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Home›Calculus 1›Limits at infinity›Problem 1.138

Limit of \( \displaystyle \frac{3 \left(x - 1\right)^{2} + 1}{\left(x - 1\right)^{2} - 4} \) as \( x \to \infty \)

Problem 1.138 · medium

Evaluate \( \displaystyle \lim_{x \to \infty} \frac{3 \left(x - 1\right)^{2} + 1}{\left(x - 1\right)^{2} - 4} \).
  1. \[ \lim_{x \to \infty}\left(\frac{3 \left(x - 1\right)^{2} + 1}{\left(x - 1\right)^{2} - 4}\right) \]
    limitStart with the limit of the given function.✓ Proved
  2. \[ = \lim_{x \to \infty}\left(\frac{3 x^{2} - 6 x + 4}{x^{2} - 2 x - 3}\right) \]
    algebra simplify simplifyExpand the squared terms. Distribute the 3. Combine constant terms in the numerator and denominator.✓ Proved
  3. \[ = \lim_{x \to \infty}\left(\frac{\frac{d}{d x} \left(3 x^{2} - 6 x + 4\right)}{\frac{d}{d x} \left(x^{2} - 2 x - 3\right)}\right) \]
    lhopitalApply L'Hopital's rule since the limit is of the form infinity/infinity.✓ Proved
  4. \[ = \lim_{x \to \infty}\left(\frac{6 x - 6}{2 x - 2}\right) \]
    simplify factorCompute the derivatives. Factor out common terms.✓ Proved
  5. \[ = \lim_{x \to \infty} 3 \]
    simplifyCancel the common factor (x-1).✓ Proved
  6. \[ = 3 \]
    limitEvaluate the final limit.✓ Proved
Answer \( 3 \)

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where (x - 1)**2 - 4 = 0
undefined where x**2 - 2*x - 3 = 0
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x**2 - 2*x - 3 = 0
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x**2 - 2*x - 3 = 0
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x**2 - 2*x - 3 = 0
undefined where Derivative(x**2 - 2*x - 3, x) = 0
6✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where Derivative(x**2 - 2*x - 3, x) = 0
undefined where 2*x - 2 = 0
7✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where 2*x - 2 = 0
8✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where 2*x - 2 = 0
9✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
answer, a second way✓ Provedsympy 1.14.0SymPy took the limit from both sides and got the stated value

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-10-04
  • gpt-oss:20b: pass 2026-10-04
  • qwen3.6:27b-mlx: pass 2026-10-04 — The solution correctly applies algebraic simplification, L'Hopital's rule, and limit evaluation. Each step changes only one aspect of the expression and uses valid labels from the fixed vocabulary.
  • gpt-oss:20b: pass 2026-10-04

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-10-04 with SymPy 1.14.0.