∫Calc Practice

Dot product and angles

Problem 9.58 · easy

Let \( \displaystyle \mathbf{u} = \langle -4, 2, -3 \rangle \) and \( \displaystyle \mathbf{v} = \langle 5, 4, -2 \rangle \). Find \( \displaystyle \mathbf{u} \cdot \mathbf{v} \) and the angle between them.
  1. \[ \left(-4\right) 5 - 3 \left(-2\right) + 2 \cdot 4 = -6 \]
    Multiply componentwise and add.✓ Proved
  2. \[ \sqrt{29} \]
    |u|.✓ Proved
  3. \[ 3 \sqrt{5} \]
    |v|.✓ Proved
  4. \[ - \frac{2 \sqrt{145}}{145} \]
    cos θ = u·v / (|u||v|).✓ Proved
  5. θ = arccos of that.
Answer \( \mathbf{u}\cdot\mathbf{v} = -6,\quad \theta = \operatorname{acos}{\left(- \frac{2 \sqrt{145}}{145} \right)} \approx 99.56^\circ \)

Lines: 4 proved, 1 not checked. The answer was also checked a second way, without looking at the solution. The explanation has not been reviewed yet.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
5Not checked—a sentence; read, not computed
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0the law of cosines on the triangle u, v, u − v gives the same angle

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/dot_product_angle, checked 2026-09-26 with SymPy 1.14.0.