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Estimating a limit from a table practice problems

Estimate a limit from a table of values on both sides, then confirm it exactly. 60 problems with worked solutions; in 60 of them every equation is proved by a computer algebra system.

11 worked problems

Try each one before opening the solution. Every line is labeled with what checked it. How we verify

Make a table of values of \( \displaystyle f(x) = \frac{x^{2} - x - 2}{x^{2} + 4 x - 12} \) at \( \displaystyle x = 2 \pm 0.1,\ 2 \pm 0.01,\ 2 \pm 0.001,\ 2 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 2} f(x) \).
  1. f(2) itself is undefined (0/0), so the table approaches 2 from both sides.
    Reviewed
  2. The table: f(2 − 0.1) ≈ 3.67088608e-1; f(2 − 0.01) ≈ 3.74217772e-1; f(2 − 0.001) ≈ 3.74921865e-1; f(2 − 0.0001) ≈ 3.74992187e-1; f(2 + 0.0001) ≈ 3.75007812e-1; f(2 + 0.001) ≈ 3.75078115e-1; f(2 + 0.01) ≈ 3.75780275e-1; f(2 + 0.1) ≈ 3.82716049e-1.
    Reviewed
  3. From both sides the values settle toward 0.375000.
    Reviewed
  4. \[ \lim_{x \to 2}\left(\frac{x^{2} - x - 2}{x^{2} + 4 x - 12}\right) = \frac{3}{8} \]
    The exact (two-sided) limit agrees with the table.✓ Proved
Answer \( \lim_{x\to 2} f(x) = \frac{3}{8} \approx 0.375000 \)

✓ Nihil obstat Lines: 1 proved, 3 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Make a table of values of \( \displaystyle f(x) = \frac{\sqrt{x} - 1}{x - 1} \) at \( \displaystyle x = 1 \pm 0.1,\ 1 \pm 0.01,\ 1 \pm 0.001,\ 1 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 1} f(x) \).
  1. f(1) itself is undefined (0/0), so the table approaches 1 from both sides.
    Reviewed
  2. The table: f(1 − 0.1) ≈ 5.13167019e-1; f(1 − 0.01) ≈ 5.01256289e-1; f(1 − 0.001) ≈ 5.00125063e-1; f(1 − 0.0001) ≈ 5.00012501e-1; f(1 + 0.0001) ≈ 4.99987501e-1; f(1 + 0.001) ≈ 4.99875062e-1; f(1 + 0.01) ≈ 4.98756211e-1; f(1 + 0.1) ≈ 4.88088482e-1.
    Reviewed
  3. From both sides the values settle toward 0.500000.
    Reviewed
  4. \[ \lim_{x \to 1}\left(\frac{\sqrt{x} - 1}{x - 1}\right) = \frac{1}{2} \]
    The exact (two-sided) limit agrees with the table.✓ Proved
Answer \( \lim_{x\to 1} f(x) = \frac{1}{2} \approx 0.500000 \)

✓ Nihil obstat Lines: 1 proved, 3 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Make a table of values of \( \displaystyle f(x) = \frac{x^{2} + 5 x + 4}{x^{2} + 8 x + 7} \) at \( \displaystyle x = -1 \pm 0.1,\ -1 \pm 0.01,\ -1 \pm 0.001,\ -1 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to -1} f(x) \).
  1. f(-1) itself is undefined (0/0), so the table approaches -1 from both sides.
    Reviewed
  2. The table: f(-1 − 0.1) ≈ 4.91525424e-1; f(-1 − 0.01) ≈ 4.99165275e-1; f(-1 − 0.001) ≈ 4.99916653e-1; f(-1 − 0.0001) ≈ 4.99991667e-1; f(-1 + 0.0001) ≈ 5.00008333e-1; f(-1 + 0.001) ≈ 5.00083319e-1; f(-1 + 0.01) ≈ 5.00831947e-1; f(-1 + 0.1) ≈ 5.08196721e-1.
    Reviewed
  3. From both sides the values settle toward 0.500000.
    Reviewed
  4. \[ \lim_{x \to -1}\left(\frac{x^{2} + 5 x + 4}{x^{2} + 8 x + 7}\right) = \frac{1}{2} \]
    The exact (two-sided) limit agrees with the table.✓ Proved
Answer \( \lim_{x\to -1} f(x) = \frac{1}{2} \approx 0.500000 \)

