Quadric surfaces in standard form
Problem 9.834 · easy
Write \( \displaystyle - 3 x^{2} + 108 y^{2} - 108 z = 0 \) in standard form and identify the surface.
- Divide through by 108 and solve for the variable to the first power.Reviewed
- \[ \frac{- 3 x^{2} + 108 y^{2} - 108 z}{108} = - \frac{x^{2}}{36} + y^{2} - z \]The standard form.✓ Proved
- A hyperbolic paraboloid: z to the first power equals a difference of squares.Reviewed
Answer \( - \frac{x^{2}}{36} + y^{2} - z = 0\ (\text{hyperbolic paraboloid}) \)
✓ Nihil obstat Lines: 1 proved, 2 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 3 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | the surface classified from the signs of its coefficients; the standard form is a multiple of the given equation |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly identifies the surface as a hyperbolic paraboloid and derives the standard form accurately.
Every verdict on record (6)
qwen3.6:27b-mlx: pass 2026-10-20 — The solution correctly identifies the surface as a hyperbolic paraboloid and derives the standard form accurately.gpt-oss:20b: pass 2026-10-20qwen3.6:27b-mlx: pass 2026-10-19 — The solution correctly manipulates the equation into standard form and accurately identifies the surface as a hyperbolic paraboloid based on the resulting structure.gpt-oss:20b: pass 2026-10-19qwen3.6:27b-mlx: pass 2026-10-19 — The solution correctly identifies the surface as a hyperbolic paraboloid and derives the standard form. The reasoning is sound.gpt-oss:20b: pass 2026-10-19
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/quadric_surfaces, checked 2026-10-20 with SymPy 1.14.0.