∫Calc Practice

Equations of spheres

Problem 9.918 · easy

Find the center and radius of the sphere \( \displaystyle x^{2} + 6 x + y^{2} + z^{2} + 6 z + 9 = 0 \).
  1. Complete the square in x, y and z.
    Reviewed
  2. \[ x^{2} + 6 x + y^{2} + z^{2} + 6 z + 9 = y^{2} + \left(x + 3\right)^{2} + \left(z + 3\right)^{2} - 9 \]
    So (x − -3)² + (y − 0)² + (z − -3)² = 9.✓ Proved
Answer \( \text{center } (-3, 0, -3),\ \text{radius } 3 \)

✓ Nihil obstat Lines: 1 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify

The full receipt
LineStatusChecked byDetail
1Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0points at the claimed radius from the claimed center satisfy the equation

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly completes the square to identify the center and radius. The algebraic manipulation is valid and the final result matches the stated answer.
Every verdict on record (6)
  • qwen3.6:27b-mlx: pass 2026-11-08 — The solution correctly completes the square to identify the center and radius. The algebraic manipulation is valid and the final result matches the stated answer.
  • gpt-oss:20b: pass 2026-11-08
  • qwen3.6:27b-mlx: pass 2026-11-07 — The solution correctly completes the square to identify the center and radius. The algebraic manipulation is valid, and the final result matches the stated answer.
  • gpt-oss:20b: pass 2026-11-07
  • qwen3.6:27b-mlx: pass 2026-11-07 — The solution correctly completes the square to identify the center and radius. The algebraic manipulation is sound and the final result matches the stated answer.
  • gpt-oss:20b: pass 2026-11-07

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/sphere_equation, checked 2026-11-08 with SymPy 1.14.0.