✓ Nihil obstat Lines: 1 proved, 3 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Make a table of values of \( \displaystyle f(x) = \frac{x^{2} + x - 6}{x^{2} + 2 x - 8} \) at \( \displaystyle x = 2 \pm 0.1,\ 2 \pm 0.01,\ 2 \pm 0.001,\ 2 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 2} f(x) \).
  1. f(2) itself is undefined (0/0), so the table approaches 2 from both sides.
    Reviewed
  2. The table: f(2 − 0.1) ≈ 8.30508475e-1; f(2 − 0.01) ≈ 8.33055092e-1; f(2 − 0.001) ≈ 8.33305551e-1; f(2 − 0.0001) ≈ 8.33330556e-1; f(2 + 0.0001) ≈ 8.33336111e-1; f(2 + 0.001) ≈ 8.33361106e-1; f(2 + 0.01) ≈ 8.33610649e-1; f(2 + 0.1) ≈ 8.36065574e-1.
    Reviewed
  3. From both sides the values settle toward 0.833333.
    Reviewed
  4. \[ \lim_{x \to 2}\left(\frac{x^{2} + x - 6}{x^{2} + 2 x - 8}\right) = \frac{5}{6} \]
    The exact (two-sided) limit agrees with the table.✓ Proved
Answer \( \lim_{x\to 2} f(x) = \frac{5}{6} \approx 0.833333 \)

✓ Nihil obstat Lines: 1 proved, 3 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Make a table of values of \( \displaystyle f(x) = \frac{x^{2} - 3 x + 2}{x^{2} + 6 x - 7} \) at \( \displaystyle x = 1 \pm 0.1,\ 1 \pm 0.01,\ 1 \pm 0.001,\ 1 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 1} f(x) \).
  1. f(1) itself is undefined (0/0), so the table approaches 1 from both sides.
    Reviewed
  2. The table: f(1 − 0.1) ≈ -1.39240506e-1; f(1 − 0.01) ≈ -1.2640801e-1; f(1 − 0.001) ≈ -1.25140643e-1; f(1 − 0.0001) ≈ -1.25014063e-1; f(1 + 0.0001) ≈ -1.24985938e-1; f(1 + 0.001) ≈ -1.24859393e-1; f(1 + 0.01) ≈ -1.23595506e-1; f(1 + 0.1) ≈ -1.11111111e-1.
    Reviewed
  3. From both sides the values settle toward -0.125000.
    Reviewed
  4. \[ \lim_{x \to 1}\left(\frac{x^{2} - 3 x + 2}{x^{2} + 6 x - 7}\right) = - \frac{1}{8} \]
    The exact (two-sided) limit agrees with the table.✓ Proved
Answer \( \lim_{x\to 1} f(x) = - \frac{1}{8} \approx -0.125000 \)

✓ Nihil obstat Lines: 1 proved, 3 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Make a table of values of \( \displaystyle f(x) = \frac{x^{2} - 2 x - 3}{x^{2} + 4 x + 3} \) at \( \displaystyle x = -1 \pm 0.1,\ -1 \pm 0.01,\ -1 \pm 0.001,\ -1 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to -1} f(x) \).
  1. f(-1) itself is undefined (0/0), so the table approaches -1 from both sides.
    Reviewed
  2. The table: f(-1 − 0.1) ≈ -2.15789474; f(-1 − 0.01) ≈ -2.01507538; f(-1 − 0.001) ≈ -2.00150075; f(-1 − 0.0001) ≈ -2.00015001; f(-1 + 0.0001) ≈ -1.99985001; f(-1 + 0.001) ≈ -1.99850075; f(-1 + 0.01) ≈ -1.98507463; f(-1 + 0.1) ≈ -1.85714286.
    Reviewed
  3. From both sides the values settle toward -2.000000.
    Reviewed
  4. \[ \lim_{x \to -1}\left(\frac{x^{2} - 2 x - 3}{x^{2} + 4 x + 3}\right) = -2 \]
    The exact (two-sided) limit agrees with the table.✓ Proved
Answer \( \lim_{x\to -1} f(x) = -2 \approx -2.000000 \)

✓ Nihil obstat Lines: 1 proved, 3 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Make a table of values of \( \displaystyle f(x) = \frac{x^{2} - 1}{x^{2} + 5 x + 4} \) at \( \displaystyle x = -1 \pm 0.1,\ -1 \pm 0.01,\ -1 \pm 0.001,\ -1 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to -1} f(x) \).
  1. f(-1) itself is undefined (0/0), so the table approaches -1 from both sides.
    Reviewed
  2. The table: f(-1 − 0.1) ≈ -7.24137931e-1; f(-1 − 0.01) ≈ -6.72240803e-1; f(-1 − 0.001) ≈ -6.67222407e-1; f(-1 − 0.0001) ≈ -6.66722224e-1; f(-1 + 0.0001) ≈ -6.66611113e-1; f(-1 + 0.001) ≈ -6.66111296e-1; f(-1 + 0.01) ≈ -6.61129568e-1; f(-1 + 0.1) ≈ -6.12903226e-1.
    Reviewed
  3. From both sides the values settle toward -0.666667.
    Reviewed
  4. \[ \lim_{x \to -1}\left(\frac{x^{2} - 1}{x^{2} + 5 x + 4}\right) = - \frac{2}{3} \]
    The exact (two-sided) limit agrees with the table.✓ Proved
Answer \( \lim_{x\to -1} f(x) = - \frac{2}{3} \approx -0.666667 \)

