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Riemann sums for double integrals

Problem 11.522 · medium

Estimate \( \displaystyle \iint_R 3 x - y^{2} + 5 \, dA \) over \( \displaystyle R = [0, 2] \times [0, 1] \) with a Riemann sum, \( \displaystyle m = 4 \) subintervals in \( \displaystyle x \) and \( \displaystyle n = 2 \) in \( \displaystyle y \), sampling at the lower left corners.

\[ 1 \cdot \frac{1}{2} \cdot 2 \cdot \frac{1}{4} = \frac{1}{4} \]
ΔA = Δx Δy.✓ Proved
The sample points: (0, 0), (0, 1/2), (1/2, 0), (1/2, 1/2), (1, 0), (1, 1/2), (3/2, 0), (3/2, 1/2).
Reviewed
\[ 1 \cdot \frac{1}{2} \cdot 1 \cdot \frac{1}{2} \left(\frac{19}{4} + 5 + \frac{25}{4} + \frac{13}{2} + \frac{31}{4} + 8 + \frac{37}{4} + \frac{19}{2}\right) = \frac{57}{4} \]
ΔA times the sum of f at the sample points.✓ Proved
\[ \int\limits_{0}^{1}\int\limits_{0}^{2} \left(3 x - y^{2} + 5\right)\, dx\, dy = \frac{46}{3} \]
For comparison, the exact value is 46/3.✓ Proved

Answer \( \frac{57}{4} \)

✓ Nihil obstat Lines: 3 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify

The full receipt

Line	Status	Checked by	Detail
1	✓ Proved	sympy 1.14.0	simplify(lhs - rhs) reduced to 0
2	Reviewed	reviewers: gpt-oss:20b, qwen3.6:27b-mlx	a sentence; read, not computed
3	✓ Proved	sympy 1.14.0	simplify(lhs - rhs) reduced to 0
4	✓ Proved	sympy 1.14.0	simplify(lhs - rhs) reduced to 0
answer, a second way	✓ Checked independently	sympy 1.14.0 + mpmath 1.3.0	the sum recomputed in exact fractions

Reviewers

gpt-oss:20b: pass
qwen3.6:27b-mlx: pass — The solution correctly identifies the grid dimensions, sample points, and area element. The arithmetic for the Riemann sum is correct, and the comparison with the exact integral is accurate.

Every verdict on record (6)

qwen3.6:27b-mlx: pass 2026-10-19 — The solution correctly identifies the grid dimensions, sample points, and area element. The arithmetic for the Riemann sum is correct, and the comparison with the exact integral is accurate.
gpt-oss:20b: pass 2026-10-19
qwen3.6:27b-mlx: pass 2026-10-17 — The solution correctly identifies the grid dimensions, sample points, and function evaluations. The arithmetic is correct, and the setup matches the problem statement.
gpt-oss:20b: pass 2026-10-17
qwen3.6:27b-mlx: pass 2026-10-17 — The solution correctly identifies the grid dimensions, sample points, and function evaluations for the specified Riemann sum. The arithmetic is correct, and the comparison with the exact integral is accurate.
gpt-oss:20b: pass 2026-10-17

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/double_riemann, checked 2026-10-19 with SymPy 1.14.0.