∫Calc Practice
Home›Calculus 1›L'Hôpital's rule›Problem 1.151

Limit of \( \displaystyle \frac{\ln{\left(2 x - 1 \right)}}{2 x - 1} \) as \( x \to \infty \)

Problem 1.151 · medium

Evaluate \( \displaystyle \lim_{x \to \infty} \frac{\ln{\left(2 x - 1 \right)}}{2 x - 1} \).
  1. \[ \lim_{x \to \infty}\left(\frac{\ln{\left(2 x - 1 \right)}}{2 x - 1}\right) \]
    limitStart with the original limit.✓ Proved
  2. \[ = 0 \]
    substitutionSubstitute u = 2*x - 1.✓ Proved
  3. \[ = \lim_{u \to \infty}\left(\frac{\ln{\left(u \right)}}{u}\right) \]
    limitEvaluate the limit as u approaches infinity.✓ Proved
  4. \[ = \lim_{u \to \infty}\left(\frac{\frac{d}{d u} \ln{\left(u \right)}}{\frac{d}{d u} u}\right) \]
    lhopitalApply L'Hopital's rule.✓ Proved
  5. \[ = \lim_{u \to \infty} \frac{1}{u} \]
    simplify simplifyCompute the derivatives. Simplify the fraction.✓ Proved
  6. \[ = 0 \]
    limitThe limit is 0.✓ Proved
Answer \( 0 \)

Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. A reviewer's objection to the explanation stands; see the receipt.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x - 1 = 0
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where u = 0
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where u = 0
undefined where Derivative(u, u) = 0
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where Derivative(u, u) = 0
undefined where u = 0
6✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where u = 0
7✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where u = 0
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
answer, a second way✓ Provedsympy 1.14.0SymPy took the limit from both sides and got the stated value

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly applies substitution, L'Hopital's rule, and limit evaluation. Each step changes only one aspect of the expression and uses valid labels from the fixed vocabulary.

Senior review claude-sonnet-5-5, 2026-10-04: fail — The final answer 0 is correct and the L'Hopital chain in lines 3-7 is fine. Line 2 is a malformed conditional expression rather than the substituted limit Limit(log(u)/u, u, oo), so the substitution step is not validly stated and its SymPy check proves nothing.

  • qwen3.6:27b-mlx: uphold — Line 2 is a Python conditional (`... if u == 2*x - 1 else 0`), not a mathematical expression equal to line 1. Its 'proved' status is vacuous, since the conditional evaluates to 0 and so the SymPy check against the neighbouring lines was meaningless. The claim that step 3 violates the single-rule constraint is overstated, but the core objection about step 2 holds.
Every verdict on record (5)
  • qwen3.6:27b-mlx: pass 2026-10-04 — The solution correctly applies substitution, L'Hopital's rule, and limit evaluation. Each step changes only one aspect of the expression and uses valid labels from the fixed vocabulary.
  • gpt-oss:20b: pass 2026-10-04
  • claude-sonnet-5-5: fail (error) 2026-10-04 — The final answer 0 is correct and the L'Hopital chain in lines 3-7 is fine. Line 2 is a malformed conditional expression rather than the substituted limit Limit(log(u)/u, u, oo), so the substitution step is not validly stated and its SymPy check proves nothing.
  • qwen3.6:27b-mlx: fail (error) 2026-10-04 — Step 2 is syntactically invalid and does not represent a valid algebraic substitution step; it introduces a conditional expression rather than transforming the limit expression. Step 3 then arbitrarily discards the conditional structure without justification, violating the single-rule-per-step constraint and logical continuity.
  • gpt-oss:20b: pass 2026-10-04

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-10-04 with SymPy 1.14.0.