✓ Nihil obstat Lines: 1 proved, 3 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Make a table of values of \( \displaystyle f(x) = \frac{x^{2} - 9}{x^{2} + 4 x - 21} \) at \( \displaystyle x = 3 \pm 0.1,\ 3 \pm 0.01,\ 3 \pm 0.001,\ 3 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 3} f(x) \).
  1. f(3) itself is undefined (0/0), so the table approaches 3 from both sides.
    Reviewed
  2. The table: f(3 − 0.1) ≈ 5.95959596e-1; f(3 − 0.01) ≈ 5.995996e-1; f(3 − 0.001) ≈ 5.99959996e-1; f(3 − 0.0001) ≈ 5.99996e-1; f(3 + 0.0001) ≈ 6.00004e-1; f(3 + 0.001) ≈ 6.00039996e-1; f(3 + 0.01) ≈ 6.003996e-1; f(3 + 0.1) ≈ 6.03960396e-1.
    Reviewed
  3. From both sides the values settle toward 0.600000.
    Reviewed
  4. \[ \lim_{x \to 3}\left(\frac{x^{2} - 9}{x^{2} + 4 x - 21}\right) = \frac{3}{5} \]
    The exact (two-sided) limit agrees with the table.✓ Proved
Answer \( \lim_{x\to 3} f(x) = \frac{3}{5} \approx 0.600000 \)

✓ Nihil obstat Lines: 1 proved, 3 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Make a table of values of \( \displaystyle f(x) = \frac{x^{2} - 2 x - 3}{x^{2} + 5 x - 24} \) at \( \displaystyle x = 3 \pm 0.1,\ 3 \pm 0.01,\ 3 \pm 0.001,\ 3 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 3} f(x) \).
  1. f(3) itself is undefined (0/0), so the table approaches 3 from both sides.
    Reviewed
  2. The table: f(3 − 0.1) ≈ 3.57798165e-1; f(3 − 0.01) ≈ 3.63057325e-1; f(3 − 0.001) ≈ 3.63578507e-1; f(3 − 0.0001) ≈ 3.63630578e-1; f(3 + 0.0001) ≈ 3.63642149e-1; f(3 + 0.001) ≈ 3.6369421e-1; f(3 + 0.01) ≈ 3.64214351e-1; f(3 + 0.1) ≈ 3.69369369e-1.
    Reviewed
  3. From both sides the values settle toward 0.363636.
    Reviewed
  4. \[ \lim_{x \to 3}\left(\frac{x^{2} - 2 x - 3}{x^{2} + 5 x - 24}\right) = \frac{4}{11} \]
    The exact (two-sided) limit agrees with the table.✓ Proved
Answer \( \lim_{x\to 3} f(x) = \frac{4}{11} \approx 0.363636 \)

✓ Nihil obstat Lines: 1 proved, 3 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Make a table of values of \( \displaystyle f(x) = \frac{x^{2} + 2 x - 3}{x^{2} + 5 x - 6} \) at \( \displaystyle x = 1 \pm 0.1,\ 1 \pm 0.01,\ 1 \pm 0.001,\ 1 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 1} f(x) \).
  1. f(1) itself is undefined (0/0), so the table approaches 1 from both sides.
    Reviewed
  2. The table: f(1 − 0.1) ≈ 5.65217391e-1; f(1 − 0.01) ≈ 5.70815451e-1; f(1 − 0.001) ≈ 5.71367338e-1; f(1 − 0.0001) ≈ 5.71422449e-1; f(1 + 0.0001) ≈ 5.71434694e-1; f(1 + 0.001) ≈ 5.71489787e-1; f(1 + 0.01) ≈ 5.72039943e-1; f(1 + 0.1) ≈ 5.77464789e-1.
    Reviewed
  3. From both sides the values settle toward 0.571429.
    Reviewed
  4. \[ \lim_{x \to 1}\left(\frac{x^{2} + 2 x - 3}{x^{2} + 5 x - 6}\right) = \frac{4}{7} \]
    The exact (two-sided) limit agrees with the table.✓ Proved
Answer \( \lim_{x\to 1} f(x) = \frac{4}{7} \approx 0.571429 \)

