Accumulation functions
Problem 4.1135 · easy
Use the Fundamental Theorem of Calculus to write \( \displaystyle F(x) = \displaystyle \int_{2}^{x} t + 4 \, dt \) as a function of \( \displaystyle x \).
- \[ \frac{d}{d t} \left(\frac{t^{2}}{2} + 4 t\right) = t + 4 \]An antiderivative of the integrand is t**2/2 + 4*t.✓ Proved
- \[ - \left. \frac{t^{2}}{2} + 4 t \right|_{\substack{ t=2 }} + \left. \frac{t^{2}}{2} + 4 t \right|_{\substack{ t=x }} = \frac{x^{2}}{2} + 4 x - 10 \]F(x) = G(x) − G(a).✓ Proved
- \[ \frac{d}{d x} \left(\frac{x^{2}}{2} + 4 x - 10\right) = x + 4 \]F′(x) = f(x), as FTC Part 1 says.✓ Proved
- \[ \left. \frac{x^{2}}{2} + 4 x - 10 \right|_{\substack{ x=2 }} = 0 \]And F(2) = 0.✓ Proved
Answer \( F(x) = \frac{x^{2}}{2} + 4 x - 10 \)
✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | numerical quadrature from a to three values of x |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly applies the Fundamental Theorem of Calculus to evaluate the definite integral and verifies the result using differentiation and the initial condition.
Every verdict on record (6)
qwen3.6:27b-mlx: pass 2026-10-18 — The solution correctly applies the Fundamental Theorem of Calculus to evaluate the definite integral and verifies the result using differentiation and the initial condition.gpt-oss:20b: pass 2026-10-18qwen3.6:27b-mlx: pass 2026-10-15 — The solution correctly applies the Fundamental Theorem of Calculus to evaluate the definite integral and verifies the result using differentiation and boundary conditions.gpt-oss:20b: pass 2026-10-15qwen3.6:27b-mlx: pass 2026-10-14 — The solution correctly applies the Fundamental Theorem of Calculus to evaluate the definite integral and verifies the result using FTC Part 1 and the initial condition.gpt-oss:20b: pass 2026-10-14
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/ftc_accumulation, checked 2026-10-18 with SymPy 1.14.0.