∫Calc Practice

Vectors in the plane

Problem 9.354 · easy

Find the component form of the vector \( \displaystyle \mathbf u \) with \( \displaystyle \|\mathbf u\| = 6 \) at angle \( \displaystyle \theta = \frac{7 \pi}{6} \) from the positive \( \displaystyle x \)-axis.
  1. \[ \left[\begin{matrix}- 3 \sqrt{3}\\-3\end{matrix}\right] \]
    u = ‖u‖⟨cos θ, sin θ⟩.✓ Proved
Answer \( \left\langle - 3 \sqrt{3}, -3 \right\rangle \)

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0floating point

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly applies the formula for converting polar coordinates to component form, and the computed values match the stated answer.
Every verdict on record (4)
  • gpt-oss:20b: pass 2026-10-07
  • qwen3.6:27b-mlx: pass 2026-10-07 — The solution correctly applies the formula for converting polar coordinates to component form, and the computed values match the stated answer.
  • gpt-oss:20b: pass 2026-10-07
  • qwen3.6:27b-mlx: pass 2026-10-07 — The solution correctly applies the formula for converting polar coordinates to component form, yielding the correct vector.

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/vectors_plane, checked 2026-10-07 with SymPy 1.14.0.