∫Calc Practice

Radius of convergence

Problem 7.60 · easy

Find the radius of convergence of \( \displaystyle \sum_{n=1}^{\infty} \frac{\left(x + 3\right)^{n}}{n!} \).
  1. Use the ratio test on the absolute values of the terms.
  2. \[ \lim_{n \to \infty}\left(\frac{\left(x + 3\right)^{- n} \left(x + 3\right)^{n + 1} n!}{\left(x + 3\right) \left(n + 1\right)!}\right) = 0 \]
    |a_(n+1)/a_n| → 0·|x − -3|.✓ Proved
  3. The series converges when 0|x − -3| < 1, which is every x: R = ∞.
Answer \( R = \infty \)

Lines: 1 proved, 2 not checked. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify

The full receipt
LineStatusChecked byDetail
1Not checked—a sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3Not checked—a sentence; read, not computed
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0terms evaluated just inside and just outside the radius shrink and grow

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: fail (style) — [domain objection, downgraded to style] The limit of the ratio of absolute terms is 0, which is strictly less than 1 for all x. The solution incorrectly states the convergence condition as '0|x+3| < 1', implying a restriction on x, whereas the ratio test guarantees convergence for all x when the limit is 0.
Every verdict on record (6)
  • qwen3.6:27b-mlx: fail (style) 2026-09-28 — [domain objection, downgraded to style] The limit of the ratio of absolute terms is 0, which is strictly less than 1 for all x. The solution incorrectly states the convergence condition as '0|x+3| < 1', implying a restriction on x, whereas the ratio test guarantees convergence for all x when the limit is 0.
  • gpt-oss:20b: pass 2026-09-28
  • qwen3.6:27b-mlx: fail (error) 2026-09-27 — The limit of the ratio is 0, so the condition for convergence is 0 < 1, which is always true. The solution incorrectly states the condition as '0|x - -3| < 1', implying the limit depends on x, which is false for this series.
  • gpt-oss:20b: pass 2026-09-27
  • qwen3.6:27b-mlx: fail (error) 2026-09-26 — The solution incorrectly applies the Ratio Test condition. The limit of the ratio is 0, which is less than 1 for all x, implying convergence everywhere. However, the text claims convergence requires '0 < 1', which is a nonsensical condition and misstates the theorem (convergence requires L < 1, not 0 < 1).
  • gpt-oss:20b: pass 2026-09-26

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/radius_of_convergence, checked 2026-09-28 with SymPy 1.14.0.