Projectiles: time of flight, maximum height and range from a launch speed, angle and height. 60 problems with worked solutions; in 60 of them every
equation is proved by a computer algebra system.
2 worked problems
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A projectile is fired from \( \displaystyle 0 \) ft above the ground at \( \displaystyle 96 \) ft/s, \( \displaystyle 30^\circ \) above the horizontal. Taking \( \displaystyle g = 32 \) ft/s², find the maximum height, the time of flight and the horizontal range.
x(t) = v₀cos θ · t and y(t) = 0 + v₀sin θ · t − ½gt².
Answer \( H = 36 \approx 36.00,\ T = 3 \approx 3.000,\ \text{range} = 144 \sqrt{3} \approx 249.42 \)
✓ Nihil obstat Lines: 4 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt ·
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A projectile is fired from \( \displaystyle 2 \) m above the ground at \( \displaystyle 20 \) m/s, \( \displaystyle 30^\circ \) above the horizontal. Taking \( \displaystyle g = 9.8 \) m/s², find the maximum height, the time of flight and the horizontal range.
x(t) = v₀cos θ · t and y(t) = 2 + v₀sin θ · t − ½gt².
✓ Nihil obstat Lines: 4 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. The full receipt ·
How we verify