∫Calc Practice

Calculus of vector-valued functions

Problem 9.492 · medium

Evaluate \( \displaystyle \int_0^{\frac{\pi}{2}} \left\langle t^{2}, 2 t, \cos{\left(t \right)} \right\rangle\, dt \).
  1. Integrate each component separately.
    Reviewed
  2. \[ \left[\begin{matrix}\int\limits_{0}^{\frac{\pi}{2}} t^{2}\, dt\\\int\limits_{0}^{\frac{\pi}{2}} 2 t\, dt\\\int\limits_{0}^{\frac{\pi}{2}} \cos{\left(t \right)}\, dt\end{matrix}\right] = \left[\begin{matrix}\frac{\pi^{3}}{24}\\\frac{\pi^{2}}{4}\\1\end{matrix}\right] \]
    Component by component.✓ Proved
Answer \( \left\langle \frac{\pi^{3}}{24}, \frac{\pi^{2}}{4}, 1 \right\rangle \)

✓ Nihil obstat Lines: 1 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0each component by numerical quadrature

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly applies the definition of the integral of a vector-valued function by integrating each component separately. The bounds and integrands are correct, and the algebraic results are verified.
Every verdict on record (4)
  • gpt-oss:20b: pass 2026-10-11
  • qwen3.6:27b-mlx: pass 2026-10-11 — The solution correctly applies the definition of the integral of a vector-valued function by integrating each component separately. The bounds and integrands are correct, and the algebraic results are verified.
  • qwen3.6:27b-mlx: pass 2026-10-11 — The solution correctly applies the definition of the integral of a vector-valued function by integrating each component separately. The algebraic results for each component are correct.
  • gpt-oss:20b: pass 2026-10-11

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/vector_function_calculus, checked 2026-10-11 with SymPy 1.14.0.