Derivative of \( \displaystyle \sqrt{x} e^{x} \)
Problem 2.463 · hard
Differentiate \( \displaystyle f(x) = \sqrt{x} e^{x} \).
- \[ \frac{d}{d x} \sqrt{x} e^{x} \]rewrite rewrite algebraStart with the derivative of the function. Rewrite the square root as a power. Rewrite the power using the exponential and logarithm. Combine the exponents using properties of exponents.✓ Proved
- \[ = \sqrt{x} e^{x} \frac{d}{d x} \left(x + \frac{\ln{\left(x \right)}}{2}\right) \]chainApply the chain rule for the exponential function.✓ Proved
- \[ = \sqrt{x} e^{x} \frac{d}{d x} x + \sqrt{x} e^{x} \frac{d}{d x} \frac{\ln{\left(x \right)}}{2} \]sumApply the sum rule to the exponent.✓ Proved
- \[ = \sqrt{x} e^{x} + \frac{e^{x}}{2 \sqrt{x}} \]derivativeDifferentiate the individual terms in the sum.✓ Proved
- \[ = \sqrt{x} \left(1 + \frac{1}{2 x}\right) e^{x} \]algebra algebraFactor out the common exponential term. Substitute back the original form of the exponential term.✓ Proved
- \[ = \left(\sqrt{x} + \frac{1}{2 \sqrt{x}}\right) e^{x} \]simplifySimplify the expression into a final form.✓ Proved
Answer \( \frac{\left(x + \frac{1}{2}\right) e^{x}}{\sqrt{x}} \)
✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | line 1 is the problem as stated |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 |
| 5 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 6 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 7 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where x = 0 |
| 8 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x = 0 |
| 9 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x = 0 |
| 10 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x = 0 |
| answer | ✓ Proved | sympy 1.14.0 | final line against the stated answer: simplify(a - b) reduced to 0 undefined where x = 0 |
| answer, a second way | ✓ Proved | sympy 1.14.0 | SymPy differentiated f directly and got the stated answer |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly applies the chain rule to the exponential form and handles the differentiation of the logarithmic term. Each step changes only one aspect of the expression and uses valid labels from the fixed vocabulary.
Every verdict on record (6)
qwen3.6:27b-mlx: pass 2026-09-21 — The solution correctly applies the chain rule to the exponential form and handles the differentiation of the logarithmic term. Each step changes only one aspect of the expression and uses valid labels from the fixed vocabulary.gpt-oss:20b: pass 2026-09-21qwen3.6:27b-mlx: pass 2026-09-20gpt-oss:20b: pass 2026-09-20qwen3.6:27b-mlx: pass 2026-09-20 — The solution correctly applies the chain rule and sum rule to the rewritten exponential form. Each step isolates a single transformation, and the labels accurately reflect the operations performed.gpt-oss:20b: pass 2026-09-20
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
gemma4:26b, checked 2026-09-26 with SymPy 1.14.0.