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Home›Calculus 1›Limits at infinity›Problem 1.368

Limit of \( \displaystyle \frac{3 \left(2 x + 1\right)^{2} + 1}{\left(2 x + 1\right)^{2} - 4} \) as \( x \to \infty \)

Problem 1.368 · hard

Evaluate \( \displaystyle \lim_{x \to \infty} \frac{3 \left(2 x + 1\right)^{2} + 1}{\left(2 x + 1\right)^{2} - 4} \).
  1. \[ \lim_{x \to \infty}\left(\frac{3 \left(2 x + 1\right)^{2} + 1}{\left(2 x + 1\right)^{2} - 4}\right) \]
    limitStart with the original limit.✓ Proved
  2. \[ = \lim_{x \to \infty}\left(\frac{12 x^{2} + 12 x + 4}{4 x^{2} + 4 x - 3}\right) \]
    simplify simplifyExpand the squared terms. Distribute the 3 and combine like terms.✓ Proved
  3. \[ = \lim_{x \to \infty}\left(\frac{12 + \frac{12}{x} + \frac{4}{x^{2}}}{4 + \frac{4}{x} - \frac{3}{x^{2}}}\right) \]
    algebra simplifyDivide numerator and denominator by x**2. Simplify the fractions inside the limit.✓ Proved
  4. \[ = \lim_{x \to \infty}\left(12 + \frac{12}{x} + \frac{4}{x^{2}}\right) \left(\lim_{x \to \infty}\left(4 + \frac{4}{x} - \frac{3}{x^{2}}\right)\right)^{-1} \]
    limit-lawApply the quotient rule for limits.✓ Proved
  5. \[ = \frac{\lim_{x \to \infty}\left(12 + \frac{12}{x} + \frac{4}{x^{2}}\right)}{4} \]
    limitEvaluate the limit of the denominator.✓ Proved
  6. \[ = 3 \]
    limit simplify simplifyEvaluate the limit of the numerator. Simplify the resulting fraction. Final result.✓ Proved
Answer \( 3 \)

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where (2*x + 1)**2 - 4 = 0
undefined where 4*x**2 + 4*x - 3 = 0
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where 4*x**2 + 4*x - 3 = 0
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where 4*x**2 + 4*x - 3 = 0
undefined where x = 0
undefined where 4 + 4/x - 3/x**2 = 0
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x = 0
undefined where 4 + 4/x - 3/x**2 = 0
6✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x = 0
undefined where 4 + 4/x - 3/x**2 = 0
undefined where Limit(4 + 4/x - 3/x**2, x, oo, dir='-') = 0
7✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x = 0
undefined where Limit(4 + 4/x - 3/x**2, x, oo, dir='-') = 0
8✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x = 0
9✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
10✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
answer, a second way✓ Provedsympy 1.14.0SymPy took the limit from both sides and got the stated value

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly applies algebraic simplification and limit laws. Each step changes only one aspect of the expression and uses valid labels from the fixed vocabulary.
Every verdict on record (4)
  • gpt-oss:20b: pass 2026-10-07
  • qwen3.6:27b-mlx: pass 2026-10-07 — The solution correctly applies algebraic simplification and limit laws. Each step changes only one aspect of the expression and uses valid labels from the fixed vocabulary.
  • qwen3.6:27b-mlx: pass 2026-10-07 — The solution correctly expands, simplifies, and applies limit laws to evaluate the limit at infinity. Each step applies a single rule and is correctly labeled.
  • gpt-oss:20b: pass 2026-10-07

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-10-07 with SymPy 1.14.0.