∫Calc Practice

Triple integrals over general regions

Problem 11.285 · medium

Evaluate \( \displaystyle \iiint_E z\, dV \), where \( \displaystyle E = \{(x, y, z) : -1 \le x \le 1,\ 0 \le y \le 2,\ 0 \le z \le 1 - x^{2}\} \).
  1. \[ \int\limits_{0}^{1 - x^{2}} z\, dz = \frac{x^{4}}{2} - x^{2} + \frac{1}{2} \]
    Integrate in z first.✓ Proved
  2. \[ \int\limits_{0}^{2} \frac{\left(1 - x^{2}\right)^{2}}{2}\, dy = x^{4} - 2 x^{2} + 1 \]
    Then in y.✓ Proved
  3. \[ \int\limits_{-1}^{1} \left(1 - x^{2}\right)^{2}\, dx = \frac{16}{15} \]
    Then in x.✓ Proved
Answer \( \frac{16}{15} \)

Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0nested numerical quadrature

Reviewers

  • gpt-oss:20b: fail (error) — The y‑integration step is incorrect: after integrating over z the integrand is (1−x²)²/2, but multiplying by the y‑interval length 2 gives (1−x²)², not (1−x²)²/2. This propagates a factor‑of‑2 error, leading to the wrong final value 16/15 instead of the correct 32/15.
  • qwen3.6:27b-mlx: pass — The solution correctly sets up the iterated integral with the appropriate bounds and order of integration. The intermediate steps and final result are algebraically correct.
Every verdict on record (4)
  • gpt-oss:20b: fail (error) 2026-10-07 — The y‑integration step is incorrect: after integrating over z the integrand is (1−x²)²/2, but multiplying by the y‑interval length 2 gives (1−x²)², not (1−x²)²/2. This propagates a factor‑of‑2 error, leading to the wrong final value 16/15 instead of the correct 32/15.
  • qwen3.6:27b-mlx: pass 2026-10-07 — The solution correctly sets up the iterated integral with the appropriate bounds and order of integration. The intermediate steps and final result are algebraically correct.
  • gpt-oss:20b: pass 2026-10-07
  • qwen3.6:27b-mlx: pass 2026-10-07 — The solution correctly sets up the iterated integral with the appropriate bounds and order of integration. The algebraic steps and final result are correct.

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/triple_integral_region, checked 2026-10-07 with SymPy 1.14.0.