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Home›Calculus 1›Limits at infinity›Problem 1.369

Limit of \( \displaystyle \frac{3 \left(3 x + 1\right)^{2} + 1}{\left(3 x + 1\right)^{2} - 4} \) as \( x \to \infty \)

Problem 1.369 · hard

Evaluate \( \displaystyle \lim_{x \to \infty} \frac{3 \left(3 x + 1\right)^{2} + 1}{\left(3 x + 1\right)^{2} - 4} \).
  1. \[ \lim_{x \to \infty}\left(\frac{3 \left(3 x + 1\right)^{2} + 1}{\left(3 x + 1\right)^{2} - 4}\right) \]
    limitEvaluate the limit as x approaches infinity.✓ Proved
  2. \[ = \lim_{x \to \infty}\left(\frac{27 x^{2} + 18 x + 4}{9 x^{2} + 6 x - 3}\right) \]
    algebra simplifyExpand the squared terms. Simplify the numerator and denominator.✓ Proved
  3. \[ = \lim_{x \to \infty}\left(\frac{27 + \frac{18}{x} + \frac{4}{x^{2}}}{9 + \frac{6}{x} - \frac{3}{x^{2}}}\right) \]
    algebra simplifyDivide numerator and denominator by x**2. Simplify the terms inside the limit.✓ Proved
  4. \[ = \lim_{x \to \infty}\left(27 + \frac{18}{x} + \frac{4}{x^{2}}\right) \left(\lim_{x \to \infty}\left(9 + \frac{6}{x} - \frac{3}{x^{2}}\right)\right)^{-1} \]
    limit-lawApply the quotient rule for limits.✓ Proved
  5. \[ = \frac{\lim_{x \to \infty}\left(27 + \frac{18}{x} + \frac{4}{x^{2}}\right)}{9} \]
    limit-lawEvaluate the limit of the denominator.✓ Proved
  6. \[ = 3 \]
    limit simplifyEvaluate the limit of the numerator. Final simplification.✓ Proved
Answer \( 3 \)

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where (3*x + 1)**2 - 4 = 0
undefined where 9*x**2 + 6*x - 3 = 0
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where 9*x**2 + 6*x - 3 = 0
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where 9*x**2 + 6*x - 3 = 0
undefined where x = 0
undefined where 9 + 6/x - 3/x**2 = 0
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x = 0
undefined where 9 + 6/x - 3/x**2 = 0
6✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x = 0
undefined where 9 + 6/x - 3/x**2 = 0
undefined where Limit(9 + 6/x - 3/x**2, x, oo, dir='-') = 0
7✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x = 0
undefined where Limit(9 + 6/x - 3/x**2, x, oo, dir='-') = 0
8✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x = 0
9✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
answer, a second way✓ Provedsympy 1.14.0SymPy took the limit from both sides and got the stated value

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly applies algebraic manipulation and limit laws to evaluate the limit at infinity. Each step changes only one aspect of the expression and uses valid labels from the fixed vocabulary.
Every verdict on record (4)
  • gpt-oss:20b: pass 2026-10-07
  • qwen3.6:27b-mlx: pass 2026-10-07 — The solution correctly applies algebraic manipulation and limit laws to evaluate the limit at infinity. Each step changes only one aspect of the expression and uses valid labels from the fixed vocabulary.
  • qwen3.6:27b-mlx: pass 2026-10-07 — The solution correctly applies algebraic manipulation and limit laws to evaluate the limit at infinity. Each step changes only one aspect of the expression and uses valid labels from the fixed vocabulary.
  • gpt-oss:20b: pass 2026-10-07

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-10-07 with SymPy 1.14.0.