+}\left(\frac{e^{2 x} - 1}{\sin{\left(x \right)}}\right) \]
    limitEvaluate the limit of the given function as x approaches 0.✓ Proved
  2. \[ = \lim_{x \to 0^+}\left(\frac{\frac{d}{d x} \left(e^{2 x} - 1\right)}{\frac{d}{d x} \sin{\left(x \right)}}\right) \]
    lhopitalApply L'Hopital's rule since the limit is an indeterminate form 0/0.✓ Proved
  3. \[ = \lim_{x \to 0^+}\left(\frac{2 e^{2 x}}{\cos{\left(x \right)}}\right) \]
    simplifyCompute the derivatives of the numerator and denominator.✓ Proved
  4. \[ = \lim_{x \to 0^+}\left(2 e^{2 x}\right) \left(\lim_{x \to 0^+} \cos{\left(x \right)}\right)^{-1} \]
    limit-lawApply the quotient rule for limits.✓ Proved
  5. \[ = 2 \]
    limit simplify simplifyEvaluate the limits of the numerator and denominator separately. Simplify the exponential and trigonometric terms. Final result.✓ Proved
Answer \( 2 \)
The graph of f(x) = (e^(2x) - 1)/sin(x). Two points slide along the curve toward x = 0, one from each side; their heights close in on 2.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to 0^+}\left(\frac{e^{2 x} - 1}{\sin{\left(x \right)}}\right) \]
    limit✓ Proved
  2. \[ = \lim_{x \to 0^+}\left(\frac{\frac{d}{d x} \left(e^{2 x} - 1\right)}{\frac{d}{d x} \sin{\left(x \right)}}\right) \]
    lhopitalApply l'Hôpital's rule because 0/0 form✓ Proved
  3. \[ = \lim_{x \to 0^+}\left(\frac{2 e^{2 x}}{\cos{\left(x \right)}}\right) \]
    simplifyCompute the derivatives✓ Proved
  4. \[ = 2 \]
    limitEvaluate the limit by substitution✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Problem 1.28

medium Video
Evaluate \( \displaystyle \lim_{x \to 0} \frac{- x + e^{x} - 1}{x^{2}} \).
  1. \[ \lim_{x \to 0^+}\left(\frac{- x + e^{x} - 1}{x^{2}}\right) \]
    limit algebraStart with the limit of the given function as x approaches 0 from the right. Rearrange the terms in the numerator.✓ Proved
  2. \[ = \lim_{x \to 0^+}\left(\frac{\frac{d}{d x} \left(- x + e^{x} - 1\right)}{\frac{d}{d x} x^{2}}\right) \]
    lhopitalApply L'Hopital's rule since the limit is an indeterminate form 0/0.✓ Proved
  3. \[ = \lim_{x \to 0^+}\left(\frac{e^{x} - 1}{2 x}\right) \]
    simplifyCompute the derivatives in the numerator and denominator.✓ Proved
  4. \[ = \lim_{x \to 0^+}\left(\frac{\frac{d}{d x} \left(e^{x} - 1\right)}{\frac{d}{d x} 2 x}\right) \]
    lhopitalApply L'Hopital's rule again as the limit is still 0/0.✓ Proved
  5. \[ = \lim_{x \to 0^+}\left(\frac{e^{x}}{2}\right) \]
    simplifyCompute the derivatives.✓ Proved
  6. \[ = \frac{1}{2} \]
    limitEvaluate the limit as x approaches 0.✓ Proved
Answer \( \frac{1}{2} \)
The graph of f(x) = (-x + e^(x) - 1)/x². Two points slide along the curve toward x = 0, one from each side; their heights close in on 1/2.
A second solution, written separately

By gpt-oss:20b, without seeing the first. SymPy checked every line.

  1. \[ \lim_{x \to 0^+}\left(\frac{- x + e^{x} - 1}{x^{2}}\right) \]
    limit algebraRearrange the numerator.✓ Proved
  2. \[ = \lim_{x \to 0^+}\left(\frac{\frac{d}{d x} \left(- x + e^{x} - 1\right)}{\frac{d}{d x} x^{2}}\right) \]
    lhopitalApply l'Hôpital's rule once.✓ Proved
  3. \[ = \lim_{x \to 0^+}\left(\frac{e^{x} - 1}{2 x}\right) \]
    simplifyCompute the derivatives.✓ Proved
  4. \[ = \lim_{x \to 0^+}\left(\frac{\frac{d}{d x} \left(e^{x} - 1\right)}{\frac{d}{d x} 2 x}\right) \]
    lhopitalApply l'Hôpital's rule again.✓ Proved
  5. \[ = \lim_{x \to 0^+}\left(\frac{e^{x}}{2}\right) \]
    simplifyCompute the derivatives.✓ Proved
  6. \[ = \frac{1}{2} \]
    limitEvaluate the limit.✓ Proved

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

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