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Derivative of \( \displaystyle \frac{5 x^{2}}{4} - \frac{x}{2} + \left(- \frac{5 x^{2}}{2} + x - \frac{1}{10}\right) \ln{\left(5 x - 1 \right)} \)

Problem 2.2422 · hard Video

Differentiate \( \displaystyle f(x) = \frac{5 x^{2}}{4} - \frac{x}{2} + \left(- \frac{5 x^{2}}{2} + x - \frac{1}{10}\right) \ln{\left(5 x - 1 \right)} \).
  1. \[ \frac{d}{d x} \left(\frac{5 x^{2}}{4} - \frac{x}{2} + \left(- \frac{5 x^{2}}{2} + x - \frac{1}{10}\right) \ln{\left(5 x - 1 \right)}\right) \]
    derivativeStart with the derivative of the function.✓ Proved
  2. \[ = - \frac{d}{d x} \frac{x}{2} + \frac{d}{d x} \frac{5 x^{2}}{4} + \frac{d}{d x} \left(- \frac{5 x^{2}}{2} + x - \frac{1}{10}\right) \ln{\left(5 x - 1 \right)} \]
    sumApply the sum rule.✓ Proved
  3. \[ = \left(- \frac{5 x^{2}}{2} + x - \frac{1}{10}\right) \frac{d}{d x} \ln{\left(5 x - 1 \right)} + \ln{\left(5 x - 1 \right)} \frac{d}{d x} \left(- \frac{5 x^{2}}{2} + x - \frac{1}{10}\right) - \frac{d}{d x} \frac{x}{2} + \frac{d}{d x} \frac{5 x^{2}}{4} \]
    productApply the product rule to the third term.✓ Proved
  4. \[ = \left(1 - 5 x\right) \ln{\left(5 x - 1 \right)} + \left(- \frac{5 x^{2}}{2} + x - \frac{1}{10}\right) \frac{d}{d x} \ln{\left(5 x - 1 \right)} - \frac{d}{d x} \frac{x}{2} + \frac{d}{d x} \frac{5 x^{2}}{4} \]
    derivativeDifferentiate the polynomial part of the product.✓ Proved
  5. \[ = \left(1 - 5 x\right) \ln{\left(5 x - 1 \right)} - \frac{d}{d x} \frac{x}{2} + \frac{d}{d x} \frac{5 x^{2}}{4} + \frac{\left(- \frac{5 x^{2}}{2} + x - \frac{1}{10}\right) \frac{d}{d x} \left(5 x - 1\right)}{5 x - 1} \]
    chainApply the chain rule to the logarithm.✓ Proved
  6. \[ = \left(1 - 5 x\right) \ln{\left(5 x - 1 \right)} - \frac{d}{d x} \frac{x}{2} + \frac{d}{d x} \frac{5 x^{2}}{4} + \frac{5 \left(- \frac{5 x^{2}}{2} + x - \frac{1}{10}\right)}{5 x - 1} \]
    derivativeDifferentiate the inner function 5*x - 1.✓ Proved
  7. \[ = \left(1 - 5 x\right) \ln{\left(5 x - 1 \right)} - \frac{d}{d x} \frac{x}{2} + \frac{d}{d x} \frac{5 x^{2}}{4} + \frac{- \frac{25 x^{2}}{2} + 5 x - \frac{1}{2}}{5 x - 1} \]
    algebraMultiply the numerator by 5.✓ Proved
  8. \[ = \frac{5 x}{2} + \left(1 - 5 x\right) \ln{\left(5 x - 1 \right)} - \frac{1}{2} + \frac{- \frac{25 x^{2}}{2} + 5 x - \frac{1}{2}}{5 x - 1} \]
    derivativeDifferentiate the first two terms.✓ Proved
  9. \[ = \frac{5 x}{2} + \left(1 - 5 x\right) \ln{\left(5 x - 1 \right)} - \frac{1}{2} + \frac{- 25 x^{2} + 10 x - 1}{10 x - 2} \]
    algebra simplifySimplify the fraction by multiplying the numerator and denominator by 2. Distribute the 2 in the denominator.✓ Proved
Answer \( \left(1 - 5 x\right) \ln{\left(5 x - 1 \right)} \)
Top: the graph of f = 5x²/4 - x/2 + (-5x²/2 + x - 1/10)·log(5x - 1). A tangent line slides along it, and its slope is plotted below as it goes, tracing f' = 5x/2 + (1 - 5x)·log(5x - 1) - 1/2 + 5(-5x²/2 + x - 1/10)/(5x - 1).

Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 5*x - 1 = 0
6✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 5*x - 1 = 0
7✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 5*x - 1 = 0
8✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 5*x - 1 = 0
9✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 5*x - 1 = 0
undefined where 10*x - 2 = 0
10✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 10*x - 2 = 0
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
log is undefined for non-positive arguments
answer, a second way✓ Provedsympy 1.14.0SymPy differentiated f directly and got the stated answer

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly applies differentiation rules step-by-step, adhering to the one-change-per-step constraint. The algebraic simplifications in the final steps are valid, and the final result matches the stated answer.
Every verdict on record (6)
  • qwen3.6:27b-mlx: pass 2026-10-19 — The solution correctly applies differentiation rules step-by-step, adhering to the one-change-per-step constraint. The algebraic simplifications in the final steps are valid, and the final result matches the stated answer.
  • gpt-oss:20b: pass 2026-10-19
  • qwen3.6:27b-mlx: pass 2026-10-16 — The solution correctly applies differentiation rules step-by-step, adhering to the one-change-per-step constraint. The algebraic simplifications in the final steps are valid and lead to the correct result.
  • gpt-oss:20b: fail (error) 2026-10-16 — The final expression contains an extra rational term that does not cancel; the derivative is not simplified to (1-5*x)*log(5*x-1).
  • qwen3.6:27b-mlx: pass 2026-10-16 — The solution correctly applies differentiation rules step-by-step. Each step changes only one aspect of the expression, uses valid labels from the vocabulary, and the final simplification is algebraically correct.
  • gpt-oss:20b: pass 2026-10-16

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-10-19 with SymPy 1.14.0.