∫Calc Practice

Dot product and angles

Problem 9.91 · easy

Let \( \displaystyle \mathbf{u} = \langle 1, -2, -4 \rangle \) and \( \displaystyle \mathbf{v} = \langle 5, 2, -3 \rangle \). Find \( \displaystyle \mathbf{u} \cdot \mathbf{v} \) and the angle between them.
  1. \[ \left(-2\right) 2 + 1 \cdot 5 - 4 \left(-3\right) = 13 \]
    Multiply componentwise and add.✓ Proved
  2. \[ \sqrt{21} \]
    |u|.✓ Proved
  3. \[ \sqrt{38} \]
    |v|.✓ Proved
  4. \[ \frac{13 \sqrt{798}}{798} \]
    cos θ = u·v / (|u||v|).✓ Proved
  5. θ = arccos of that.
    Reviewed
Answer \( \mathbf{u}\cdot\mathbf{v} = 13,\quad \theta = \operatorname{acos}{\left(\frac{13 \sqrt{798}}{798} \right)} \approx 62.60^\circ \)

✓ Nihil obstat Lines: 4 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
5Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0the law of cosines on the triangle u, v, u − v gives the same angle

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly computes the dot product and magnitudes, applies the cosine formula accurately, and identifies the angle via arccos.
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-09-26 — The solution correctly computes the dot product and magnitudes, applies the cosine formula accurately, and identifies the angle via arccos.
  • gpt-oss:20b: pass 2026-09-26
  • qwen3.6:27b-mlx: pass 2026-09-26 — The solution correctly computes the dot product and magnitudes, applies the cosine formula accurately, and states the final angle in terms of arccos. The algebraic simplification in line 4 is correct.
  • gpt-oss:20b: pass 2026-09-26

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/dot_product_angle, checked 2026-09-26 with SymPy 1.14.0.