∫Calc Practice

Quadric surfaces in standard form

Problem 9.732 · easy

Write \( \displaystyle - 3 x^{2} + 75 y^{2} - 75 z = 0 \) in standard form and identify the surface.
  1. Divide through by 75 and solve for the variable to the first power.
    Reviewed
  2. \[ \frac{- 3 x^{2} + 75 y^{2} - 75 z}{75} = - \frac{x^{2}}{25} + y^{2} - z \]
    The standard form.✓ Proved
  3. A hyperbolic paraboloid: z to the first power equals a difference of squares.
    Reviewed
Answer \( - \frac{x^{2}}{25} + y^{2} - z = 0\ (\text{hyperbolic paraboloid}) \)

Lines: 1 proved, 2 reviewed. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify

The full receipt
LineStatusChecked byDetail
1Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0the surface classified from the signs of its coefficients; the standard form is a multiple of the given equation

Reviewers

  • gpt-oss:20b: pass — The first sentence is vague—‘solve for the variable to the first power’ is unnecessary and could confuse a student, but the mathematical steps are correct.
  • qwen3.6:27b-mlx: pass — The solution correctly derives the standard form and accurately identifies the surface as a hyperbolic paraboloid based on the structure of the equation.
Every verdict on record (6)
  • qwen3.6:27b-mlx: pass 2026-10-18 — The solution correctly derives the standard form and accurately identifies the surface as a hyperbolic paraboloid based on the structure of the equation.
  • gpt-oss:20b: pass 2026-10-18 — The first sentence is vague—‘solve for the variable to the first power’ is unnecessary and could confuse a student, but the mathematical steps are correct.
  • qwen3.6:27b-mlx: pass 2026-10-16 — The solution correctly derives the standard form and accurately identifies the surface based on the equation structure.
  • gpt-oss:20b: pass 2026-10-16
  • qwen3.6:27b-mlx: pass 2026-10-15 — The solution correctly identifies the standard form and the surface type. The reasoning is sound and concise.
  • gpt-oss:20b: fail (misleading) 2026-10-15 — The first sentence claims to solve for the variable to the first power, but it only divides by 75; it does not isolate z or otherwise solve for a linear variable. This misleads a student into thinking a further step was performed.

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/quadric_surfaces, checked 2026-10-18 with SymPy 1.14.0.