Equations of spheres
Problem 9.844 · easy
Find the equation of the sphere with center \( \displaystyle (5, 1, 3) \) and radius \( \displaystyle 3 \), in standard form.
- A sphere is every point at distance r from the center: (x − h)² + (y − k)² + (z − l)² = r².
- \[ \left. \left(x - 5\right)^{2} + \left(y - 1\right)^{2} + \left(z - 3\right)^{2} \right|_{\substack{ x=8\\ y=1\\ z=3 }} = 9 \]A point at distance r along the x-direction is on it.✓ Proved
Answer \( \left(x - 5\right)^{2} + \left(y - 1\right)^{2} + \left(z - 3\right)^{2} = 9 \)
Lines: 1 proved, 1 not checked. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Not checked | — | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | points at the claimed radius from the claimed center satisfy the equation |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: fail (misleading) — The solution provides the correct final answer but includes a confusing and irrelevant verification step (Line 2) that checks a specific point rather than deriving the equation. This does not constitute a valid derivation and may mislead students about how to construct the equation from the given parameters.
Every verdict on record (6)
qwen3.6:27b-mlx: fail (misleading) 2026-10-20 — The solution provides the correct final answer but includes a confusing and irrelevant verification step (Line 2) that checks a specific point rather than deriving the equation. This does not constitute a valid derivation and may mislead students about how to construct the equation from the given parameters.gpt-oss:20b: pass 2026-10-20qwen3.6:27b-mlx: pass 2026-10-19 — The solution correctly identifies the standard equation of a sphere and substitutes the given center and radius. The verification step is algebraically correct and logically sound.gpt-oss:20b: pass 2026-10-19qwen3.6:27b-mlx: pass 2026-10-19 — The solution correctly identifies the standard equation of a sphere and substitutes the given center and radius. The unchecked equation line is a valid verification step (checking a point on the sphere) and does not introduce errors.gpt-oss:20b: pass 2026-10-19
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/sphere_equation, checked 2026-10-20 with SymPy 1.14.0.