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Lagrange multipliers

Problem 10.196 · medium Video

Use Lagrange multipliers to find the maximum and minimum of \( \displaystyle f(x, y) = 2 x + 3 y \) on the circle \( \displaystyle x^2 + y^2 = 1 \).
  1. Solve ∇f = λ∇g with g(x, y) = x² + y² − r² = 0.
    Reviewed
  2. \[ \left[\begin{matrix}\frac{\partial}{\partial x} \left(2 x + 3 y\right)\\\frac{\partial}{\partial y} \left(2 x + 3 y\right)\end{matrix}\right] = \left[\begin{matrix}2\\3\end{matrix}\right] \]
    ∇f.✓ Proved
  3. \[ \left[\begin{matrix}\frac{\partial}{\partial x} \left(x^{2} + y^{2} - 1\right)\\\frac{\partial}{\partial y} \left(x^{2} + y^{2} - 1\right)\end{matrix}\right] = \left[\begin{matrix}2 x\\2 y\end{matrix}\right] \]
    ∇g.✓ Proved
  4. So x = 2/(2λ), y = 3/(2λ); substituting into the constraint gives λ = ±√(13)/(2√1).
    Reviewed
  5. \[ \sqrt{13} \]
    The maximum; the minimum is its negative.Reviewed
Answer \( \max = \sqrt{13},\ \min = - \sqrt{13} \)
A contour map of f(x, y) = 2x + 3y: each curve joins points where f has the same value. The constraint circle of radius 1 is drawn over it; the largest and smallest values on the circle are where a level line just touches it.

Lines: 2 proved, 3 reviewed. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify

The full receipt
LineStatusChecked byDetail
1Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
5Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxboth sides are the same expression: the line states a value, and the working that produced it is not on the line
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0f around 100,000 points of the circle tops out at the same value

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly applies the method of Lagrange multipliers, derives the correct critical values, and identifies the maximum and minimum values of the function on the given constraint.
Every verdict on record (6)
  • qwen3.6:27b-mlx: pass 2026-09-28 — The solution correctly applies the method of Lagrange multipliers, derives the correct critical values, and identifies the maximum and minimum values of the function on the given constraint.
  • gpt-oss:20b: pass 2026-09-28
  • qwen3.6:27b-mlx: pass 2026-09-27 — The solution correctly applies the method of Lagrange multipliers, derives the critical points, and identifies the correct maximum and minimum values.
  • gpt-oss:20b: pass 2026-09-27
  • qwen3.6:27b-mlx: fail (error) 2026-09-27 — The solution fails to explicitly solve for x and y or substitute them back into f(x,y) to derive the final value sqrt(13). It jumps from the value of lambda to the final answer without showing the critical step of evaluating the function at the critical points.
  • gpt-oss:20b: pass 2026-09-27

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/lagrange_multipliers, checked 2026-10-13 with SymPy 1.14.0.