Equations of spheres
Problem 9.625 · easy
Find the equation of the sphere with center \( \displaystyle (3, -4, 1) \) and radius \( \displaystyle 2 \), in standard form.
- A sphere is every point at distance r from the center: (x − h)² + (y − k)² + (z − l)² = r².Reviewed
- \[ \left. \left(x - 3\right)^{2} + \left(y + 4\right)^{2} + \left(z - 1\right)^{2} \right|_{\substack{ x=5\\ y=-4\\ z=1 }} = 4 \]A point at distance r along the x-direction is on it.✓ Proved
Answer \( \left(x - 3\right)^{2} + \left(y + 4\right)^{2} + \left(z - 1\right)^{2} = 4 \)
Lines: 1 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | points at the claimed radius from the claimed center satisfy the equation |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly identifies the standard equation of a sphere and substitutes the given center and radius. The algebraic verification in line 2 is consistent with the stated answer.
Every verdict on record (6)
qwen3.6:27b-mlx: pass 2026-10-17 — The solution correctly identifies the standard equation of a sphere and substitutes the given center and radius. The algebraic verification in line 2 is consistent with the stated answer.gpt-oss:20b: pass 2026-10-17qwen3.6:27b-mlx: fail (error) 2026-10-15 — The solution fails to explicitly state the final equation derived from the standard form formula. It only provides a verification step for a single point, which does not constitute finding the equation as requested.gpt-oss:20b: pass 2026-10-15qwen3.6:27b-mlx: pass 2026-10-14 — The solution correctly identifies the standard equation of a sphere and substitutes the given center and radius. The unchecked equation serves as a valid verification step for a specific point on the sphere.gpt-oss:20b: pass 2026-10-14
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/sphere_equation, checked 2026-10-17 with SymPy 1.14.0.