∫Calc Practice

Equations of spheres

Problem 9.844 · easy

Find the equation of the sphere with center \( \displaystyle (5, 1, 3) \) and radius \( \displaystyle 3 \), in standard form.
  1. A sphere is every point at distance r from the center: (x − h)² + (y − k)² + (z − l)² = r².
  2. \[ \left. \left(x - 5\right)^{2} + \left(y - 1\right)^{2} + \left(z - 3\right)^{2} \right|_{\substack{ x=8\\ y=1\\ z=3 }} = 9 \]
    A point at distance r along the x-direction is on it.✓ Proved
Answer \( \left(x - 5\right)^{2} + \left(y - 1\right)^{2} + \left(z - 3\right)^{2} = 9 \)

Lines: 1 proved, 1 not checked. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify

The full receipt
LineStatusChecked byDetail
1Not checked—a sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0points at the claimed radius from the claimed center satisfy the equation

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: fail (misleading) — The solution provides the correct final answer but includes a confusing and irrelevant verification step (Line 2) that checks a specific point rather than deriving the equation. This does not constitute a valid derivation and may mislead students about how to construct the equation from the given parameters.
Every verdict on record (6)
  • qwen3.6:27b-mlx: fail (misleading) 2026-10-20 — The solution provides the correct final answer but includes a confusing and irrelevant verification step (Line 2) that checks a specific point rather than deriving the equation. This does not constitute a valid derivation and may mislead students about how to construct the equation from the given parameters.
  • gpt-oss:20b: pass 2026-10-20
  • qwen3.6:27b-mlx: pass 2026-10-19 — The solution correctly identifies the standard equation of a sphere and substitutes the given center and radius. The verification step is algebraically correct and logically sound.
  • gpt-oss:20b: pass 2026-10-19
  • qwen3.6:27b-mlx: pass 2026-10-19 — The solution correctly identifies the standard equation of a sphere and substitutes the given center and radius. The unchecked equation line is a valid verification step (checking a point on the sphere) and does not introduce errors.
  • gpt-oss:20b: pass 2026-10-19

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/sphere_equation, checked 2026-10-20 with SymPy 1.14.0.