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Cross product

Problem 9.103 · medium

Find \( \displaystyle \mathbf{u} \times \mathbf{v} \) for \( \displaystyle \mathbf{u} = \langle -3, 3, -2 \rangle,\ \mathbf{v} = \langle 0, 3, 0 \rangle \), and the area of the parallelogram they span.
  1. Expand the determinant with rows i j k, u, v.
    Reviewed
  2. \[ \left[\begin{matrix}6\\0\\-9\end{matrix}\right] \]
    The components.✓ Proved
  3. \[ 3 \sqrt{13} \]
    Area = |u × v|.✓ Proved
Answer \( \mathbf{u}\times\mathbf{v} = \langle 6, 0, -9 \rangle,\quad \text{area} = 3 \sqrt{13} \)

✓ Nihil obstat Lines: 2 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0Lagrange's identity √(|u|²|v|² − (u·v)²) gives the same area

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly computes the cross product and its magnitude. The steps are logically sound and the final answer matches the stated result.
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-09-26 — The solution correctly computes the cross product and its magnitude. The steps are logically sound and the final answer matches the stated result.
  • gpt-oss:20b: pass 2026-09-26
  • qwen3.6:27b-mlx: pass 2026-09-26 — The solution correctly computes the cross product and its magnitude. The algebraic steps are verified, and the final answer matches the stated result.
  • gpt-oss:20b: pass 2026-09-26

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/cross_product_area, checked 2026-09-26 with SymPy 1.14.0.