∫Calc Practice

Accumulation functions

Problem 4.1136 · easy

Use the Fundamental Theorem of Calculus to write \( \displaystyle F(x) = \displaystyle \int_{0}^{x} t - 4 \, dt \) as a function of \( \displaystyle x \).
  1. \[ \frac{d}{d t} \left(\frac{t^{2}}{2} - 4 t\right) = t - 4 \]
    An antiderivative of the integrand is t**2/2 - 4*t.✓ Proved
  2. \[ - \left. \frac{t^{2}}{2} - 4 t \right|_{\substack{ t=0 }} + \left. \frac{t^{2}}{2} - 4 t \right|_{\substack{ t=x }} = \frac{x \left(x - 8\right)}{2} \]
    F(x) = G(x) − G(a).✓ Proved
  3. \[ \frac{d}{d x} \frac{x \left(x - 8\right)}{2} = x - 4 \]
    F′(x) = f(x), as FTC Part 1 says.✓ Proved
  4. \[ \left. \frac{x \left(x - 8\right)}{2} \right|_{\substack{ x=0 }} = 0 \]
    And F(0) = 0.✓ Proved
Answer \( F(x) = \frac{x \left(x - 8\right)}{2} \)

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0numerical quadrature from a to three values of x

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly applies the Fundamental Theorem of Calculus to evaluate the definite integral and verifies the result. The steps are logically sound and algebraically correct.
Every verdict on record (6)
  • qwen3.6:27b-mlx: pass 2026-10-18 — The solution correctly applies the Fundamental Theorem of Calculus to evaluate the definite integral and verifies the result. The steps are logically sound and algebraically correct.
  • gpt-oss:20b: pass 2026-10-18
  • qwen3.6:27b-mlx: pass 2026-10-15 — The solution correctly applies the Fundamental Theorem of Calculus to evaluate the definite integral and verifies the result. The steps are logically sound and algebraically correct.
  • gpt-oss:20b: pass 2026-10-15
  • qwen3.6:27b-mlx: pass 2026-10-14 — The solution correctly applies the Fundamental Theorem of Calculus to evaluate the definite integral and verify the result. The algebraic steps are correct and the logic is sound.
  • gpt-oss:20b: pass 2026-10-14

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/ftc_accumulation, checked 2026-10-18 with SymPy 1.14.0.