Second-order initial and boundary value problems
Problem 6.477 · medium
Solve \( \displaystyle - 4 y + 3 y' + y'' = 0 \) with \( \displaystyle y(0) = 4,\ y'(0) = 4 \).
- \[ m^{2} + 3 m - 4 = \left(m - 1\right) \left(m + 4\right) \]The characteristic equation has distinct real roots -4 and 1.✓ Proved
- So y = C₁exp(-4*x) + C₂exp(x); the two conditions fix C₁ and C₂.
- \[ - 16 e^{x} + 3 \frac{d}{d x} 4 e^{x} + \frac{d^{2}}{d x^{2}} 4 e^{x} = 0 \]It satisfies the equation ...✓ Proved
- \[ \left. 4 e^{x} \right|_{\substack{ x=0 }} = 4 \]... y(0) = 4 ...✓ Proved
- \[ \left. \frac{d}{d x} 4 e^{x} \right|_{\substack{ x=0 }} = 4 \]y′(0) = 4.✓ Proved
Answer \( y = 4 e^{x} \)
Lines: 4 proved, 1 not checked. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 2 | Not checked | — | a sentence; read, not computed |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 5 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | finite differences of the answer satisfy the equation, and the conditions hold in floating point |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: fail (error) — The solution fails to determine the constants C₁ and C₂ from the initial conditions. It merely verifies that the specific function y = 4e^x satisfies the conditions, but does not show that this is the unique solution derived from the general form y = C₁e^{-4x} + C₂e^x. A student might incorrectly conclude that one can simply guess a solution and verify it, rather than solving the system of linear equations for the constants.
Every verdict on record (6)
qwen3.6:27b-mlx: fail (error) 2026-10-17 — The solution fails to determine the constants C₁ and C₂ from the initial conditions. It merely verifies that the specific function y = 4e^x satisfies the conditions, but does not show that this is the unique solution derived from the general form y = C₁e^{-4x} + C₂e^x. A student might incorrectly conclude that one can simply guess a solution and verify it, rather than solving the system of linear equations for the constants.gpt-oss:20b: pass 2026-10-17qwen3.6:27b-mlx: fail (error) 2026-10-15 — The solution fails to determine the constants C₁ and C₂ from the initial conditions. It merely verifies that the final answer satisfies the conditions, ignoring the general solution structure derived in step 2. Specifically, it skips the system of equations C₁ + C₂ = 4 and -4C₁ + C₂ = 4, which yields C₁ = 0 and C₂ = 4. While the final answer is correct, the logical gap implies the student did not actually solve for the constants.gpt-oss:20b: fail (error) 2026-10-15 — The solution skips the crucial step of determining the constants C₁ and C₂ from the initial conditions. It merely states that the conditions fix them but never actually solves for C₁=0 and C₂=4, and then proceeds to test only the particular function y=4e^x without showing that it is the unique solution that satisfies both the differential equation and the given initial values.qwen3.6:27b-mlx: fail (error) 2026-10-14 — The solution fails to determine the constants C₁ and C₂ from the initial conditions. It merely verifies that the specific function y = 4e^x is a solution, but does not show that it is the unique solution satisfying the given initial conditions (specifically, it skips the step showing C₁ must be 0).gpt-oss:20b: pass 2026-10-14
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/second_order_ivp_bvp, checked 2026-10-17 with SymPy 1.14.0.