Derivatives and integrals of hyperbolic functions
Problem 2.2350 · easy
Differentiate \( \displaystyle f(x) = \tanh{\left(4 x + 2 \right)} \).
- (sinh u)′ = cosh u·u′, (cosh u)′ = sinh u·u′, (tanh u)′ = sech²u·u′, (sinh⁻¹u)′ = u′/√(1 + u²), (tanh⁻¹u)′ = u′/(1 − u²).Reviewed
- \[ \frac{d}{d x} \tanh{\left(4 x + 2 \right)} = \frac{4}{\cosh^{2}{\left(4 x + 2 \right)}} \]Apply the rule (and the chain rule).✓ Proved
Answer \( f'(x) = \frac{4}{\cosh^{2}{\left(4 x + 2 \right)}} \)
✓ Nihil obstat Lines: 1 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | a central difference, with sinh and cosh computed from exponentials by mpmath |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly identifies the derivative rule for tanh and applies the chain rule. The final answer is mathematically equivalent to the standard form 4 sech^2(4x+2) since sech(u) = 1/cosh(u).
Every verdict on record (6)
qwen3.6:27b-mlx: pass 2026-10-18 — The solution correctly identifies the derivative rule for tanh and applies the chain rule. The final answer is mathematically equivalent to the standard form 4 sech^2(4x+2) since sech(u) = 1/cosh(u).gpt-oss:20b: pass 2026-10-18qwen3.6:27b-mlx: pass 2026-10-16 — The solution correctly identifies the derivative rule for tanh and applies the chain rule. The final answer is equivalent to the standard form 4 sech^2(4x+2) since sech(u) = 1/cosh(u).gpt-oss:20b: pass 2026-10-16qwen3.6:27b-mlx: pass 2026-10-15 — The solution correctly identifies the derivative rule for tanh and applies the chain rule. The identity sech^2(u) = 1/cosh^2(u) is correctly used to match the stated answer.gpt-oss:20b: pass 2026-10-15
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/hyperbolic_calculus, checked 2026-10-18 with SymPy 1.14.0.