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Riemann sums for double integrals

Problem 11.521 · medium

Estimate \( \displaystyle \iint_R x^{2} + y \, dA \) over \( \displaystyle R = [0, 4] \times [0, 2] \) with a Riemann sum, \( \displaystyle m = 2 \) subintervals in \( \displaystyle x \) and \( \displaystyle n = 2 \) in \( \displaystyle y \), sampling at the midpoint points.

\[ 2 \cdot \frac{1}{2} \cdot 4 \cdot \frac{1}{2} = 2 \]
ΔA = Δx Δy.✓ Proved
The sample points: (1, 1/2), (1, 3/2), (3, 1/2), (3, 3/2).
Reviewed
\[ 2 \cdot 1 \left(\frac{3}{2} + \frac{5}{2} + \frac{19}{2} + \frac{21}{2}\right) = 48 \]
ΔA times the sum of f at the sample points.✓ Proved
\[ \int\limits_{0}^{2}\int\limits_{0}^{4} \left(x^{2} + y\right)\, dx\, dy = \frac{152}{3} \]
For comparison, the exact value is 152/3.✓ Proved

Answer \( 48 \)

✓ Nihil obstat Lines: 3 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify

The full receipt

Line	Status	Checked by	Detail
1	✓ Proved	sympy 1.14.0	simplify(lhs - rhs) reduced to 0
2	Reviewed	reviewers: gpt-oss:20b, qwen3.6:27b-mlx	a sentence; read, not computed
3	✓ Proved	sympy 1.14.0	simplify(lhs - rhs) reduced to 0
4	✓ Proved	sympy 1.14.0	simplify(lhs - rhs) reduced to 0
answer, a second way	✓ Checked independently	sympy 1.14.0 + mpmath 1.3.0	the sum recomputed in exact fractions

Reviewers

gpt-oss:20b: pass
qwen3.6:27b-mlx: pass — The solution correctly identifies the subregion areas, midpoints, and function evaluations. The final Riemann sum calculation is correct.

Every verdict on record (6)

qwen3.6:27b-mlx: pass 2026-10-19 — The solution correctly identifies the subregion areas, midpoints, and function evaluations. The final Riemann sum calculation is correct.
gpt-oss:20b: pass 2026-10-19
qwen3.6:27b-mlx: pass 2026-10-17 — The solution correctly identifies the subrectangle area, the midpoint sample points, and computes the Riemann sum accurately. The comparison with the exact integral is correct and serves as a valid sanity check.
gpt-oss:20b: pass 2026-10-17
qwen3.6:27b-mlx: pass 2026-10-17 — The solution correctly identifies the subrectangle area, the midpoint sample points, and the function evaluations. The final calculation is correct.
gpt-oss:20b: pass 2026-10-17

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/double_riemann, checked 2026-10-19 with SymPy 1.14.0.