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Arc length in polar coordinates practice problems

Arc length of a polar curve, L = ∫ √(r² + (dr/dθ)²) dθ. 28 problems with worked solutions; in 28 of them every equation is proved by a computer algebra system.

9 worked problems

Try each one before opening the solution. Every line is labeled with what checked it. How we verify

Find the length of the polar curve \( \displaystyle r = 5 \cos{\left(\theta \right)} + 5 \) for \( \displaystyle 0 \le \theta \le \pi \).
  1. L = ∫ √(r² + (dr/dθ)²) dθ.
    Reviewed
  2. \[ \left(5 \cos{\left(\theta \right)} + 5\right)^{2} + \left(\frac{d}{d \theta} \left(5 \cos{\left(\theta \right)} + 5\right)\right)^{2} = 50 \cos{\left(\theta \right)} + 50 \]
    r² + (dr/dθ)², simplified.✓ Proved
  3. \[ 100 \cos^{2}{\left(\frac{\theta}{2} \right)} = 50 \cos{\left(\theta \right)} + 50 \]
    Its square root is 2a cos(θ/2) on [0, π] (half-angle identity).✓ Proved
  4. \[ \int\limits_{0}^{\pi} 10 \cos{\left(\frac{\theta}{2} \right)}\, d\theta = 20 \]
    Integrate.✓ Proved
Answer \( 20 \)

✓ Nihil obstat Lines: 3 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Find the length of the polar curve \( \displaystyle r = \theta^{2} \) for \( \displaystyle 0 \le \theta \le \sqrt{5} \).
  1. L = ∫ √(r² + (dr/dθ)²) dθ.
    Reviewed
  2. \[ \theta^{4} + \left(\frac{d}{d \theta} \theta^{2}\right)^{2} = \theta^{2} \left(\theta^{2} + 4\right) \]
    r² + (dr/dθ)², simplified.✓ Proved
  3. \[ \int\limits_{0}^{\sqrt{5}} \sqrt{\theta^{2} + 4} \left|{\theta}\right|\, d\theta = \frac{19}{3} \]
    Integrate.✓ Proved
Answer \( \frac{19}{3} \)

✓ Nihil obstat Lines: 2 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Find the length of the polar curve \( \displaystyle r = e^{\theta} \) for \( \displaystyle 0 \le \theta \le 1 \).
  1. L = ∫ √(r² + (dr/dθ)²) dθ.
    Reviewed
  2. \[ e^{2 \theta} + \left(\frac{d}{d \theta} e^{\theta}\right)^{2} = 2 e^{2 \theta} \]
    r² + (dr/dθ)², simplified.✓ Proved
  3. \[ \int\limits_{0}^{1} \sqrt{2} e^{\theta}\, d\theta = \sqrt{2} \left(-1 + e\right) \]
    Integrate.✓ Proved
Answer \( \sqrt{2} \left(-1 + e\right) \)

✓ Nihil obstat Lines: 2 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Find the length of the polar curve \( \displaystyle r = 3 \) for \( \displaystyle 0 \le \theta \le \frac{\pi}{2} \).
  1. L = ∫ √(r² + (dr/dθ)²) dθ.
    Reviewed
  2. \[ \left(\frac{d}{d \theta} 3\right)^{2} + 9 = 9 \]
    r² + (dr/dθ)², simplified.✓ Proved
  3. \[ \int\limits_{0}^{\frac{\pi}{2}} 3\, d\theta = \frac{3 \pi}{2} \]
    Integrate.✓ Proved
Answer \( \frac{3 \pi}{2} \)

✓ Nihil obstat Lines: 2 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Find the length of the polar curve \( \displaystyle r = 5 \sin{\left(\theta \right)} \) for \( \displaystyle 0 \le \theta \le \pi \).
  1. L = ∫ √(r² + (dr/dθ)²) dθ.
    Reviewed
  2. \[ 25 \sin^{2}{\left(\theta \right)} + \left(\frac{d}{d \theta} 5 \sin{\left(\theta \right)}\right)^{2} = 25 \]
    r² + (dr/dθ)², simplified.✓ Proved
  3. \[ \int\limits_{0}^{\pi} 5\, d\theta = 5 \pi \]
    Integrate.✓ Proved
Answer \( 5 \pi \)

✓ Nihil obstat Lines: 2 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Find the length of the polar curve \( \displaystyle r = \sin{\left(\theta \right)} \) for \( \displaystyle 0 \le \theta \le \pi \).
  1. L = ∫ √(r² + (dr/dθ)²) dθ.
    Reviewed
  2. \[ \sin^{2}{\left(\theta \right)} + \left(\frac{d}{d \theta} \sin{\left(\theta \right)}\right)^{2} = 1 \]
    r² + (dr/dθ)², simplified.✓ Proved
  3. \[ \int\limits_{0}^{\pi} 1\, d\theta = \pi \]
    Integrate.✓ Proved
Answer \( \pi \)

✓ Nihil obstat Lines: 2 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Find the length of the polar curve \( \displaystyle r = \theta^{2} \) for \( \displaystyle 0 \le \theta \le 2 \).
  1. L = ∫ √(r² + (dr/dθ)²) dθ.
    Reviewed
  2. \[ \theta^{4} + \left(\frac{d}{d \theta} \theta^{2}\right)^{2} = \theta^{2} \left(\theta^{2} + 4\right) \]
    r² + (dr/dθ)², simplified.✓ Proved
  3. \[ \int\limits_{0}^{2} \sqrt{\theta^{2} + 4} \left|{\theta}\right|\, d\theta = - \frac{8}{3} + \frac{16 \sqrt{2}}{3} \]
    Integrate.✓ Proved
Answer \( - \frac{8}{3} + \frac{16 \sqrt{2}}{3} \)

