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Home›Calculus 1›Limits at infinity›Problem 1.132

Limit of \( \displaystyle \frac{- x + \left(x + 1\right)^{3} - 1}{2 \left(x + 1\right)^{3} + 5} \) as \( x \to \infty \)

Problem 1.132 · medium

Evaluate \( \displaystyle \lim_{x \to \infty} \frac{- x + \left(x + 1\right)^{3} - 1}{2 \left(x + 1\right)^{3} + 5} \).
  1. \[ \lim_{x \to \infty}\left(\frac{- x + \left(x + 1\right)^{3} - 1}{2 \left(x + 1\right)^{3} + 5}\right) \]
    limitEvaluate the limit of the given function as x approaches infinity.✓ Proved
  2. \[ = \lim_{x \to \infty}\left(\frac{x^{3} + 3 x^{2} + 2 x}{2 x^{3} + 6 x^{2} + 6 x + 7}\right) \]
    simplifyExpand and simplify the numerator and denominator.✓ Proved
  3. \[ = \lim_{x \to \infty}\left(\frac{x^{3}}{2 x^{3} + 6 x^{2} + 6 x + 7} + \frac{3 x^{2}}{2 x^{3} + 6 x^{2} + 6 x + 7} + \frac{2 x}{2 x^{3} + 6 x^{2} + 6 x + 7}\right) \]
    limit-lawSplit the fraction into three separate parts using the limit law for sums.✓ Proved
  4. \[ = \lim_{x \to \infty}\left(\frac{2 x}{2 x^{3} + 6 x^{2} + 6 x + 7}\right) + \lim_{x \to \infty}\left(\frac{3 x^{2}}{2 x^{3} + 6 x^{2} + 6 x + 7}\right) + \lim_{x \to \infty}\left(\frac{x^{3}}{2 x^{3} + 6 x^{2} + 6 x + 7}\right) \]
    limit-lawApply the limit law to each term individually.✓ Proved
  5. \[ = \lim_{x \to \infty} \frac{1}{2 + \frac{6}{x} + \frac{6}{x^{2}} + \frac{7}{x^{3}}} + \lim_{x \to \infty}\left(\frac{3}{2 x + 6 + \frac{6}{x} + \frac{7}{x^{2}}}\right) + \lim_{x \to \infty}\left(\frac{2}{2 x^{2} + 6 x + 6 + \frac{7}{x}}\right) \]
    algebraDivide the numerator and denominator of each term by the highest power of x in the denominator.✓ Proved
  6. \[ = \lim_{x \to \infty} \frac{1}{2 + \frac{6}{x} + \frac{6}{x^{2}} + \frac{7}{x^{3}}} \]
    limit-lawEvaluate the limits of the terms that approach zero.✓ Proved
  7. \[ = \lim_{x \to \infty} \frac{1}{2} \]
    infinityEvaluate the limit as terms with 1/x approach zero.✓ Proved
  8. \[ = \frac{1}{2} \]
    limitFinal evaluation of the limit.✓ Proved
Answer \( \frac{1}{2} \)

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where 2*(x + 1)**3 + 5 = 0
undefined where 2*x**3 + 6*x**2 + 6*x + 7 = 0
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where 2*x**3 + 6*x**2 + 6*x + 7 = 0
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where 2*x**3 + 6*x**2 + 6*x + 7 = 0
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where 2*x**3 + 6*x**2 + 6*x + 7 = 0
undefined where 2*x + 6 + 6/x + 7/x**2 = 0
undefined where 2*x**2 + 6*x + 6 + 7/x = 0
undefined where x = 0
undefined where 2 + 6/x + 6/x**2 + 7/x**3 = 0
6✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where 2*x + 6 + 6/x + 7/x**2 = 0
undefined where 2*x**2 + 6*x + 6 + 7/x = 0
undefined where x = 0
undefined where 2 + 6/x + 6/x**2 + 7/x**3 = 0
7✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x = 0
undefined where 2 + 6/x + 6/x**2 + 7/x**3 = 0
8✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
answer, a second way✓ Provedsympy 1.14.0SymPy took the limit from both sides and got the stated value

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly expands, splits, and evaluates the limit using standard algebraic manipulations and limit laws. Each step applies a single rule appropriately.
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-10-03 — The solution correctly expands, splits, and evaluates the limit using standard algebraic manipulations and limit laws. Each step applies a single rule appropriately.
  • gpt-oss:20b: pass 2026-10-03
  • qwen3.6:27b-mlx: pass 2026-10-03 — The solution correctly applies limit laws and algebraic simplification to evaluate the limit at infinity. Each step changes only one aspect of the expression and uses valid labels from the fixed vocabulary.
  • gpt-oss:20b: pass 2026-10-03

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-10-03 with SymPy 1.14.0.