∫Calc Practice

Double integrals in polar coordinates

Problem 11.39 · easy

Evaluate \( \displaystyle \iint_D x^{2} + y^{2} + 1 \, dA \) over the disk \( \displaystyle x^2 + y^2 \le 9 \) using polar coordinates.
  1. In polar coordinates the disk is 0 ≤ r ≤ R, 0 ≤ θ ≤ 2π, and dA = r dr dθ.
  2. \[ r^{2} \sin^{2}{\left(\theta \right)} + r^{2} \cos^{2}{\left(\theta \right)} + 1 = r^{2} + 1 \]
    The integrand in r and θ.✓ Proved
  3. \[ \int\limits_{0}^{2 \pi}\int\limits_{0}^{3} r \left(r^{2} + 1\right)\, dr\, d\theta = \frac{99 \pi}{2} \]
    Integrate, remembering the extra r.✓ Proved
Answer \( \frac{99 \pi}{2} \)

Lines: 2 proved, 1 not checked. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify

The full receipt
LineStatusChecked byDetail
1Not checked—a sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0the integral done in x and y, numerically, without polar coordinates, agrees

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: fail (error) — Line 1 defines the radius bound as R but fails to specify that R=3 for the given disk x^2 + y^2 <= 9. This omission makes the setup incomplete and logically disconnected from the specific problem statement.
Every verdict on record (6)
  • qwen3.6:27b-mlx: fail (error) 2026-09-28 — Line 1 defines the radius bound as R but fails to specify that R=3 for the given disk x^2 + y^2 <= 9. This omission makes the setup incomplete and logically disconnected from the specific problem statement.
  • gpt-oss:20b: pass 2026-09-28
  • qwen3.6:27b-mlx: pass 2026-09-27 — The solution correctly sets up the polar coordinate transformation, including the Jacobian factor r, and applies the correct bounds for the disk of radius 3. The final result is correct.
  • gpt-oss:20b: pass 2026-09-27
  • qwen3.6:27b-mlx: pass 2026-09-26 — The solution correctly sets up the polar coordinate transformation, including the Jacobian factor r, and applies the correct bounds for the disk of radius 3. The final result is correct.
  • gpt-oss:20b: pass 2026-09-26

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/double_integral_polar, checked 2026-09-28 with SymPy 1.14.0.