Derivative of \( \displaystyle \frac{e^{3 x + 1}}{3 x + 2} \)
Problem 2.515 · hard
Differentiate \( \displaystyle f(x) = \frac{e^{3 x + 1}}{3 x + 2} \).
- \[ \frac{d}{d x} \frac{e^{3 x + 1}}{3 x + 2} \]derivative rewriteStart with the derivative of the function. Rewrite the quotient as a product using a negative exponent.✓ Proved
- \[ = e^{3 x + 1} \frac{d}{d x} \frac{1}{3 x + 2} + \frac{\frac{d}{d x} e^{3 x + 1}}{3 x + 2} \]productApply the product rule.✓ Proved
- \[ = e^{3 x + 1} \frac{d}{d x} \frac{1}{3 x + 2} + \frac{3 e^{3 x + 1}}{3 x + 2} \]chainDifferentiate the first part using the chain rule.✓ Proved
- \[ = \frac{3 e^{3 x + 1}}{3 x + 2} - \frac{e^{3 x + 1} \frac{d}{d x} \left(3 x + 2\right)}{\left(3 x + 2\right)^{2}} \]chainDifferentiate the second part using the chain rule.✓ Proved
- \[ = \frac{3 e^{3 x + 1}}{3 x + 2} - \frac{3 e^{3 x + 1}}{\left(3 x + 2\right)^{2}} \]derivative algebra algebraEvaluate the derivative of the inner function. Simplify the expression. Rewrite with positive exponents.✓ Proved
- \[ = \frac{3 \left(3 x + 2\right) e^{3 x + 1} - 3 e^{3 x + 1}}{\left(3 x + 2\right)^{2}} \]algebraFind a common denominator.✓ Proved
- \[ = \frac{3 \left(3 x + 1\right) e^{3 x + 1}}{\left(3 x + 2\right)^{2}} \]algebra simplifyFactor out the common term 3 * exp(3*x + 1). Simplify the expression inside the parentheses.✓ Proved
Answer \( \frac{\left(9 x + 3\right) e^{3 x + 1}}{9 x^{2} + 12 x + 4} \)
✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | line 1 is the problem as stated |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where 3*x + 2 = 0 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where 3*x + 2 = 0 |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where 3*x + 2 = 0 |
| 5 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where 3*x + 2 = 0 |
| 6 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where 3*x + 2 = 0 |
| 7 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where 3*x + 2 = 0 |
| 8 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where 3*x + 2 = 0 |
| 9 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where 3*x + 2 = 0 |
| 10 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where 3*x + 2 = 0 |
| 11 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where 3*x + 2 = 0 |
| answer | ✓ Proved | sympy 1.14.0 | final line against the stated answer: simplify(a - b) reduced to 0 undefined where 9*x**2 + 12*x + 4 = 0 |
| answer, a second way | ✓ Proved | sympy 1.14.0 | SymPy differentiated f directly and got the stated answer |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass
Every verdict on record (6)
qwen3.6:27b-mlx: pass 2026-09-21gpt-oss:20b: pass 2026-09-21qwen3.6:27b-mlx: pass 2026-09-20 — The solution correctly applies the product rule, chain rule, and algebraic simplifications. Each step changes only one aspect of the expression, and the labels accurately reflect the operations performed.gpt-oss:20b: pass 2026-09-20qwen3.6:27b-mlx: pass 2026-09-20 — The solution correctly applies the product rule and chain rule in separate steps. The algebraic simplification and labeling are consistent with the provided vocabulary.gpt-oss:20b: pass 2026-09-20
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
gemma4:26b, checked 2026-09-26 with SymPy 1.14.0.