∫Calc Practice

Double integrals in polar coordinates

Problem 11.38 · easy

Evaluate \( \displaystyle \iint_D x^{2} + y^{2} \, dA \) over the disk \( \displaystyle x^2 + y^2 \le 1 \) using polar coordinates.
  1. In polar coordinates the disk is 0 ≤ r ≤ R, 0 ≤ θ ≤ 2π, and dA = r dr dθ.
  2. \[ r^{2} \sin^{2}{\left(\theta \right)} + r^{2} \cos^{2}{\left(\theta \right)} = r^{2} \]
    The integrand in r and θ.✓ Proved
  3. \[ \int\limits_{0}^{2 \pi}\int\limits_{0}^{1} r^{3}\, dr\, d\theta = \frac{\pi}{2} \]
    Integrate, remembering the extra r.✓ Proved
Answer \( \frac{\pi}{2} \)

Lines: 2 proved, 1 not checked. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify

The full receipt
LineStatusChecked byDetail
1Not checked—a sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0the integral done in x and y, numerically, without polar coordinates, agrees

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: fail (style) — [domain objection, downgraded to style] The solution uses an undefined variable 'R' in the bounds for r, whereas the problem specifies the unit disk (R=1). This makes the setup incomplete and technically incorrect as written.
Every verdict on record (6)
  • qwen3.6:27b-mlx: fail (style) 2026-09-28 — [domain objection, downgraded to style] The solution uses an undefined variable 'R' in the bounds for r, whereas the problem specifies the unit disk (R=1). This makes the setup incomplete and technically incorrect as written.
  • gpt-oss:20b: pass 2026-09-28
  • qwen3.6:27b-mlx: fail (style) 2026-09-27 — [domain objection, downgraded to style] Line 1 introduces an undefined variable 'R' for the radius bound, whereas the problem specifies the unit disk (radius 1). This makes the setup inconsistent with the problem statement.
  • gpt-oss:20b: pass 2026-09-27
  • qwen3.6:27b-mlx: fail (style) 2026-09-26 — [domain objection, downgraded to style] The solution uses an undefined variable 'R' in the bounds for r in step 1, instead of the specific radius 1 given in the problem statement. While the subsequent integration limits are correct, the setup is formally incorrect and inconsistent.
  • gpt-oss:20b: pass 2026-09-26

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/double_integral_polar, checked 2026-09-28 with SymPy 1.14.0.