Derivative of \( \displaystyle \sqrt{5} \sqrt{x} e^{5 x} \)
Problem 2.577 · hard
Differentiate \( \displaystyle f(x) = \sqrt{5} \sqrt{x} e^{5 x} \).
- \[ \frac{d}{d x} \sqrt{5} \sqrt{x} e^{5 x} \]derivativeStart with the derivative of the function.✓ Proved
- \[ = \sqrt{5} \frac{d}{d x} \sqrt{x} e^{5 x} \]constant-multiplePull out the constant factor.✓ Proved
- \[ = \sqrt{5} \left(\sqrt{x} \frac{d}{d x} e^{5 x} + e^{5 x} \frac{d}{d x} \sqrt{x}\right) \]productApply the product rule.✓ Proved
- \[ = \sqrt{5} \left(\sqrt{x} \frac{d}{d x} e^{5 x} + e^{5 x} \frac{d}{d x} x^{0.5}\right) \]rewriteRewrite sqrt(x) as x**0.5.✓ Proved
- \[ = \sqrt{5} \left(\frac{0.5 e^{5 x}}{x^{0.5}} + \sqrt{x} \frac{d}{d x} e^{5 x}\right) \]derivativeDifferentiate x**0.5.✓ Proved
- \[ = \sqrt{5} \left(\frac{0.5 e^{5 x}}{x^{0.5}} + 5 \sqrt{x} e^{5 x}\right) \]derivativeDifferentiate exp(5*x) using the chain rule.✓ Proved
- \[ = \sqrt{5} \left(\frac{0.5}{x^{0.5}} + 5 \sqrt{x}\right) e^{5 x} \]algebraFactor out exp(5*x).✓ Proved
- \[ = \sqrt{5} \left(5 \sqrt{x} + \frac{1}{2 \sqrt{x}}\right) e^{5 x} \]algebraRewrite 0.5*x**(-0.5) as 1/(2*sqrt(x)).✓ Proved
- \[ = \frac{\sqrt{5} \left(10 x + 1\right) e^{5 x}}{2 \sqrt{x}} \]simplifyCombine the terms into a single fraction.✓ Proved
Answer \( \frac{\sqrt{5} \left(10 x + 1\right) e^{5 x}}{2 \sqrt{x}} \)
Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | line 1 is the problem as stated |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 |
| 5 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x = 0 |
| 6 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x = 0 |
| 7 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x = 0 |
| 8 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x = 0 |
| 9 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x = 0 |
| answer | ✓ Proved | sympy 1.14.0 | final line against the stated answer: simplify(a - b) reduced to 0 undefined where x = 0 |
| answer, a second way | ✓ Proved | sympy 1.14.0 | SymPy differentiated f directly and got the stated answer |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass
Every verdict on record (4)
qwen3.6:27b-mlx: pass 2026-09-21gpt-oss:20b: pass 2026-09-21qwen3.6:27b-mlx: fail (misleading) 2026-09-21 — Step 6 is labeled 'derivative' but applies the chain rule to differentiate exp(5*x); the label should be 'chain'. Additionally, the note explicitly mentions the chain rule while the label does not, creating a contradiction that would confuse a student about which label corresponds to which operation.gpt-oss:20b: pass 2026-09-21
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
gemma4:26b, checked 2026-09-26 with SymPy 1.14.0.