Riemann sums for double integrals
Problem 11.523 · medium
Estimate \( \displaystyle \iint_R 3 x - y^{2} + 5 \, dA \) over \( \displaystyle R = [0, 4] \times [0, 2] \) with a Riemann sum, \( \displaystyle m = 2 \) subintervals in \( \displaystyle x \) and \( \displaystyle n = 2 \) in \( \displaystyle y \), sampling at the midpoint points.
- \[ 2 \cdot \frac{1}{2} \cdot 4 \cdot \frac{1}{2} = 2 \]ΔA = Δx Δy.✓ Proved
- The sample points: (1, 1/2), (1, 3/2), (3, 1/2), (3, 3/2).Reviewed
- \[ 2 \cdot 1 \left(\frac{23}{4} + \frac{31}{4} + \frac{47}{4} + \frac{55}{4}\right) = 78 \]ΔA times the sum of f at the sample points.✓ Proved
- \[ \int\limits_{0}^{2}\int\limits_{0}^{4} \left(3 x - y^{2} + 5\right)\, dx\, dy = \frac{232}{3} \]For comparison, the exact value is 232/3.✓ Proved
Answer \( 78 \)
✓ Nihil obstat ✓ Checked by a person Lines: 3 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 2 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | the sum recomputed in exact fractions |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly identifies the subrectangle area, the midpoint sample points, and the function evaluations. The final sum is calculated correctly.
Every verdict on record (6)
qwen3.6:27b-mlx: pass 2026-10-19 — The solution correctly identifies the subrectangle area, the midpoint sample points, and the function evaluations. The final sum is calculated correctly.gpt-oss:20b: pass 2026-10-19qwen3.6:27b-mlx: pass 2026-10-17 — The solution correctly identifies the subrectangle area, the midpoint sample points, and the function evaluations. The final calculation is correct.gpt-oss:20b: pass 2026-10-17qwen3.6:27b-mlx: pass 2026-10-17 — The solution correctly identifies the subrectangle area, the midpoint sample points, and the function evaluations. The final summation is correct.gpt-oss:20b: pass 2026-10-17
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/double_riemann, checked 2026-10-19 with SymPy 1.14.0.