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Lagrange multipliers

Problem 10.195 · medium Video

Use Lagrange multipliers to find the maximum and minimum of \( \displaystyle f(x, y) = 2 x + 3 y \) on the circle \( \displaystyle x^2 + y^2 = 25 \).
  1. Solve ∇f = λ∇g with g(x, y) = x² + y² − r² = 0.
    Reviewed
  2. \[ \left[\begin{matrix}\frac{\partial}{\partial x} \left(2 x + 3 y\right)\\\frac{\partial}{\partial y} \left(2 x + 3 y\right)\end{matrix}\right] = \left[\begin{matrix}2\\3\end{matrix}\right] \]
    ∇f.✓ Proved
  3. \[ \left[\begin{matrix}\frac{\partial}{\partial x} \left(x^{2} + y^{2} - 25\right)\\\frac{\partial}{\partial y} \left(x^{2} + y^{2} - 25\right)\end{matrix}\right] = \left[\begin{matrix}2 x\\2 y\end{matrix}\right] \]
    ∇g.✓ Proved
  4. So x = 2/(2λ), y = 3/(2λ); substituting into the constraint gives λ = ±√(13)/(2√25).
    Reviewed
  5. \[ 5 \sqrt{13} \]
    The maximum; the minimum is its negative.Reviewed
Answer \( \max = 5 \sqrt{13},\ \min = - 5 \sqrt{13} \)
A contour map of f(x, y) = 2x + 3y: each curve joins points where f has the same value. The constraint circle of radius 5 is drawn over it; the largest and smallest values on the circle are where a level line just touches it.

✓ Nihil obstat Lines: 2 proved, 3 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify

The full receipt
LineStatusChecked byDetail
1Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
5Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxboth sides are the same expression: the line states a value, and the working that produced it is not on the line
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0f around 100,000 points of the circle tops out at the same value

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly sets up the Lagrange multiplier equations, solves for the critical points, and identifies the maximum and minimum values. The logic is sound and the final answer is correct.
Every verdict on record (6)
  • qwen3.6:27b-mlx: pass 2026-09-28 — The solution correctly sets up the Lagrange multiplier equations, solves for the critical points, and identifies the maximum and minimum values. The logic is sound and the final answer is correct.
  • gpt-oss:20b: pass 2026-09-28
  • qwen3.6:27b-mlx: pass 2026-09-27 — The solution correctly sets up the Lagrange multiplier equations, solves for the critical points, and identifies the correct maximum and minimum values.
  • gpt-oss:20b: pass 2026-09-27
  • qwen3.6:27b-mlx: pass 2026-09-27 — The solution correctly applies the method of Lagrange multipliers, derives the critical points, and identifies the correct maximum and minimum values.
  • gpt-oss:20b: pass 2026-09-27

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/lagrange_multipliers, checked 2026-10-13 with SymPy 1.14.0.