Radius of convergence
Problem 7.55 · easy
Find the radius of convergence of \( \displaystyle \sum_{n=1}^{\infty} \frac{\left(x - 2\right)^{n}}{n^{2}} \).
- Use the ratio test on the absolute values of the terms.Reviewed
- \[ \lim_{n \to \infty}\left(\frac{n^{2} \left(x - 2\right)^{- n} \left(x - 2\right)^{n + 1}}{\left(n + 1\right)^{2} \left(x - 2\right)}\right) = 1 \]|a_(n+1)/a_n| → 1·|x − 2|.✓ Proved
- The series converges when 1|x − 2| < 1, that is |x − 2| < 1.Reviewed
Answer \( R = 1 \)
✓ Nihil obstat Lines: 1 proved, 2 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 3 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | terms evaluated just inside and just outside the radius shrink and grow |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly applies the ratio test to determine the radius of convergence. The limit calculation is correct, and the resulting inequality correctly identifies the radius as 1.
Every verdict on record (6)
qwen3.6:27b-mlx: pass 2026-09-28 — The solution correctly applies the ratio test to determine the radius of convergence. The limit calculation is correct, and the resulting inequality correctly identifies the radius as 1.gpt-oss:20b: pass 2026-09-28qwen3.6:27b-mlx: pass 2026-09-27 — The solution correctly applies the Ratio Test to determine the radius of convergence. The limit calculation is correct, and the resulting inequality |x - 2| < 1 correctly identifies the radius as 1.gpt-oss:20b: pass 2026-09-27qwen3.6:27b-mlx: pass 2026-09-26 — The solution correctly applies the Ratio Test to determine the radius of convergence. The algebraic simplification and the resulting inequality |x - 2| < 1 are correct, leading to the correct radius R = 1.gpt-oss:20b: pass 2026-09-26
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/radius_of_convergence, checked 2026-09-28 with SymPy 1.14.0.