∫Calc Practice

Arc length in polar coordinates

Problem 8.284 · medium

Find the length of the polar curve \( \displaystyle r = 3 \) for \( \displaystyle 0 \le \theta \le \frac{\pi}{2} \).
  1. L = ∫ √(r² + (dr/dθ)²) dθ.
    Reviewed
  2. \[ \left(\frac{d}{d \theta} 3\right)^{2} + 9 = 9 \]
    r² + (dr/dθ)², simplified.✓ Proved
  3. \[ \int\limits_{0}^{\frac{\pi}{2}} 3\, d\theta = \frac{3 \pi}{2} \]
    Integrate.✓ Proved
Answer \( \frac{3 \pi}{2} \)

✓ Nihil obstat Lines: 2 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify

The full receipt
LineStatusChecked byDetail
1Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0a 20,000-segment polyline along the curve

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly applies the arc length formula for polar coordinates. Since r is constant, dr/dθ is 0, simplifying the integrand to r, which yields the correct arc length of a quarter circle.
Every verdict on record (6)
  • qwen3.6:27b-mlx: pass 2026-10-17 — The solution correctly applies the arc length formula for polar coordinates. Since r is constant, dr/dθ is 0, simplifying the integrand to r, which yields the correct arc length of a quarter circle.
  • gpt-oss:20b: pass 2026-10-17
  • qwen3.6:27b-mlx: pass 2026-10-15 — The solution correctly applies the arc length formula for polar curves. Since r is constant, dr/dθ is 0, simplifying the integrand to r, and the integration over [0, π/2] yields the correct arc length of a quarter circle.
  • gpt-oss:20b: pass 2026-10-15
  • qwen3.6:27b-mlx: pass 2026-10-14 — The solution correctly applies the arc length formula for polar curves, computes the derivative and integrand accurately, and evaluates the definite integral correctly.
  • gpt-oss:20b: pass 2026-10-14

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/polar_arc_length, checked 2026-10-17 with SymPy 1.14.0.