✓ Nihil obstat Lines: 2 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Find the length of the polar curve \( \displaystyle r = \cos{\left(\theta \right)} \) for \( \displaystyle 0 \le \theta \le \frac{\pi}{2} \).
  1. L = ∫ √(r² + (dr/dθ)²) dθ.
    Reviewed
  2. \[ \cos^{2}{\left(\theta \right)} + \left(\frac{d}{d \theta} \cos{\left(\theta \right)}\right)^{2} = 1 \]
    r² + (dr/dθ)², simplified.✓ Proved
  3. \[ \int\limits_{0}^{\frac{\pi}{2}} 1\, d\theta = \frac{\pi}{2} \]
    Integrate.✓ Proved
Answer \( \frac{\pi}{2} \)

✓ Nihil obstat Lines: 2 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

Find the length of the polar curve \( \displaystyle r = 2 \cos{\left(\theta \right)} \) for \( \displaystyle 0 \le \theta \le \frac{\pi}{2} \).
  1. L = ∫ √(r² + (dr/dθ)²) dθ.
    Reviewed
  2. \[ 4 \cos^{2}{\left(\theta \right)} + \left(\frac{d}{d \theta} 2 \cos{\left(\theta \right)}\right)^{2} = 4 \]
    r² + (dr/dθ)², simplified.✓ Proved
  3. \[ \int\limits_{0}^{\frac{\pi}{2}} 2\, d\theta = \pi \]
    Integrate.✓ Proved
Answer \( \pi \)

✓ Nihil obstat Lines: 2 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt · How we verify

More arc length in polar coordinates practice

Find the length of the polar curve \( \displaystyle r = 6 \cos{\left(\theta \right)} + 6 \) for \( \displaystyle 0 \le \theta \le \pi \).
Problem 8.281medium✓ Nihil obstat
Find the length of the polar curve \( \displaystyle r = 1 \) for \( \displaystyle 0 \le \theta \le \frac{\pi}{2} \).
Problem 8.286medium✓ Nihil obstat
Find the length of the polar curve \( \displaystyle r = 2 \cos{\left(\theta \right)} + 2 \) for \( \displaystyle 0 \le \theta \le \pi \).
Problem 8.287medium✓ Nihil obstat
Find the length of the polar curve \( \displaystyle r = 4 \cos{\left(\theta \right)} + 4 \) for \( \displaystyle 0 \le \theta \le \pi \).
Problem 8.289medium✓ Nihil obstat
Find the length of the polar curve \( \displaystyle r = 2 \sin{\left(\theta \right)} \) for \( \displaystyle 0 \le \theta \le \pi \).
Problem 8.290medium✓ Nihil obstat
Find the length of the polar curve \( \displaystyle r = 6 \sin{\left(\theta \right)} \) for \( \displaystyle 0 \le \theta \le \pi \).
Problem 8.291medium✓ Nihil obstat
Find the length of the polar curve \( \displaystyle r = 5 \) for \( \displaystyle 0 \le \theta \le \frac{\pi}{2} \).
Problem 8.293medium✓ Nihil obstat
Find the length of the polar curve \( \displaystyle r = 3 \cos{\left(\theta \right)} + 3 \) for \( \displaystyle 0 \le \theta \le \pi \).
Problem 8.294medium✓ Nihil obstat
Find the length of the polar curve \( \displaystyle r = \theta^{2} \) for \( \displaystyle 0 \le \theta \le 1 \).
Problem 8.404medium✓ Every equation proved
Find the length of the polar curve \( \displaystyle r = 4 \sin{\left(\theta \right)} \) for \( \displaystyle 0 \le \theta \le \pi \).
Problem 8.405medium✓ Nihil obstat
Find the length of the polar curve \( \displaystyle r = 6 \) for \( \displaystyle 0 \le \theta \le \frac{\pi}{2} \).
Problem 8.407medium✓ Nihil obstat
Find the length of the polar curve \( \displaystyle r = 3 \sin{\left(\theta \right)} \) for \( \displaystyle 0 \le \theta \le \pi \).
Problem 8.408medium✓ Nihil obstat
Find the length of the polar curve \( \displaystyle r = 2 \) for \( \displaystyle 0 \le \theta \le \frac{\pi}{2} \).
Problem 8.410medium✓ Nihil obstat
Find the length of the polar curve \( \displaystyle r = 3 \cos{\left(\theta \right)} \) for \( \displaystyle 0 \le \theta \le \frac{\pi}{2} \).
Problem 8.411medium✓ Nihil obstat
Find the length of the polar curve \( \displaystyle r = 6 \cos{\left(\theta \right)} \) for \( \displaystyle 0 \le \theta \le \frac{\pi}{2} \).
Problem 8.412medium✓ Nihil obstat
Find the length of the polar curve \( \displaystyle r = 4 \) for \( \displaystyle 0 \le \theta \le \frac{\pi}{2} \).
Problem 8.413medium✓ Nihil obstat
Find the length of the polar curve \( \displaystyle r = \cos{\left(\theta \right)} + 1 \) for \( \displaystyle 0 \le \theta \le \pi \).
Problem 8.414medium✓ Every equation proved
Find the length of the polar curve \( \displaystyle r = 5 \cos{\left(\theta \right)} \) for \( \displaystyle 0 \le \theta \le \frac{\pi}{2} \).
Problem 8.415medium✓ Nihil obstat
Find the length of the polar curve \( \displaystyle r = 4 \cos{\left(\theta \right)} \) for \( \displaystyle 0 \le \theta \le \frac{\pi}{2} \).
Problem 8.416medium✓ Nihil obstat