∫Calc Practice

Sums with sigma notation

Problem 4.1033 · easy

Evaluate \( \displaystyle \sum_{i=1}^{10} \left(3 i^{2} - 3 i + 5\right) \) using summation formulas.
  1. Split the sum and use Σᵢ₌₁ᴺ 1 = N, Σ i = N(N + 1)/2, Σ i² = N(N + 1)(2N + 1)/6, Σ i³ = [N(N + 1)/2]².
    Reviewed
  2. \[ \left(-3\right) 10 \cdot 11 \cdot 1 \cdot \frac{1}{2} + 5 \cdot 10 + 3 \cdot 10 \cdot 11 \cdot 21 \cdot 1 \cdot \frac{1}{6} = 1040 \]
    From i = 1 to 10.✓ Proved
  3. \[ \sum_{i=1}^{10} \left(3 i^{2} - 3 i + 5\right) = 1040 \]
    The sum, evaluated directly, agrees.✓ Proved
Answer \( 1040 \)

✓ Nihil obstat Lines: 2 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify

The full receipt
LineStatusChecked byDetail
1Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0the terms added one by one in Python integers

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly identifies the necessary summation formulas and applies them to the specific terms of the polynomial. The intermediate calculation and final verification are correct.
Every verdict on record (6)
  • qwen3.6:27b-mlx: pass 2026-10-17 — The solution correctly identifies the necessary summation formulas and applies them to the specific terms of the polynomial. The intermediate calculation and final verification are correct.
  • gpt-oss:20b: pass 2026-10-17
  • qwen3.6:27b-mlx: pass 2026-10-14 — The solution correctly identifies the necessary summation formulas and applies them to the specific bounds. The algebraic verification confirms the result.
  • gpt-oss:20b: pass 2026-10-14
  • qwen3.6:27b-mlx: pass 2026-10-14 — The solution correctly identifies the necessary summation formulas and applies them to the specific terms of the polynomial. The arithmetic in the unchecked equations is correct, and the final result matches the direct evaluation.
  • gpt-oss:20b: pass 2026-10-14

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/summation_formulas, checked 2026-10-17 with SymPy 1.14.0.