∫Calc Practice

Integrals giving inverse trig functions

Problem 4.505 · medium

Evaluate \( \displaystyle \int \frac{4}{x^{2} + 2 x + 26}\, dx \).
  1. \[ x^{2} + 2 x + 26 = \left(x + 1\right)^{2} + 25 \]
    Complete the square.✓ Proved
  2. With u = x + 1 and a = 5, this is c·∫ du/(u² + a²)
  3. \[ \frac{d}{d x} \frac{4 \operatorname{atan}{\left(\frac{x}{5} + \frac{1}{5} \right)}}{5} = \frac{4}{x^{2} + 2 x + 26} \]
    An antiderivative is 4*atan(x/5 + 1/5)/5; differentiate to confirm.✓ Proved
Answer \( \frac{4 \operatorname{atan}{\left(\frac{x}{5} + \frac{1}{5} \right)}}{5} + C \)

Lines: 2 proved, 1 not checked. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2Not checked—a sentence; read, not computed
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0difference quotient of the answer at x = -4.0

Reviewers

  • gpt-oss:20b: fail (misleading) — The sentence claims the integral becomes "c·∫ du/(u² + a²)" but never defines the constant c (it should be 4). This omission misleads a student about the correct scaling factor in the antiderivative.
  • qwen3.6:27b-mlx: pass — The solution correctly completes the square, identifies the standard arctangent integral form, and verifies the result by differentiation.
Every verdict on record (4)
  • gpt-oss:20b: fail (misleading) 2026-10-06 — The sentence claims the integral becomes "c·∫ du/(u² + a²)" but never defines the constant c (it should be 4). This omission misleads a student about the correct scaling factor in the antiderivative.
  • qwen3.6:27b-mlx: pass 2026-10-06 — The solution correctly completes the square, identifies the standard arctangent integral form, and verifies the result by differentiation.
  • gpt-oss:20b: fail (misleading) 2026-10-06 — The sentence claims the integral becomes "c·∫ du/(u² + a²)" but does not specify that c=4, nor does it show the factor 4 in front of the integral. This omission could mislead a student into thinking the constant factor is irrelevant.
  • qwen3.6:27b-mlx: fail (misleading) 2026-10-06 — The solution omits the constant factor 4 in the transition from the original integral to the standard form, stating 'this is c·∫ du/(u² + a²)' without specifying c=4. This skips the crucial step of factoring out the numerator, which could lead a student to incorrectly apply the formula ∫ du/(u² + a²) directly to the original expression.

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/inverse_trig_integral, checked 2026-10-06 with SymPy 1.14.0.