Derivative of \( \displaystyle - 3 x + \left(3 x + 3\right) \ln{\left(x + 1 \right)} \)
Problem 2.2001 · hard Beautiful
Differentiate \( \displaystyle f(x) = - 3 x + \left(3 x + 3\right) \ln{\left(x + 1 \right)} \).
- \[ \frac{d}{d x} \left(- 3 x + \left(3 x + 3\right) \ln{\left(x + 1 \right)}\right) \]derivativeStart with the derivative of the function.✓ Proved
- \[ = \frac{d}{d x} \left(- 3 x\right) + \frac{d}{d x} \left(3 x + 3\right) \ln{\left(x + 1 \right)} \]sumApply the sum rule.✓ Proved
- \[ = \frac{d}{d x} \left(- 3 x\right) + \frac{d}{d x} \left(3 x \ln{\left(x + 1 \right)} + 3 \ln{\left(x + 1 \right)}\right) \]algebraDistribute the term.✓ Proved
- \[ = \frac{d}{d x} \left(- 3 x\right) + \frac{d}{d x} 3 x \ln{\left(x + 1 \right)} + \frac{d}{d x} 3 \ln{\left(x + 1 \right)} \]sumApply the sum rule again.✓ Proved
- \[ = \frac{d}{d x} \left(- 3 x\right) + 3 \frac{d}{d x} x \ln{\left(x + 1 \right)} + 3 \frac{d}{d x} \ln{\left(x + 1 \right)} \]constant-multipleFactor out the constant 3.✓ Proved
- \[ = 3 x \frac{d}{d x} \ln{\left(x + 1 \right)} + 3 \ln{\left(x + 1 \right)} \frac{d}{d x} x + \frac{d}{d x} \left(- 3 x\right) + 3 \frac{d}{d x} \ln{\left(x + 1 \right)} \]productApply the product rule to the middle term.✓ Proved
- \[ = 3 x \frac{d}{d x} \ln{\left(x + 1 \right)} + 3 \ln{\left(x + 1 \right)} + \frac{d}{d x} \left(- 3 x\right) + 3 \frac{d}{d x} \ln{\left(x + 1 \right)} \]derivative algebraDifferentiate x. Distribute the 3.✓ Proved
- \[ = \frac{3 x}{x + 1} + 3 \ln{\left(x + 1 \right)} + \frac{d}{d x} \left(- 3 x\right) + \frac{3}{x + 1} \]derivativeDifferentiate log(x + 1).✓ Proved
- \[ = \frac{3 x}{x + 1} + 3 \ln{\left(x + 1 \right)} - 3 + \frac{3}{x + 1} \]derivativeDifferentiate -3*x.✓ Proved
- \[ = 3 \ln{\left(x + 1 \right)} - 3 + \frac{3 x + 3}{x + 1} \]algebra algebraCombine the fractions. Factor out 3 from the numerator.✓ Proved
- \[ = 3 \ln{\left(x + 1 \right)} \]algebra simplifySimplify the fraction. Combine the constants.✓ Proved
Answer \( 3 \ln{\left(x + 1 \right)} \)
✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | line 1 is the problem as stated |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 5 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 6 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 7 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 8 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| 9 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where x + 1 = 0 |
| 10 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where x + 1 = 0 |
| 11 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where x + 1 = 0 |
| 12 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where x + 1 = 0 |
| 13 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where x + 1 = 0 |
| 14 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| answer | ✓ Proved | sympy 1.14.0 | final line against the stated answer: simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| answer, a second way | ✓ Proved | sympy 1.14.0 | SymPy differentiated f directly and got the stated answer |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly applies differentiation rules and algebraic simplifications. Each step changes only one aspect of the expression and uses appropriate labels from the fixed vocabulary.
Every verdict on record (4)
gpt-oss:20b: pass 2026-10-10qwen3.6:27b-mlx: pass 2026-10-10 — The solution correctly applies differentiation rules and algebraic simplifications. Each step changes only one aspect of the expression and uses appropriate labels from the fixed vocabulary.gpt-oss:20b: pass 2026-10-10qwen3.6:27b-mlx: pass 2026-10-10
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
gemma4:26b, checked 2026-10-10 with SymPy 1.14.0.