∫Calc Practice

Derivative of \( \displaystyle 3 x \ln{\left(x - 1 \right)} - 3 x - 3 \ln{\left(x - 1 \right)} \)

Problem 2.407 · hard Beautiful

Differentiate \( \displaystyle f(x) = 3 x \ln{\left(x - 1 \right)} - 3 x - 3 \ln{\left(x - 1 \right)} \).
  1. \[ \frac{d}{d x} \left(3 x \ln{\left(x - 1 \right)} - 3 x - 3 \ln{\left(x - 1 \right)}\right) \]
    Start with the derivative of the function.✓ Proved
  2. \[ = - \frac{d}{d x} 3 x + \frac{d}{d x} 3 x \ln{\left(x - 1 \right)} - \frac{d}{d x} 3 \ln{\left(x - 1 \right)} \]
    sumApply the sum rule to differentiate each term separately.✓ Proved
  3. \[ = \frac{d}{d x} 3 x \ln{\left(x - 1 \right)} - \frac{d}{d x} 3 \ln{\left(x - 1 \right)} - 3 \]
    constantThe derivative of 3*x is 3.✓ Proved
  4. \[ = \frac{d}{d x} 3 x \ln{\left(x - 1 \right)} - 3 \frac{d}{d x} \ln{\left(x - 1 \right)} - 3 \]
    constant-multipleFactor out the constant 3 from the third term.✓ Proved
  5. \[ = \frac{d}{d x} 3 x \ln{\left(x - 1 \right)} - 3 - \frac{3}{x - 1} \]
    logarithmicDifferentiate the natural logarithm term.✓ Proved
  6. \[ = 3 \frac{d}{d x} x \ln{\left(x - 1 \right)} - 3 - \frac{3}{x - 1} \]
    constant-multipleFactor out the constant 3 from the first term.✓ Proved
  7. \[ = 3 x \frac{d}{d x} \ln{\left(x - 1 \right)} + 3 \ln{\left(x - 1 \right)} \frac{d}{d x} x - 3 - \frac{3}{x - 1} \]
    productApply the product rule to the first term.✓ Proved
  8. \[ = \frac{3 x}{x - 1} + 3 \ln{\left(x - 1 \right)} - 3 - \frac{3}{x - 1} \]
    derivative algebra algebraDifferentiate x and log(x - 1) inside the product rule. Distribute the 3. Group the terms with the same denominator.✓ Proved
  9. \[ = 3 \ln{\left(x - 1 \right)} - 3 + \frac{3 x - 3}{x - 1} \]
    algebra algebraCombine the fractions. Factor the numerator of the fraction.✓ Proved
  10. \[ = 3 \ln{\left(x - 1 \right)} \]
    simplify simplifySimplify the fraction (x-1)/(x-1) to 1. Combine the constant terms.✓ Proved
Answer \( 3 \log{\left(x - 1 \right)} \)

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where x - 1 = 0
6✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where x - 1 = 0
7✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where x - 1 = 0
8✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where x - 1 = 0
9✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where x - 1 = 0
10✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where x - 1 = 0
11✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where x - 1 = 0
12✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where x - 1 = 0
13✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where x - 1 = 0
14✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
log is undefined for non-positive arguments
answer, a second way✓ Provedsympy 1.14.0SymPy differentiated f directly and got the stated answer

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly applies differentiation rules and algebraic simplifications in a step-by-step manner. Each step changes only one aspect of the expression and uses valid labels from the provided vocabulary.
Every verdict on record (6)
  • qwen3.6:27b-mlx: pass 2026-09-21 — The solution correctly applies differentiation rules and algebraic simplifications in a step-by-step manner. Each step changes only one aspect of the expression and uses valid labels from the provided vocabulary.
  • gpt-oss:20b: pass 2026-09-21
  • qwen3.6:27b-mlx: pass 2026-09-20 — The solution correctly applies differentiation rules and algebraic simplifications. Each step isolates a single operation, and the labels accurately reflect the rules applied.
  • gpt-oss:20b: pass 2026-09-20
  • qwen3.6:27b-mlx: pass 2026-09-20 — The solution correctly applies differentiation rules and algebraic simplifications. Each step changes only one aspect of the expression, and the labels accurately reflect the operations performed.
  • gpt-oss:20b: pass 2026-09-20

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-09-26 with SymPy 1.14.0.