∫Calc Practice

Derivative of \( \displaystyle e^{3 x - 3} \)

Problem 2.382 · easy Video

Differentiate \( \displaystyle f(x) = e^{3 x - 3} \).
  1. \[ \frac{d}{d x} e^{3 x - 3} \]
    Start with the derivative of the function.✓ Proved
  2. \[ = e^{3 x - 3} \frac{d}{d x} \left(3 x - 3\right) \]
    chainApply the chain rule.✓ Proved
  3. \[ = - e^{3 x - 3} \frac{d}{d x} 3 + e^{3 x - 3} \frac{d}{d x} 3 x \]
    sumDifferentiate the terms inside the parenthesis.✓ Proved
  4. \[ = 3 e^{3 x - 3} \]
    derivative simplifyDifferentiate the linear and constant terms. Simplify the expression.✓ Proved
Answer \( 3 e^{3 x - 3} \)
Top: the graph of f = e^(3x - 3). A tangent line slides along it, and its slope is plotted below as it goes, tracing f' = 3e^(3x - 3).

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
answer, a second way✓ Provedsympy 1.14.0SymPy differentiated f directly and got the stated answer

Reviewers

  • gpt-oss:20b: fail (style) — Step 3 applies two rules at once (splitting the inner derivative and distributing the exponential factor) and incorrectly labels the operation as "sum".
  • qwen3.6:27b-mlx: pass — The solution correctly applies the chain rule, linearity of the derivative, and basic differentiation rules in separate steps. The labels are appropriate for the operations performed.

Senior review claude-sonnet-5-5, 2026-10-08: pass — Every line is SymPy-verified and the rule labels are legitimate. The chain rule gives exp(3x-3)*3, and the constant term's derivative is 0, so the answer 3*exp(3*x-3) is correct.

  • gpt-oss:20b: dismiss — Step 3 applies the sum rule to the inner derivative, and distributing the exponential factor across the resulting terms is part of that same change, so 'sum' is a legitimate label and only one thing changes.
Every verdict on record (7)
  • claude-sonnet-5-5: pass 2026-10-08 — Every line is SymPy-verified and the rule labels are legitimate. The chain rule gives exp(3x-3)*3, and the constant term's derivative is 0, so the answer 3*exp(3*x-3) is correct.
  • qwen3.6:27b-mlx: pass 2026-09-21 — The solution correctly applies the chain rule, linearity of the derivative, and basic differentiation rules in separate steps. The labels are appropriate for the operations performed.
  • gpt-oss:20b: fail (style) 2026-09-21 — Step 3 applies two rules at once (splitting the inner derivative and distributing the exponential factor) and incorrectly labels the operation as "sum".
  • qwen3.6:27b-mlx: pass 2026-09-20
  • gpt-oss:20b: pass 2026-09-20
  • qwen3.6:27b-mlx: fail (error) 2026-09-20 — Step 3 is mathematically incorrect because it distributes the outer exponential term into the derivative of the sum, effectively applying the product rule to a constant multiplier which is not present in the previous step. The chain rule result in Step 2 is a single product term, so the derivative of the inner function should be computed as a whole, not split by distributing the outer factor.
  • gpt-oss:20b: fail (error) 2026-09-20 — Step 3 applies two rules at once: it distributes the factor exp(3*x‑3) over the sum 3*x‑3, which is an algebraic distributive step, and then uses the sum rule for derivatives. Each step must change only one thing, so this step is invalid.

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-09-26 with SymPy 1.14.0.