∫Calc Practice

Converting between polar and rectangular coordinates

Problem 8.174 · easy

Convert the rectangular point \( \displaystyle \left(\frac{3 \sqrt{3}}{2}, - \frac{3}{2}\right) \) to polar coordinates with \( \displaystyle r > 0 \) and \( \displaystyle 0 \le \theta < 2\pi \).
  1. \[ 3 \]
    r = √(x² + y²).✓ Proved
  2. The point is in quadrant 4; θ = 11*pi/6.
    Reviewed
  3. \[ \left[\begin{matrix}\frac{3 \sqrt{3}}{2}\\- \frac{3}{2}\end{matrix}\right] \]
    Converting back gives the point.✓ Proved
Answer \( \left(3, \frac{11 \pi}{6}\right) \)

✓ Nihil obstat Lines: 2 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0r and θ from hypot and atan2

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly identifies the quadrant and the corresponding angle within the specified range [0, 2pi). The algebraic steps are verified.
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-10-08 — The solution correctly identifies the quadrant and the corresponding angle within the specified range [0, 2pi). The algebraic steps are verified.
  • gpt-oss:20b: pass 2026-10-08
  • gpt-oss:20b: pass 2026-10-08
  • qwen3.6:27b-mlx: pass 2026-10-08 — The solution correctly identifies the quadrant and calculates the reference angle to determine theta. The final coordinates satisfy the constraints r > 0 and 0 <= theta < 2pi.

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/polar_conversion, checked 2026-10-08 with SymPy 1.14.0.