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Derivatives and integrals of hyperbolic functions practice problems
Derivatives and antiderivatives of sinh, cosh, tanh and the inverse hyperbolic functions. 60 problems with worked solutions; in 60 of them every
equation is proved by a computer algebra system.
20 worked problems
Try each one before opening the solution. Every line is labeled with what checked it. How we verify
Find \( \displaystyle \int x \cosh{\left(x^{2} \right)} \, dx \). (Omit the constant of integration.)
Use (cosh u)′ = sinh u, (sinh u)′ = cosh u, (tanh u)′ = sech²u, with a substitution for the inside.
Reviewed
\[ \frac{d}{d x} \frac{\sinh{\left(x^{2} \right)}}{2} = x \cosh{\left(x^{2} \right)} \]
Differentiating the answer returns the integrand.✓ Proved
Answer \( \frac{\sinh{\left(x^{2} \right)}}{2} + C \)
✓ Nihil obstat Lines: 1 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt ·
How we verify
Find \( \displaystyle \int - \sinh{\left(4 x - 1 \right)} \, dx \). (Omit the constant of integration.)
Use (cosh u)′ = sinh u, (sinh u)′ = cosh u, (tanh u)′ = sech²u, with a substitution for the inside.
Reviewed
\[ \frac{d}{d x} \left(- \frac{\cosh{\left(4 x - 1 \right)}}{4}\right) = - \sinh{\left(4 x - 1 \right)} \]
Differentiating the answer returns the integrand.✓ Proved
Answer \( - \frac{\cosh{\left(4 x - 1 \right)}}{4} + C \)
✓ Nihil obstat Lines: 1 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt ·
How we verify
Find \( \displaystyle \int \cosh{\left(3 x + 3 \right)} \, dx \). (Omit the constant of integration.)
Use (cosh u)′ = sinh u, (sinh u)′ = cosh u, (tanh u)′ = sech²u, with a substitution for the inside.
Reviewed
\[ \frac{d}{d x} \frac{\sinh{\left(3 x + 3 \right)}}{3} = \cosh{\left(3 x + 3 \right)} \]
Differentiating the answer returns the integrand.✓ Proved
Answer \( \frac{\sinh{\left(3 x + 3 \right)}}{3} + C \)
✓ Nihil obstat Lines: 1 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt ·
How we verify
Answer \( f'(x) = 2 x \cosh{\left(x^{2} \right)} \)
✓ Nihil obstat Lines: 1 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt ·
How we verify
✓ Nihil obstat Lines: 1 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt ·
How we verify
✓ Nihil obstat Lines: 1 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt ·
How we verify
✓ Nihil obstat Lines: 1 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt ·
How we verify
Find \( \displaystyle \int \cosh{\left(2 x - 3 \right)} \, dx \). (Omit the constant of integration.)
Use (cosh u)′ = sinh u, (sinh u)′ = cosh u, (tanh u)′ = sech²u, with a substitution for the inside.
Reviewed
\[ \frac{d}{d x} \frac{\sinh{\left(2 x - 3 \right)}}{2} = \cosh{\left(2 x - 3 \right)} \]
Differentiating the answer returns the integrand.✓ Proved
Answer \( \frac{\sinh{\left(2 x - 3 \right)}}{2} + C \)
✓ Nihil obstat Lines: 1 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt ·
How we verify
✓ Nihil obstat Lines: 1 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt ·
How we verify
✓ Nihil obstat Lines: 1 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt ·
How we verify
Find \( \displaystyle \int - \sinh{\left(4 x + 1 \right)} \, dx \). (Omit the constant of integration.)
Use (cosh u)′ = sinh u, (sinh u)′ = cosh u, (tanh u)′ = sech²u, with a substitution for the inside.
Reviewed
\[ \frac{d}{d x} \left(- \frac{\cosh{\left(4 x + 1 \right)}}{4}\right) = - \sinh{\left(4 x + 1 \right)} \]
Differentiating the answer returns the integrand.✓ Proved
Answer \( - \frac{\cosh{\left(4 x + 1 \right)}}{4} + C \)
✓ Nihil obstat Lines: 1 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt ·
How we verify
Differentiating the answer returns the integrand.✓ Proved
Answer \( \sinh{\left(x + 2 \right)} + C \)
✓ Nihil obstat Lines: 1 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt ·
How we verify
✓ Nihil obstat Lines: 1 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt ·
How we verify
Differentiating the answer returns the integrand.✓ Proved
Answer \( \sinh{\left(x - 2 \right)} + C \)
✓ Nihil obstat Lines: 1 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt ·
How we verify
Find \( \displaystyle \int \sinh{\left(4 x \right)} \, dx \). (Omit the constant of integration.)
Use (cosh u)′ = sinh u, (sinh u)′ = cosh u, (tanh u)′ = sech²u, with a substitution for the inside.
Reviewed
\[ \frac{d}{d x} \frac{\cosh{\left(4 x \right)}}{4} = \sinh{\left(4 x \right)} \]
Differentiating the answer returns the integrand.✓ Proved
Answer \( \frac{\cosh{\left(4 x \right)}}{4} + C \)
✓ Nihil obstat Lines: 1 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt ·
How we verify
Find \( \displaystyle \int \sinh{\left(3 x - 1 \right)} \, dx \). (Omit the constant of integration.)
Use (cosh u)′ = sinh u, (sinh u)′ = cosh u, (tanh u)′ = sech²u, with a substitution for the inside.
Reviewed
\[ \frac{d}{d x} \frac{\cosh{\left(3 x - 1 \right)}}{3} = \sinh{\left(3 x - 1 \right)} \]
Differentiating the answer returns the integrand.✓ Proved
Answer \( \frac{\cosh{\left(3 x - 1 \right)}}{3} + C \)
✓ Nihil obstat Lines: 1 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt ·
How we verify
✓ Nihil obstat Lines: 1 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt ·
How we verify
✓ Nihil obstat Lines: 1 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt ·
How we verify
Find \( \displaystyle \int \sinh{\left(2 x + 1 \right)} \, dx \). (Omit the constant of integration.)
Use (cosh u)′ = sinh u, (sinh u)′ = cosh u, (tanh u)′ = sech²u, with a substitution for the inside.
Reviewed
\[ \frac{d}{d x} \frac{\cosh{\left(2 x + 1 \right)}}{2} = \sinh{\left(2 x + 1 \right)} \]
Differentiating the answer returns the integrand.✓ Proved
Answer \( \frac{\cosh{\left(2 x + 1 \right)}}{2} + C \)
✓ Nihil obstat Lines: 1 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt ·
How we verify
✓ Nihil obstat Lines: 1 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt ·
How we verify
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