Equations of spheres
Problem 9.919 · easy
Find the equation of the sphere with center \( \displaystyle (4, 2, 0) \) and radius \( \displaystyle 1 \), in standard form.
- A sphere is every point at distance r from the center: (x − h)² + (y − k)² + (z − l)² = r².Reviewed
- \[ \left. z^{2} + \left(x - 4\right)^{2} + \left(y - 2\right)^{2} \right|_{\substack{ x=5\\ y=2\\ z=0 }} = 1 \]A point at distance r along the x-direction is on it.✓ Proved
Answer \( z^{2} + \left(x - 4\right)^{2} + \left(y - 2\right)^{2} = 1 \)
Lines: 1 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | points at the claimed radius from the claimed center satisfy the equation |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly identifies the standard equation of a sphere and substitutes the given center and radius. The verification step confirms a point on the sphere satisfies the equation.
Every verdict on record (6)
qwen3.6:27b-mlx: pass 2026-11-08 — The solution correctly identifies the standard equation of a sphere and substitutes the given center and radius. The verification step confirms a point on the sphere satisfies the equation.gpt-oss:20b: pass 2026-11-08qwen3.6:27b-mlx: pass 2026-11-07 — The solution correctly identifies the standard equation of a sphere and verifies it with a valid point on the sphere. The logic is sound and the final answer matches the problem statement.gpt-oss:20b: pass 2026-11-07qwen3.6:27b-mlx: pass 2026-11-07 — The solution correctly identifies the standard equation of a sphere and substitutes the given center and radius. The unchecked equation line serves as a valid consistency check for a point on the sphere.gpt-oss:20b: fail (error) 2026-11-07 — The solution never writes the sphere’s equation; it merely attempts a substitution without showing the result, and the justification that (5,2,0) lies on the sphere is missing.
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/sphere_equation, checked 2026-11-08 with SymPy 1.14.0.