✓ Nihil obstat Lines: 1 proved, 3 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Make a table of values of \( \displaystyle f(x) = \frac{x^{2} - x - 2}{x^{2} + 5 x + 4} \) at \( \displaystyle x = -1 \pm 0.1,\ -1 \pm 0.01,\ -1 \pm 0.001,\ -1 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to -1} f(x) \).
  1. f(-1) itself is undefined (0/0), so the table approaches -1 from both sides.
    Reviewed
  2. The table: f(-1 − 0.1) ≈ -1.06896552; f(-1 − 0.01) ≈ -1.00668896; f(-1 − 0.001) ≈ -1.00066689; f(-1 − 0.0001) ≈ -1.00006667; f(-1 + 0.0001) ≈ -9.99933336e-1; f(-1 + 0.001) ≈ -9.99333555e-1; f(-1 + 0.01) ≈ -9.93355482e-1; f(-1 + 0.1) ≈ -9.35483871e-1.
    Reviewed
  3. From both sides the values settle toward -1.000000.
    Reviewed
  4. \[ \lim_{x \to -1}\left(\frac{x^{2} - x - 2}{x^{2} + 5 x + 4}\right) = -1 \]
    The exact (two-sided) limit agrees with the table.✓ Proved
Answer \( \lim_{x\to -1} f(x) = -1 \approx -1.000000 \)

✓ Nihil obstat Lines: 1 proved, 3 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

