Radius of convergence
Problem 7.60 · easy
Find the radius of convergence of \( \displaystyle \sum_{n=1}^{\infty} \frac{\left(x + 3\right)^{n}}{n!} \).
- Use the ratio test on the absolute values of the terms.
- \[ \lim_{n \to \infty}\left(\frac{\left(x + 3\right)^{- n} \left(x + 3\right)^{n + 1} n!}{\left(x + 3\right) \left(n + 1\right)!}\right) = 0 \]|a_(n+1)/a_n| → 0·|x − -3|.✓ Proved
- The series converges when 0|x − -3| < 1, which is every x: R = ∞.
Answer \( R = \infty \)
Lines: 1 proved, 2 not checked. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Not checked | — | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 3 | Not checked | — | a sentence; read, not computed |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | terms evaluated just inside and just outside the radius shrink and grow |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: fail (style) — [domain objection, downgraded to style] The limit of the ratio of absolute terms is 0, which is strictly less than 1 for all x. The solution incorrectly states the convergence condition as '0|x+3| < 1', implying a restriction on x, whereas the ratio test guarantees convergence for all x when the limit is 0.
Every verdict on record (6)
qwen3.6:27b-mlx: fail (style) 2026-09-28 — [domain objection, downgraded to style] The limit of the ratio of absolute terms is 0, which is strictly less than 1 for all x. The solution incorrectly states the convergence condition as '0|x+3| < 1', implying a restriction on x, whereas the ratio test guarantees convergence for all x when the limit is 0.gpt-oss:20b: pass 2026-09-28qwen3.6:27b-mlx: fail (error) 2026-09-27 — The limit of the ratio is 0, so the condition for convergence is 0 < 1, which is always true. The solution incorrectly states the condition as '0|x - -3| < 1', implying the limit depends on x, which is false for this series.gpt-oss:20b: pass 2026-09-27qwen3.6:27b-mlx: fail (error) 2026-09-26 — The solution incorrectly applies the Ratio Test condition. The limit of the ratio is 0, which is less than 1 for all x, implying convergence everywhere. However, the text claims convergence requires '0 < 1', which is a nonsensical condition and misstates the theorem (convergence requires L < 1, not 0 < 1).gpt-oss:20b: pass 2026-09-26
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/radius_of_convergence, checked 2026-09-28 with SymPy 1.14.0.