∫Calc Practice

Derivative of \( \displaystyle x - \left(x + \frac{1}{2}\right) \ln{\left(2 x + 1 \right)} \)

Problem 2.2008 · hard

Differentiate \( \displaystyle f(x) = x - \left(x + \frac{1}{2}\right) \ln{\left(2 x + 1 \right)} \).
  1. \[ \frac{d}{d x} \left(x - \left(x + \frac{1}{2}\right) \ln{\left(2 x + 1 \right)}\right) \]
    derivativeStart with the derivative of the function.✓ Proved
  2. \[ = \frac{d}{d x} x - \frac{d}{d x} \left(x + \frac{1}{2}\right) \ln{\left(2 x + 1 \right)} \]
    sumApply the difference rule.✓ Proved
  3. \[ = - \left(x + \frac{1}{2}\right) \frac{d}{d x} \ln{\left(2 x + 1 \right)} - \ln{\left(2 x + 1 \right)} \frac{d}{d x} \left(x + \frac{1}{2}\right) + \frac{d}{d x} x \]
    productApply the product rule to the second term.✓ Proved
  4. \[ = - \left(x + \frac{1}{2}\right) \frac{d}{d x} \ln{\left(2 x + 1 \right)} - \ln{\left(2 x + 1 \right)} \frac{d}{d x} \frac{1}{2} - \ln{\left(2 x + 1 \right)} \frac{d}{d x} x + \frac{d}{d x} x \]
    sumApply the sum rule to the first part of the product.✓ Proved
  5. \[ = - \left(x + \frac{1}{2}\right) \frac{d}{d x} \ln{\left(2 x + 1 \right)} - \ln{\left(2 x + 1 \right)} \frac{d}{d x} x + \frac{d}{d x} x \]
    constant simplifyThe derivative of the constant 1/2 is 0. Simplify the expression by removing the zero term.✓ Proved
  6. \[ = - \frac{\left(x + \frac{1}{2}\right) \frac{d}{d x} \left(2 x + 1\right)}{2 x + 1} - \ln{\left(2 x + 1 \right)} \frac{d}{d x} x + \frac{d}{d x} x \]
    chainApply the chain rule to the logarithm.✓ Proved
  7. \[ = - \frac{2 \left(x + \frac{1}{2}\right)}{2 x + 1} - \ln{\left(2 x + 1 \right)} \frac{d}{d x} x + \frac{d}{d x} x \]
    derivativeDifferentiate the inner function 2x + 1.✓ Proved
  8. \[ = - \frac{2 \left(x + \frac{1}{2}\right)}{2 x + 1} - \ln{\left(2 x + 1 \right)} + 1 \]
    derivativeEvaluate the derivatives of the basic terms.✓ Proved
  9. \[ = - \ln{\left(2 x + 1 \right)} \]
    algebra algebra simplify simplifyDistribute the negative sign. Distribute the 2 in the numerator. Simplify the fraction. Combine the constant terms.✓ Proved
Answer \( - \ln{\left(2 x + 1 \right)} \)

Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
6✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
7✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
8✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
9✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
10✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 2*x + 1 = 0
11✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
12✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
13✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
log is undefined for non-positive arguments
answer, a second way✓ Provedsympy 1.14.0SymPy differentiated f directly and got the stated answer

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly applies differentiation rules and algebraic simplifications in single-step increments. All labels are appropriate for the operations performed.
Every verdict on record (4)
  • gpt-oss:20b: pass 2026-10-10
  • qwen3.6:27b-mlx: pass 2026-10-10 — The solution correctly applies differentiation rules and algebraic simplifications in single-step increments. All labels are appropriate for the operations performed.
  • gpt-oss:20b: fail (error) 2026-10-10 — Step 9 applies the derivative rule to two separate terms in a single step, violating the one‑rule‑per‑step rule.
  • qwen3.6:27b-mlx: pass 2026-10-10 — The solution correctly applies differentiation rules step-by-step, adhering to the one-change-per-step constraint. The labels used are appropriate for the operations performed.

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-10-10 with SymPy 1.14.0.