More estimating a limit from a table practice

Make a table of values of \( \displaystyle f(x) = \frac{e^{5 x} - 1}{x} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.590easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{\sqrt{x} - 3}{x - 9} \) at \( \displaystyle x = 9 \pm 0.1,\ 9 \pm 0.01,\ 9 \pm 0.001,\ 9 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 9} f(x) \).
Problem 1.591easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{x^{2} - x - 6}{x^{2} + 3 x - 18} \) at \( \displaystyle x = 3 \pm 0.1,\ 3 \pm 0.01,\ 3 \pm 0.001,\ 3 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 3} f(x) \).
Problem 1.593easy✓ Nihil obstat
Make a table of values of \( \displaystyle f(x) = \frac{2^{x} - 1}{x} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.594easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{\sin{\left(4 x \right)}}{\sin{\left(x \right)}} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.596easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{x^{2} - 3 x}{x^{2} + 3 x} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.597easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{e^{2 x} - 1}{x} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.598easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{\tan{\left(x \right)}}{x} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.599easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{e^{3 x} - 1}{x} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.600easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{\sin{\left(3 x \right)}}{x} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.601easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{e^{4 x} - 1}{x} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.602easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{\sin{\left(x \right)}}{x} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.603easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{\sin{\left(5 x \right)}}{\sin{\left(x \right)}} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.604easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{1 - \cos{\left(x \right)}}{x^{2}} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.649easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{\sin{\left(2 x \right)}}{x} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.650easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{\sin{\left(2 x \right)}}{\sin{\left(x \right)}} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.651easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{x^{2} - 2 x}{x^{2} + 3 x} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.652easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{x^{2} - 4 x}{x^{2} + 5 x} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.653easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{\sin{\left(3 x \right)}}{\sin{\left(x \right)}} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.654easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = 1 \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.656easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{x^{2} - 2 x}{x^{2} + 2 x} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.658easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{x^{2} - 7 x + 12}{x^{2} + 3 x - 18} \) at \( \displaystyle x = 3 \pm 0.1,\ 3 \pm 0.01,\ 3 \pm 0.001,\ 3 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 3} f(x) \).
Problem 1.659easy✓ Nihil obstat
Make a table of values of \( \displaystyle f(x) = \frac{\sin{\left(5 x \right)}}{x} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.661easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{x^{2} + x}{x^{2} + 4 x} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.662easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{x^{2} - 5 x + 6}{x^{2} + 3 x - 18} \) at \( \displaystyle x = 3 \pm 0.1,\ 3 \pm 0.01,\ 3 \pm 0.001,\ 3 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 3} f(x) \).
Problem 1.663easy✓ Nihil obstat
Make a table of values of \( \displaystyle f(x) = \frac{e^{x} - 1}{x} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.664easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{\tan{\left(2 x \right)}}{x} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.665easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{\sin{\left(4 x \right)}}{x} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.667easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{x^{2} + 3 x}{x^{2} + 4 x} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.668easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{\tan{\left(3 x \right)}}{x} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.670easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{\sqrt{x} - 2}{x - 4} \) at \( \displaystyle x = 4 \pm 0.1,\ 4 \pm 0.01,\ 4 \pm 0.001,\ 4 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 4} f(x) \).
Problem 1.671easy✓ Nihil obstat
Make a table of values of \( \displaystyle f(x) = \frac{\tan{\left(4 x \right)}}{x} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.672easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{x^{2} - 1}{x^{2} + 4 x + 3} \) at \( \displaystyle x = -1 \pm 0.1,\ -1 \pm 0.01,\ -1 \pm 0.001,\ -1 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to -1} f(x) \).
Problem 1.720easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{x^{2} + 3 x + 2}{x^{2} + 4 x + 3} \) at \( \displaystyle x = -1 \pm 0.1,\ -1 \pm 0.01,\ -1 \pm 0.001,\ -1 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to -1} f(x) \).
Problem 1.721easy✓ Nihil obstat
Make a table of values of \( \displaystyle f(x) = \frac{x^{2} + 3 x}{x^{2} + 2 x} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.722easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{x^{2} + x}{x^{2} + 5 x} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.724easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{x^{2} - 5 x + 6}{x^{2} + 4 x - 12} \) at \( \displaystyle x = 2 \pm 0.1,\ 2 \pm 0.01,\ 2 \pm 0.001,\ 2 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 2} f(x) \).
Problem 1.726easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{\tan{\left(5 x \right)}}{x} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.728easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{x^{2} - 3 x - 4}{x^{2} + 5 x + 4} \) at \( \displaystyle x = -1 \pm 0.1,\ -1 \pm 0.01,\ -1 \pm 0.001,\ -1 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to -1} f(x) \).
Problem 1.729easy✓ Nihil obstat
Make a table of values of \( \displaystyle f(x) = \frac{x^{2} + 5 x + 4}{x^{2} + 6 x + 5} \) at \( \displaystyle x = -1 \pm 0.1,\ -1 \pm 0.01,\ -1 \pm 0.001,\ -1 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to -1} f(x) \).
Problem 1.785easy✓ Nihil obstat
Make a table of values of \( \displaystyle f(x) = \frac{x^{2} + x - 12}{x^{2} + 4 x - 21} \) at \( \displaystyle x = 3 \pm 0.1,\ 3 \pm 0.01,\ 3 \pm 0.001,\ 3 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 3} f(x) \).
Problem 1.786easy✓ Nihil obstat
Make a table of values of \( \displaystyle f(x) = \frac{x^{2} + 4 x}{x^{2} + 5 x} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.787easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{x^{2} + x - 2}{x^{2} + 3 x - 4} \) at \( \displaystyle x = 1 \pm 0.1,\ 1 \pm 0.01,\ 1 \pm 0.001,\ 1 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 1} f(x) \).
Problem 1.788easy✓ Nihil obstat
Make a table of values of \( \displaystyle f(x) = \frac{x^{2} - 2 x - 3}{x^{2} + 2 x - 15} \) at \( \displaystyle x = 3 \pm 0.1,\ 3 \pm 0.01,\ 3 \pm 0.001,\ 3 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 3} f(x) \).
Problem 1.789easy✓ Nihil obstat
Make a table of values of \( \displaystyle f(x) = \frac{x^{2} - 2 x}{x^{2} + 6 x} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.790easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{x^{2} - 4 x + 3}{x^{2} + 3 x - 4} \) at \( \displaystyle x = 1 \pm 0.1,\ 1 \pm 0.01,\ 1 \pm 0.001,\ 1 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 1} f(x) \).
Problem 1.791easy✓ Nihil obstat
Make a table of values of \( \displaystyle f(x) = \frac{x^{2} + 4 x}{x^{2} + 3 x} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.792easy✓ Every equation proved
Make a table of values of \( \displaystyle f(x) = \frac{x^{2} - 4 x + 3}{x^{2} + 4 x - 5} \) at \( \displaystyle x = 1 \pm 0.1,\ 1 \pm 0.01,\ 1 \pm 0.001,\ 1 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 1} f(x) \).
Problem 1.793easy✓ Nihil obstat
Make a table of values of \( \displaystyle f(x) = \frac{x^{2} - 4 x}{x^{2} + 4 x} \) at \( \displaystyle x = 0 \pm 0.1,\ 0 \pm 0.01,\ 0 \pm 0.001,\ 0 \pm 0.0001 \) and use it to estimate \( \displaystyle \lim_{x \to 0} f(x) \).
Problem 1.794easy✓ Every equation proved