∫Calc Practice

Converting between polar and rectangular coordinates

Problem 8.175 · easy

Write the polar equation \( \displaystyle r = 6 \) in rectangular form.
  1. Use x = r cos θ, y = r sin θ, r² = x² + y²; square both sides: r² = x² + y².
  2. \[ r^{2} \sin^{2}{\left(\theta \right)} + r^{2} \cos^{2}{\left(\theta \right)} - 36 \]
    Substituting back gives an equation equivalent to the polar one.✓ Proved
Answer \( x^{2} + y^{2} = 36 \)

Lines: 1 proved, 1 not checked. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.

The full receipt
LineStatusChecked byDetail
1Not checked—a sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0points on the polar curve at four angles satisfy the rectangular equation

Reviewers

  • gpt-oss:20b: fail (misleading) — The solution never derives the rectangular equation x²+y²=36; it merely restates the identity r²=x²+y² without concluding the required form.
  • qwen3.6:27b-mlx: pass — The solution correctly identifies the relationship r^2 = x^2 + y^2 and substitutes r=6 to derive x^2 + y^2 = 36. The algebraic verification in step 2 is valid, though verbose.
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-10-08 — The solution correctly identifies the relationship r^2 = x^2 + y^2 and substitutes r=6 to derive x^2 + y^2 = 36. The algebraic verification in step 2 is valid, though verbose.
  • gpt-oss:20b: fail (misleading) 2026-10-08 — The solution never derives the rectangular equation x²+y²=36; it merely restates the identity r²=x²+y² without concluding the required form.
  • gpt-oss:20b: fail (error) 2026-10-08 — The solution never substitutes r=6 into the identity r²=x²+y² to obtain x²+y²=36, and the final equation shown is just a tautological rewrite, not the required rectangular form.
  • qwen3.6:27b-mlx: fail (error) 2026-10-08 — The solution fails to substitute r = 6 into the identity r^2 = x^2 + y^2 to obtain x^2 + y^2 = 36. Instead, it presents a tautology involving theta, which does not constitute a rectangular equation.

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/polar_conversion, checked 2026-10-08 with SymPy 1.14.0.