Planes: distances and angles
Problem 9.628 · easy
Find the distance from \( \displaystyle (0, -2, 4) \) to the plane \( \displaystyle - 3 x + 4 y + 2 z = 0 \).
- Distance = |ax₀ + by₀ + cz₀ − d| / ‖n‖.Reviewed
- \[ \frac{\left|{4 \left(-2\right) + 0 - 3 \cdot 0 + 2 \cdot 4}\right|}{\sqrt{2^{2} + \left(-3\right)^{2} + 4^{2}}} = 0 \]Substitute.✓ Proved
Answer \( 0 \)
✓ Nihil obstat Lines: 1 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | the foot of the perpendicular found numerically, then the distance to it |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly applies the point-to-plane distance formula and computes the result accurately.
Every verdict on record (6)
qwen3.6:27b-mlx: pass 2026-10-17 — The solution correctly applies the point-to-plane distance formula and computes the result accurately.gpt-oss:20b: pass 2026-10-17qwen3.6:27b-mlx: pass 2026-10-15 — The solution correctly applies the point-to-plane distance formula and computes the result accurately.gpt-oss:20b: pass 2026-10-15qwen3.6:27b-mlx: pass 2026-10-14 — The solution correctly applies the point-to-plane distance formula and performs the arithmetic accurately, yielding the correct result of 0.gpt-oss:20b: pass 2026-10-14
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/planes_distance_angle, checked 2026-10-17 with SymPy 1.14.0.